Find the limit (if it exists). $\lim _ { x \rightarrow \infty } \left( \frac { 32 x - 1 } { 4 x + 4 } \right)$
A) $\frac { 1 } { 4 }$
B) $\frac { 1 } { 32 }$
C)8
D)-8
E)does not exist

Question

Find the limit (if it exists).  $\lim _ { x \rightarrow \infty } \left( \frac { 32 x - 1 } { 4 x + 4 } \right)$ 
A) $\frac { 1 } { 4 }$
B) $\frac { 1 } { 32 }$ 
C)8
D)-8
E)does not exist

Quizplus · Accepted Answer

To find the limit as $x$ approaches infinity, divide every term by the highest power of $x$ in the denominator, which is $x$. This gives $\lim _ { x \rightarrow \infty } \left( \frac { 32 - \frac{1}{x} } { 4 + \frac{4}{x} } \right)$. As $x$ approaches infinity, $\frac{1}{x}$ approaches 0, simplifying the expression to $\frac{32}{4} = 8$.

Find the Limit (If It Exists) lim⁡x→∞(32x−14x+4)\lim _ { x \rightarrow \infty } \left( \frac { 32 x - 1 } { 4 x + 4 } \right)limx→∞​(4x+432x−1​)

Find the Limit (If It Exists) $\lim _ { x \rightarrow \infty } \left( \frac { 32 x - 1 } { 4 x + 4 } \right)$