Determine the pOH of a 0.741 mol L^-1 KOH solution at 25 °C. A) 0.13 B) 13.87 C) 0.17 D) 12.65 E) 11.88

Name: Determine the pOH of a 0.741 mol L -1 KOH solution at 25 °C. A) 0.13 B) 13.87 C) 0.17 D) 12.65 E) 11.88
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Quizplus · Accepted Answer

KOH is a strong base and dissociates completely in solution. Therefore, the concentration of OH⁻ ions is 0.741 mol L⁻¹. The pOH is calculated as -log[OH⁻] = -log(0.741) ≈ 0.13.

Determine the POH of a 0