Write the logarithmic equation in exponential form. $\log _ { 7 } \frac { 1 } { 49 } = - 2$
A) $7 ^ { - 2 } = - \frac { 1 } { 49 }$
B) $7 ^ { - 2 } = \frac { 1 } { 49 }$
C) $7 ^ { - 2 } = - 49$
D) $7 ^ { - 2 } = 49$
E) $49 ^ { - 2 } = \frac { 1 } { 7 }$

Question

Write the logarithmic equation in exponential form.  $\log _ { 7 } \frac { 1 } { 49 } = - 2$
A) $7 ^ { - 2 } = - \frac { 1 } { 49 }$
B) $7 ^ { - 2 } = \frac { 1 } { 49 }$
C) $7 ^ { - 2 } = - 49$
D) $7 ^ { - 2 } = 49$
E) $49 ^ { - 2 } = \frac { 1 } { 7 }$

Quizplus · Accepted Answer

The logarithmic equation $\log _ { 7 } \frac { 1 } { 49 } = - 2$ in exponential form is $7 ^ { - 2 } = \frac { 1 } { 49 }$, because $7$ raised to the power of $-2$ equals $\frac{1}{49}$.

Write the Logarithmic Equation in Exponential Form log⁡7149=−2\log _ { 7 } \frac { 1 } { 49 } = - 2log7​491​=−2

Write the Logarithmic Equation in Exponential Form $\log _ { 7 } \frac { 1 } { 49 } = - 2$