A worker was observed for four cycles in a repetitive task that contains four distinct elements. The observer recorded the following items in seconds, using the continuous method.
$$\begin{array} { | c | c | c | c | c | }
\hline \text { Element } & \text { Cycle 1 } & \text { Cycle 2 } & \text { Cycle3 } & \text { Cycle4 } \
\hline \mathbf { 1 } & 12 & 66 & 111 & 168 \
\hline \mathbf { 2 } & 21 & 75 & 122 & 185 \
\hline \mathbf { 3 } & 37 & 86 & 133 & 200 \
\hline \mathbf { 4 } & 53 & 89 & 146 & 209 \
\hline
\end{array}$$
-Use the information in Table H.1.Assuming that work element 4 receives a performance-rating factor of 1.2 and is performed once per cycle,what is the normal time for this work element?
A) Fewer than 10 seconds
B) Greater than or equal to 10 seconds but fewer than 11 seconds
C) Greater than or equal to 11 seconds but fewer than 12 seconds
D) Greater than or equal to 12 seconds

Question

A worker was observed for four cycles in a repetitive task that contains four distinct elements. The observer recorded the following items in seconds, using the continuous method.
 $$\begin{array} { | c | c | c | c | c | } 
\hline \text { Element } & \text { Cycle 1 } & \text { Cycle 2 } & \text { Cycle3 } & \text { Cycle4 } \
\hline \mathbf { 1 } & 12 & 66 & 111 & 168 \
\hline \mathbf { 2 } & 21 & 75 & 122 & 185 \
\hline \mathbf { 3 } & 37 & 86 & 133 & 200 \
\hline \mathbf { 4 } & 53 & 89 & 146 & 209 \
\hline
\end{array}$$
-Use the information in Table H.1.Assuming that work element 4 receives a performance-rating factor of 1.2 and is performed once per cycle,what is the normal time for this work element?
A) Fewer than 10 seconds
B) Greater than or equal to 10 seconds but fewer than 11 seconds
C) Greater than or equal to 11 seconds but fewer than 12 seconds
D) Greater than or equal to 12 seconds

Quizplus · Accepted Answer

The normal time for a work element is calculated by averaging the observed times and then multiplying by the performance-rating factor. The average time for element 4 is (53 + 89 + 146 + 209) / 4 = 124.25 seconds. Multiplying by the performance-rating factor of 1.2 gives 124.25 * 1.2 = 149.1 seconds, which is greater than 12 seconds.

A Worker Was Observed for Four Cycles in a Repetitive