The human eye has evolved over time so that its peak wavelength sensitivity is about 0.5 $\mu$m (1 $\mu$m = 10^-6 m).Use Wien's law to calculate the temperature of blackbody radiation to which the eye is most sensitive. A) 14,240 K B) 0.58 K C) 580 K D) 5800 K

Question

Quizplus · Accepted Answer

Wien's law states that the peak wavelength ($\lambda_{max}$) of radiation emitted by a blackbody is inversely proportional to its temperature (T), given by $\lambda_{max} \cdot T = b$, where $b = 2.898 \times 10^{-3} \, \text{m} \cdot \text{K}$. For $\lambda_{max} = 0.5 \, \mu\text{m} = 0.5 \times 10^{-6} \, \text{m}$, solving for T gives $T = \frac{2.898 \times 10^{-3}}{0.5 \times 10^{-6}} \approx 5800 \, \text{K}$.

The Human Eye Has Evolved Over Time So That Its μ\muμ

The Human Eye Has Evolved Over Time So That Its $\mu$