If a 68 Ω, 33 Ω, 100 Ω and 47 Ω resistor are connected in series across a 9 V battery, the current equals .
A)27.6 A
B)22.3 mA
C)36.3 mA
D)327 mA

Name: If a 68 Ω, 33 Ω, 100 Ω and 47 Ω resistor are connected in series across a 9 V battery, the current equals . A)27.6 A B)22.3 mA C)36.3 mA D)327 mA
Brand: Quizplus
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Question

Quizplus · Accepted Answer

The total resistance in series is 68 + 33 + 100 + 47 = 248 Ω. Using Ohm's Law (V = IR), the current I = V/R = 9V / 248Ω = 0.0363 A or 36.3 mA.