Find the general form of the equation of the plane with the given characteristics.
Passes through $( 3,8,6 )$ and is parallel to the xz-plane

A) $y + 8 = 0$
B) $- 8 y = 0$
C) $y - 8 = 0$
D) $8 y = 0$
E) $y = 0$

Question

Find the general form of the equation of the plane with the given characteristics.  
Passes through $( 3,8,6 )$ and is parallel to the xz-plane
 
A) $y + 8 = 0$
B) $- 8 y = 0$
C) $y - 8 = 0$
D) $8 y = 0$
E) $y = 0$

Quizplus · Accepted Answer

A plane parallel to the xz-plane has a normal vector pointing in the y-direction, meaning its equation can be written as $y = k$, where $k$ is a constant. Since the plane passes through the point $(3,8,6)$, we substitute $y = 8$ to find the equation of the plane, which is $y - 8 = 0$.

Find the General Form of the Equation of the Plane (3,8,6)( 3,8,6 )(3,8,6)

Find the General Form of the Equation of the Plane $( 3,8,6 )$