Given that a sample of size 12 and population standard deviation of 1.8,what would be the margin of error at a 95% level of confidence?
A)±1.018
B)±0.9186
C)±12.22
D)±0.4452

Question

Quizplus · Accepted Answer

The margin of error is calculated using the formula: Margin of Error = Z * (σ/√n), where Z is the Z-score for a 95% confidence level (approximately 1.96), σ is the population standard deviation (1.8), and n is the sample size (12). Calculating this gives: 1.96 * (1.8/√12) ≈ ±1.018.

Given That a Sample of Size 12 and Population Standard