A 25.0 mL sample of an HCl solution is titrated with a 0.139 M NaOH solution. The equivalence point is reached with 15.4 mL of base. The concentration of HCl is M.
A) 0.267
B) 0.0856
C) 0.00214
D) 0.139
E) 11.7

Question

Quizplus · Accepted Answer

First, we can use the equation:

M1V1 = M2V2

Where,
M1 = concentration of HCl
V1 = volume of HCl solution (in liters)
M2 = concentration of NaOH
V2 = volume of NaOH solution (in liters)

We can rearrange the equation to solve for M1:

M1 = (M2V2)/V1

Plugging in the given values:

M1 = (0.139 M)(0.0154 L)/(0.0250 L)

M1 = 0.0856 M

Therefore, the concentration of HCl is 0.0856 M, which corresponds to choice B.

A 250 ML Sample of an HCl Solution Is Titrated with with a 0.139