Calculate the concentration (M) of sodium ions in a solution made by diluting 50.0 mL of a 0.874 M solution of sodium sulfide to a total volume of 250.0 mL.
A) 0.874
B) 0.525
C) 0.175
D) 0.350
E) 4.37

Question

Quizplus · Accepted Answer

Sodium sulfide (Na2S) dissociates into 2 Na+ ions. The initial concentration of Na+ is 2 * 0.874 M = 1.748 M. After dilution, the concentration is (1.748 M * 50.0 mL) / 250.0 mL = 0.350 M.

Calculate the Concentration (M) of Sodium Ions in a Solution