A solution is prepared by dissolving 23.7 g of CaCl₂in 375 g of water. The density of the resulting solution is 1.05 g/mL. The concentration of CaCl₂in this solution is molal. A) 5.70 B) 63.2 C) 1.76 D) 0.214 E) 0.569

Question

Quizplus · Accepted Answer

Molality is calculated as moles of solute per kilogram of solvent. Moles of CaCl2 = 23.7 g / 110.98 g/mol = 0.2137 mol. Mass of water = 375 g = 0.375 kg. Molality = 0.2137 mol / 0.375 kg = 0.569 mol/kg.

A Solution Is Prepared by Dissolving 23