A 4000-N weight is suspended in equilibrium by two cables. Cable 1 applies a horizontal force to the right of the object and has a tension T₁. Cable 2 applies a force upward and to the left at an angle of 37.0 $\degree$ to the negative x axis and has a tension T₂. Find T_2. A) 4000 N B) 6650 N C) 8310 N D) 3340 N

Question

Quizplus · Accepted Answer

To find T₂, resolve the forces into horizontal and vertical components. The vertical component of T₂ must balance the 4000 N weight. Using trigonometry, T₂sin(37°) = 4000 N. Solving for T₂ gives T₂ = 4000 N / sin(37°) ≈ 6650 N.

A 4000-N Weight Is Suspended in Equilibrium by Two Cables °\degree°

A 4000-N Weight Is Suspended in Equilibrium by Two Cables $\degree$