What is the S0 for ozone if the standard entropy change for the reaction below is 411 J/K⋅mol-rxn and S⁰[O₂(g)] = 205 J/K⋅mol. 6 O₃(g)→ 9 O₂(g) A) 364 J/K⋅mol-rxn B) 478 J/K⋅mol-rxn C) 239 J/K⋅mol-rxn D) −117 J/K⋅mol-rxn E) −59 J/K⋅mol-rxn

Question

Quizplus · Accepted Answer

We can use the equation ΔS°rxn = ΣS°(products) - ΣS°(reactants) and the given standard entropies to solve for the standard entropy of ozone, S°(O3).

ΔS°rxn = (9 mol x S°(O2)) - (6 mol x S°(O3))

411 J/K⋅mol = (9 mol x 205 J/K⋅mol) - (6 mol x S°(O3))

S°(O3) = -239 J/K⋅mol

Note that the negative sign indicates that the entropy of ozone is less than that of the standard state.

What Is the S0 for Ozone If the Standard Entropy