A point in rectangular coordinates is given.Convert the point to polar coordinates, r 0. $( 0 , - 6 )$
A)Polar coordinates: $\left( - 6 , \frac { 3 \pi } { 2 } \right)$
B)Polar coordinates: $\left( 6 , - \frac { \pi } { 2 } \right)$
C)Polar coordinates: $\left( 6 , \frac { \pi } { 2 } \right)$
D)Polar coordinates: $\left( - 6 , - \frac { \pi } { 2 } \right)$
E)Polar coordinates: $\left( 6 , \frac { 3 \pi } { 2 } \right)$

Question

A point in rectangular coordinates is given.Convert the point to polar coordinates, r > 0.  $( 0 , - 6 )$ 
A)Polar coordinates: $\left( - 6 , \frac { 3 \pi } { 2 } \right)$
B)Polar coordinates: $\left( 6 , - \frac { \pi } { 2 } \right)$
C)Polar coordinates: $\left( 6 , \frac { \pi } { 2 } \right)$
D)Polar coordinates: $\left( - 6 , - \frac { \pi } { 2 } \right)$
E)Polar coordinates: $\left( 6 , \frac { 3 \pi } { 2 } \right)$

Quizplus · Accepted Answer

The polar coordinates of a point $(x, y)$ are given by $(r, \theta)$ where $r = \sqrt{x^2 + y^2}$ and $\theta$ is the angle in radians counter-clockwise from the positive x-axis. For the point $(0, -6)$, $r = \sqrt{0^2 + (-6)^2} = 6$ and $\theta = \frac{3\pi}{2}$ because the point is on the negative y-axis.

A Point in Rectangular Coordinates Is Given (0,−6)( 0 , - 6 )(0,−6)

A Point in Rectangular Coordinates Is Given $( 0 , - 6 )$