Find the inverse function of g(x) = x² - 3 informally. A) $g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x - 3 }$ B) $g ^ { - 1 } ( x ) = ( x + 3 ) ^ { 2 }$ C) $g ^ { - 1 } ( x ) = x ^ { 2 } + 3$ D) $g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x + 3 }$ E) $g ^ { - 1 } ( x ) = ( x - 3 ) ^ { 2 }$

Question

Quizplus · Accepted Answer

The inverse of the function g(x) = x^2 - 3 is found by solving y = x^2 - 3 for x, which gives x = ±√(y + 3). The principal square root is typically used for the inverse, so g^(-1)(x) = √(x + 3).

Find the Inverse Function of G(x) = X2 - 3 g−1(x)=x−32g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x - 3 }g−1(x)=2x−3​

Find the Inverse Function of G(x) = X² - 3 $g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x - 3 }$