What volume of oxygen will react with 21 mL of ethanol,assuming the gases are present at the same temperature and pressure? 2 CH₃CH₂OH(g)+ 6 O₂(g)→ 4 CO₂(g)+ 6 H₂O(g) A) 7.0 mL B) 14 mL C) 21 mL D) 42 mL E) 63 mL

Question

Quizplus · Accepted Answer

The balanced chemical equation given is: $$2 C_2H_5OH(g) + 6 O_2(g) \rightarrow 4 CO_2(g) + 6 H_2O(g)$$. According to the stoichiometry of the reaction, 2 moles of ethanol react with 6 moles of oxygen. Therefore, for 21 mL of ethanol, the volume of oxygen required, assuming gases are at the same temperature and pressure (and thus directly proportional to moles), would be $\frac{21 \text{ mL ethanol} \times 6 \text{ moles oxygen}}{2 \text{ moles ethanol}} = 63 \text{ mL oxygen}$.

What Volume of Oxygen Will React with 21 ML of Ethanol,assuming