$\begin{array} { l c } \text { Aendtype } & \text { \#individuals } \\A _ { 1 } A _ { 1 } & 50 \\A _ { 1 } A _ { 2 } & 50 \\A _ { 2 } A _ { 2 } & 400\end{array}$ Use the information in the table above for the next questions) .
-Given the information above, what is the frequency of the A₂allele in this population?

Question

\begin{array} { l c } \text { Aendtype } & \text { \#individuals } \\A _ { 1 } A _ { 1 } & 50 \\A _ { 1 } A _ { 2 } & 50 \\A _ { 2 } A _ { 2 } & 400\end{array}

Use the information in the table above for the next questions) .
-Given the information above, what is the frequency of the A₂allele in this population?

Quizplus · Accepted Answer

To find the frequency of a specific allele, you need to add up the number of individuals that carry that allele and divide it by the total number of alleles in the population.

For the S1U1B0 allele, we can see that it is carried by individuals with the genotypes AS1U1B0/AS1U1B0 and AS1U1B12/S1U1B0. 
The number of individuals with the AS1U1B0/AS1U1B0 genotype is 90, so they carry a total of 2 x 90 = 180 copies of the allele.
The number of individuals with the AS1U1B12/S1U1B0 genotype is 15, so they carry a total of 1 x 15 = 15 copies of the allele.
Therefore, the total number of S1U1B0 alleles in the population is 180 + 15 = 195.
The total number of alleles in the population is 2 x 150 = 300 (since each individual has two alleles).
So the frequency of the S1U1B0 allele is 195/300 = 0.65
Similarly, the frequency of the S1U1B12 allele can be calculated as 105/300 = 0.35
Therefore, the frequency of the AS1U1B12 S1U1B0 allele (since it has both alleles) would be (0.65 + 0.35)/2 = 0.85.

Use the Information in the Table Above for the Next