What is the equilibrium concentration of H₂C₂O₄ in a 0.170 M oxalic acid,H₂C₂O₄,solution? For oxalic acid,K_a1 = 5.6 × 10^-2 and K_a2 = 5.1 × 10^-5. A) 9.6 × 10^-2 M B) 9.8 × 10^-2 M C) 1.7 × 10^-1 M D) 5.1 × 10^-5 M E) 7.4 × 10^-2 M

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Quizplus · Accepted Answer

Given the dissociation constants (Ka values) for oxalic acid and its initial concentration, the equilibrium concentration of oxalic acid can be estimated using the first dissociation constant (Ka1 = 5.6 × 10^-2) because it is significantly larger than the second (Ka2 = 5.1 × 10^-5), indicating that the first dissociation step contributes most to the acid's ionization at equilibrium. The concentration of H2C2O4 that dissociates is small compared to the initial concentration, so the equilibrium concentration of undissociated acid remains close to the initial concentration, but the exact value requires solving the equilibrium expression, which isn't directly provided here. However, the choice closest to reflecting a significant ionization level without depleting the initial concentration is 9.6 × 10^-2 M, assuming partial dissociation into H+ and HC2O4^- ions.

What Is the Equilibrium Concentration of H2C2O4 in a 0

What Is the Equilibrium Concentration of H₂C₂O₄ in a 0