Find the zeros of the function algebraically.
$f ( x ) = 2 x ^ { 2 } - 9 x - 35$
A) $x = - \frac { 5 } { 2 } , 7$
B) $x = - \frac { 5 } { 2 } , - 7$
C) $x = - \frac { 2 } { 5 } , 7$
D) $x = \frac { 5 } { 2 } , - 7$
E) $x = \frac { 5 } { 2 } , 7$

Question

Find the zeros of the function algebraically.
 $f ( x ) = 2 x ^ { 2 } - 9 x - 35$
A)  $x = - \frac { 5 } { 2 } , 7$
B)  $x = - \frac { 5 } { 2 } , - 7$
C)  $x = - \frac { 2 } { 5 } , 7$
D)  $x = \frac { 5 } { 2 } , - 7$
E)  $x = \frac { 5 } { 2 } , 7$

Quizplus · Accepted Answer

To find the zeros of the function $f(x) = 2x^2 - 9x - 35$, we can use the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 2$, $b = -9$, and $c = -35$. Plugging these values into the formula gives $x = \frac{9 \pm \sqrt{(-9)^2 - 4(2)(-35)}}{2(2)}$, which simplifies to $x = \frac{9 \pm \sqrt{81 + 280}}{4}$ or $x = \frac{9 \pm \sqrt{361}}{4}$. This further simplifies to $x = \frac{9 \pm 19}{4}$, giving the solutions $x = -\frac{5}{2}$ and $x = 7$.

Find the Zeros of the Function Algebraically f(x)=2x2−9x−35f ( x ) = 2 x ^ { 2 } - 9 x - 35f(x)=2x2−9x−35

Find the Zeros of the Function Algebraically $f ( x ) = 2 x ^ { 2 } - 9 x - 35$