The range of a projectile fired at an angle $\theta$ with the horizontal and with an initial velocity of v₀ feet per second is $r = \frac { 1 } { 32 } v _ { 0 } ^ { 2 } \sin 2 \theta$ where r is measured in feet.A golfer strikes a golf ball at 90 feet per second.Ignoring the effects of air resistance, at what angle must the golfer hit the ball so that it travels 150 feet? (Round your answer to the nearest degree.) A)14° B)36° C)18° D)27° E)41°

Question

Quizplus · Accepted Answer

The range of the projectile is given by the formula $r = \frac { 1 } { 32 } v _ { 0 } ^ { 2 } \sin 2 \theta$. Substituting the given values, we get $150 = \frac { 1 } { 32 } (90) ^ { 2 } \sin 2 \theta$. Solving for $\theta$, we get $\theta = 18^\circ$.

The Range of a Projectile Fired at an Angle θ\thetaθ With the Horizontal and with an Initial Velocity of V0

The Range of a Projectile Fired at an Angle $\theta$ With the Horizontal and with an Initial Velocity of V₀