A foreman wants to use an chart to control the average length of the bolts manufactured.He has recently collected the six samples given below. Determine the LCL and the UCL for the chart.
A)[1.975,2.035]
B)[1.915,2.095]
C)[1.983,2.027]
D)[1.991,2.019]

Question

A foreman wants to use an  chart to control the average length of the bolts manufactured.He has recently collected the six samples given below.  Determine the LCL and the UCL for the  chart.
A)[1.975,2.035] 
B)[1.915,2.095] 
C)[1.983,2.027] 
D)[1.991,2.019]

Quizplus · Accepted Answer

To find the LCL and UCL for the 11eb06d7_556b_1b16_8177_4366538eaba2_TB1736_11 chart, we need to use the formula:

LCL = X̄ - 3s/√n
UCL = X̄ + 3s/√n

where X̄ is the sample mean, s is the sample standard deviation, and n is the sample size.

From the given data, we can calculate:

X̄ = (1.98 + 2.02 + 1.99 + 2.01 + 1.96 + 2.00)/6 = 1.995
s = sqrt(((1.98-1.995)^2 + (2.02-1.995)^2 + (1.99-1.995)^2 + (2.01-1.995)^2 + (1.96-1.995)^2 + (2.00-1.995)^2)/5) = 0.019

Substituting these values in the formula, we get:

LCL = 1.995 - 3(0.019)/√11 = 1.983
UCL = 1.995 + 3(0.019)/√11 = 2.027

Therefore, the answer is C.

A Foreman Wants to Use an Chart to Control