Find the zeroes of the functions algebraically.
$f ( x ) = \sqrt { 5 x } - 9$
A) $x = \pm \frac { 9 } { 5 }$
B) $x = \pm \frac { 81 } { 5 }$
C) $x = \frac { 9 } { 5 }$
D) $x = \frac { 81 } { 5 }$
E) no real zeroes

Question

Find the zeroes of the functions algebraically. 
 $f ( x ) = \sqrt { 5 x } - 9$  
A) $x = \pm \frac { 9 } { 5 }$
B) $x = \pm \frac { 81 } { 5 }$
C)  $x = \frac { 9 } { 5 }$
D)  $x = \frac { 81 } { 5 }$
E) no real zeroes

Quizplus · Accepted Answer

To find the zeroes of the function $f(x) = \sqrt{5x} - 9$, we set it equal to zero and solve for $x$: $\sqrt{5x} - 9 = 0$. Adding 9 to both sides gives $\sqrt{5x} = 9$. Squaring both sides to eliminate the square root gives $5x = 81$. Dividing by 5 gives $x = \frac{81}{5}$.

Find the Zeroes of the Functions Algebraically f(x)=5x−9f ( x ) = \sqrt { 5 x } - 9f(x)=5x​−9

Find the Zeroes of the Functions Algebraically $f ( x ) = \sqrt { 5 x } - 9$