A sample of 75 information systems managers had an average hourly income of $40.75 with a standard deviation of $7.00.The value of the margin of error at 95% confidence is
A) 80.83.
B) 7.00.
C) .81.
D) 1.61.

Question

Quizplus · Accepted Answer

The formula for margin of error is:
Margin of Error = z * (standard deviation / square root of sample size)
At 95% confidence, z = 1.96
Plugging in the values given in the problem:
Margin of Error = 1.96 * (7 / square root of 75)
Simplifying the expression:
Margin of Error = 1.61
Therefore, the answer is D.

A Sample of 75 Information Systems Managers Had an Average