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The diagram below illustrates the normal expression of three different groups of genes (A, B, and C) within four different whorls of a developing flower. Normally, whorl 1 produces sepals, whorl 2 produces petals, whorl 3 produces stamens, and whorl 4 produces carpels. Furthermore, expression of class A genes inhibits class C genes, and expression of class C inhibits class A.
-What would be the identity of the four whorls if gene B was ectopically expressed in whorls 1 and 2?
A) sepals, petals, stamens, and carpels
B) petals, petals, petals, petals
C) petals, petals, stamens, stamens
D) stamens, carpels, stamens, carpels
E) sepals, petals, sepals, petals

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The diagram below illustrates the normal expression of three different groups of genes (A, B, and C) within four different whorls of a developing flower. Normally, whorl 1 produces sepals, whorl 2 produces petals, whorl 3 produces stamens, and whorl 4 produces carpels. Furthermore, expression of class A genes inhibits class C genes, and expression of class C inhibits class A. 
-What would be the identity of the four whorls if gene B was ectopically expressed in whorls 1 and 2?
A) sepals, petals, stamens, and carpels 
B) petals, petals, petals, petals 
C) petals, petals, stamens, stamens 
D) stamens, carpels, stamens, carpels 
E) sepals, petals, sepals, petals

Quizplus · Accepted Answer

Gene B is responsible for the development of petals and stamens. Ectopic expression in whorls 1 and 2 would convert sepals to petals and petals to stamens.

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