A multiple regression analysis produced the following tables. $$\begin{array} { | c | c | c | c | c | } \hline & \text { Coefficients } & \text { Stardard Error } & t \text { Statistic } & p \text {-value } \ \hline \text { Irtercept } & 1411.876 & 7.621533 & & \ \hline \boldsymbol { x } _ { 1 } & 35.18215 & 96.8433 & & \ \hline \boldsymbol { x } _ { 1 } ^ { 2 } & - 7.721648 & \mathbf { 3 . 0 0 7 9 4 3 } & & \ \hline \end{array}$$ $$\begin{array} { | c | c | c | c | c | } \hline & \mathrm { df } & \mathrm { SS } & \mathrm { MS } & F \ \hline \text { Regression } & 2 & 58567032 & 29283516 & 57.34861 \ \hline \text { Residual } & 21 & 12765573 & 510622.9 & \ \hline \text { Total } & 23 & 71332605 & & \ \hline \end{array}$$ Using $\alpha$= 0.01 to test the null hypothesis H₀: $\beta$₁ = $\beta$₂ = 0, the critical F value is ______. A)8.09 B)6.89 C)6.09 D)5.78 E)5.09

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The Answer of A multiple regression analysis produced the following tables. $$\begin{array} { | c | c | c | c | c | } \hline & \text { Coefficients } & \text { Stardard Error } & t \text { Statistic } & p \text {-value } \ \hline \text { Irtercept } & 1411.876 & 7.621533 & & \ \hline \boldsymbol { x } _ { 1 } & 35.18215 & 96.8433 & & \ \hline \boldsymbol { x } _ { 1 } ^ { 2 } & - 7.721648 & \mathbf { 3 . 0 0 7 9 4 3 } & & \ \hline \end{array}$$ $$\begin{array} { | c | c | c | c | c | } \hline & \mathrm { df } & \mathrm { SS } & \mathrm { MS } & F \ \hline \text { Regression } & 2 & 58567032 & 29283516 & 57.34861 \ \hline \text { Residual } & 21 & 12765573 & 510622.9 & \ \hline \text { Total } & 23 & 71332605 & & \ \hline \end{array}$$ Using $\alpha$= 0.01 to test the null hypothesis H₀: $\beta$₁ = $\beta$₂ = 0, the critical F value is ______. A)8.09 B)6.89 C)6.09 D)5.78 E)5.09

A Multiple Regression Analysis Produced the Following Tables Using α\alphaα

A Multiple Regression Analysis Produced the Following Tables Using $\alpha$