Find (f + g)(x).
$\begin{array} { l }
f ( x ) = x ^ { 2 } - 2 x - 1 \
g ( x ) = - 3 x ^ { 2 } + x - 1
\end{array}$

A) $( f + g ) ( x ) = 4 x ^ { 4 } - 3 x ^ { 2 }$
B) $( f + g ) ( x ) = 2 x ^ { 2 } - x + 2$
C) $( f + g ) ( x ) = - 2 x ^ { 4 } - x ^ { 2 } - 2$
D) $( f + g ) ( x ) = 4 x ^ { 2 } - 3 x$
E) $( f + g ) ( x ) = - 2 x ^ { 2 } - x - 2$

Question

Find (f + g)(x).
 $\begin{array} { l } 
f ( x ) = x ^ { 2 } - 2 x - 1 \
g ( x ) = - 3 x ^ { 2 } + x - 1
\end{array}$  
 
A)  $( f + g ) ( x ) = 4 x ^ { 4 } - 3 x ^ { 2 }$
B)  $( f + g ) ( x ) = 2 x ^ { 2 } - x + 2$
C)  $( f + g ) ( x ) = - 2 x ^ { 4 } - x ^ { 2 } - 2$
D)  $( f + g ) ( x ) = 4 x ^ { 2 } - 3 x$
E)  $( f + g ) ( x ) = - 2 x ^ { 2 } - x - 2$

Quizplus · Accepted Answer

To find $(f + g)(x)$, you add the corresponding terms of $f(x)$ and $g(x)$ together: $x^2 - 2x - 1 + (-3x^2 + x - 1) = -2x^2 - x - 2$.

Find (F + G)(x) f(x)=x2−2x−1g(x)=−3x2+x−1\begin{array} { l } f ( x ) = x ^ { 2 } - 2 x - 1 \\g ( x ) = - 3 x ^ { 2 } + x - 1\end{array}f(x)=x2−2x−1g(x)=−3x2+x−1​

Find (F + G)(x) $\begin{array} { l } f ( x ) = x ^ { 2 } - 2 x - 1 \\g ( x ) = - 3 x ^ { 2 } + x - 1\end{array}$