Markovnikov addition of HBr to CH₃CH=CH₂ involves which of the following? A)Initial attack by bromide anion (Br^-). B)Initial attack by bromine radical (Br•). C)Formation of a primary carbocation. D)Formation of a secondary carbocation.

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The addition of HBr to an alkene follows Markovnikov's rule, which states that the hydrogen atom adds to the carbon atom with the fewest hydrogen atoms, and the halogen atom adds to the other carbon atom. In this case, the bromine atom will add to the carbon that is already bonded to one more carbon atom and has less hydrogen. This results in the formation of a secondary carbocation (D) and a bromide ion (Br-), which will then add to the carbocation.

Markovnikov Addition of HBr to CH3CH=CH2 Involves Which of the Following

Markovnikov Addition of HBr to CH₃CH=CH₂ Involves Which of the Following