Find the zeros of the function algebraically.
$f ( x ) = 9 x ^ { 2 } + 21 x - 18$
A) $x = \frac { 2 } { 3 } , - 3$
B) $x = - \frac { 2 } { 3 } , - 3$
C) $x = \frac { 3 } { 2 } , - 3$
D) $x = \frac { 2 } { 3 } , 3$
E) $x = - \frac { 2 } { 3 } , 3$

Question

Find the zeros of the function algebraically. 
$f ( x ) = 9 x ^ { 2 } + 21 x - 18$  
A)  $x = \frac { 2 } { 3 } , - 3$
B)  $x = - \frac { 2 } { 3 } , - 3$
C)  $x = \frac { 3 } { 2 } , - 3$
D)  $x = \frac { 2 } { 3 } , 3$
E)  $x = - \frac { 2 } { 3 } , 3$

Quizplus · Accepted Answer

To find the zeros of the function, we solve the equation $9x^2 + 21x - 18 = 0$. Factoring the equation, we get $3(3x^2 + 7x - 6) = 0$. Further factoring gives $3(3x - 2)(x + 3) = 0$, leading to the solutions $x = \frac{2}{3}$ and $x = -3$.

Find the Zeros of the Function Algebraically f(x)=9x2+21x−18f ( x ) = 9 x ^ { 2 } + 21 x - 18f(x)=9x2+21x−18

Find the Zeros of the Function Algebraically $f ( x ) = 9 x ^ { 2 } + 21 x - 18$