A 5.0-?F, a 14-?F, and a $21 - \mu F$ capacitor are connected in parallel. How much capacitance would a single capacitor need to have to replace the three capacitors?
A)40 ?F
B) $21 \mu \mathrm { F }$
C)5.0 ?F
D)14 ?F

Question

Quizplus · Accepted Answer

When capacitors are connected in parallel, their capacitances add up. Therefore, the total capacitance is $5.0 \mu F + 14 \mu F + 21 \mu F = 40 \mu F$.

A 50-?F, a 14-?F, and A A 21 21−μF21 - \mu F21−μF

A 50-?F, a 14-?F, and A A 21 $21 - \mu F$