Find the general form of the equation of the plane with the given characteristics. The plane passes through the point (5,-1,-4)and is parallel to the yz-plane.
A)y = -1
B)z = -4
C)x + y + z = 0
D)y + z = -5
E)x = 5

Question

Quizplus · Accepted Answer

A plane parallel to the yz-plane has a normal vector pointing in the x-direction, meaning its equation will be of the form x = k, where k is a constant. Since it passes through (5,-1,-4), k = 5, making the equation of the plane x = 5.

Find the General Form of the Equation of the Plane