Deck 9: Inverse Functions

ملء الشاشة (f)
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سؤال
Select the correct graph,showing f and g are inverse functions.? f(x)=x3,g(x)=x2+3,x0f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0 ?

A)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
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سؤال
Determine whether the function has an inverse function.If it does,find the inverse function. ?
G(x)= x7
?

A) g1(x)=7xg ^ { - 1 } ( x ) = \frac { 7 } { x }
B)g-1(x)= -7x
C)? g1(x)=x7g ^ { - 1 } ( x ) = - \frac { x } { 7 }
D)g-1(x)= 7x
E)The inverse exists,but none of the above
سؤال
Find the inverse function of f(x)=36x2,0x6f ( x ) = \sqrt { 36 - x ^ { 2 } } , 0 \leq x \leq 6 . ?

A) f1(x)=36x2,0x6f ^ { - 1 } ( x ) = \sqrt { 36 - x ^ { 2 } } , 0 \leq x \leq 6
B) f1(x)=x236,0x6f ^ { - 1 } ( x ) = \sqrt { x ^ { 2 } - 36 } , 0 \leq x \leq 6
C) f1(x)=36x2,0x6f ^ { - 1 } ( x ) = 36 - x ^ { 2 } , 0 \leq x \leq 6
D) f1(x)=36+x2,0x6f ^ { - 1 } ( x ) = \sqrt { 36 + x ^ { 2 } } , 0 \leq x \leq 6
E) f1(x)=36+x2,0x6f ^ { - 1 } ( x ) = 36 + x ^ { 2 } , 0 \leq x \leq 6
سؤال
Select the graph of f and f-1 on the same set of coordinate axes.? f(x)=3xf ( x ) = \frac { 3 } { x } ?

A)  <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes.?  f ( x ) = \frac { 3 } { x }  ?</strong> A)   ? B)   C)?   D)?   E)   <div style=padding-top: 35px>  ?
B)  <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes.?  f ( x ) = \frac { 3 } { x }  ?</strong> A)   ? B)   C)?   D)?   E)   <div style=padding-top: 35px>
C)?  <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes.?  f ( x ) = \frac { 3 } { x }  ?</strong> A)   ? B)   C)?   D)?   E)   <div style=padding-top: 35px>
D)?  <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes.?  f ( x ) = \frac { 3 } { x }  ?</strong> A)   ? B)   C)?   D)?   E)   <div style=padding-top: 35px>
E)  <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes.?  f ( x ) = \frac { 3 } { x }  ?</strong> A)   ? B)   C)?   D)?   E)   <div style=padding-top: 35px>
سؤال
Select the correct graph,showing f and g are inverse functions.? f(x)=9x,g(x)=x9f ( x ) = 9 x , g ( x ) = \frac { x } { 9 } ?

A)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 9 x , g ( x ) = \frac { x } { 9 }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 9 x , g ( x ) = \frac { x } { 9 }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 9 x , g ( x ) = \frac { x } { 9 }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 9 x , g ( x ) = \frac { x } { 9 }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 9 x , g ( x ) = \frac { x } { 9 }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
سؤال
Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.? g(x)=4x5g ( x ) = \frac { 4 - x } { 5 } ? ?

A)  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = \frac { 4 - x } { 5 }  ? ?</strong> A)   The function has an inverse. B)?   The function has an inverse. C)?   The function has an inverse. D)?   The function has an inverse. E)?   The function has an inverse. <div style=padding-top: 35px>  The function has an inverse.
B)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = \frac { 4 - x } { 5 }  ? ?</strong> A)   The function has an inverse. B)?   The function has an inverse. C)?   The function has an inverse. D)?   The function has an inverse. E)?   The function has an inverse. <div style=padding-top: 35px>  The function has an inverse.
C)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = \frac { 4 - x } { 5 }  ? ?</strong> A)   The function has an inverse. B)?   The function has an inverse. C)?   The function has an inverse. D)?   The function has an inverse. E)?   The function has an inverse. <div style=padding-top: 35px>  The function has an inverse.
D)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = \frac { 4 - x } { 5 }  ? ?</strong> A)   The function has an inverse. B)?   The function has an inverse. C)?   The function has an inverse. D)?   The function has an inverse. E)?   The function has an inverse. <div style=padding-top: 35px>  The function has an inverse.
E)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = \frac { 4 - x } { 5 }  ? ?</strong> A)   The function has an inverse. B)?   The function has an inverse. C)?   The function has an inverse. D)?   The function has an inverse. E)?   The function has an inverse. <div style=padding-top: 35px>  The function has an inverse.
سؤال
Does the function have an inverse function?​ <strong>Does the function have an inverse function?​   ​</strong> A)No B)Yes <div style=padding-top: 35px>

A)No
B)Yes
سؤال
Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.? g(x)=2x6x2g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } } ? ?

A)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } }  ? ?</strong> A)?   The function does not have inverse. B)?   The function does not have inverse. C)?   The function does not have inverse. D)?   The function does not have inverse. E)?   The function does not have inverse. <div style=padding-top: 35px>  The function does not have inverse.
B)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } }  ? ?</strong> A)?   The function does not have inverse. B)?   The function does not have inverse. C)?   The function does not have inverse. D)?   The function does not have inverse. E)?   The function does not have inverse. <div style=padding-top: 35px>  The function does not have inverse.
C)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } }  ? ?</strong> A)?   The function does not have inverse. B)?   The function does not have inverse. C)?   The function does not have inverse. D)?   The function does not have inverse. E)?   The function does not have inverse. <div style=padding-top: 35px>  The function does not have inverse.
D)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } }  ? ?</strong> A)?   The function does not have inverse. B)?   The function does not have inverse. C)?   The function does not have inverse. D)?   The function does not have inverse. E)?   The function does not have inverse. <div style=padding-top: 35px>  The function does not have inverse.
E)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } }  ? ?</strong> A)?   The function does not have inverse. B)?   The function does not have inverse. C)?   The function does not have inverse. D)?   The function does not have inverse. E)?   The function does not have inverse. <div style=padding-top: 35px>  The function does not have inverse.
سؤال
Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​
G(x)= |x + 5| - |x - 5|

A)​ <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​ G(x)= |x + 5| - |x - 5| ​</strong> A)​   The function does not have inverse. B)​   The function does not have inverse. C)​   The function does not have inverse. D)​   The function does not have inverse. E)   The function does not have inverse. <div style=padding-top: 35px> The function does not have inverse.
B)​ <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​ G(x)= |x + 5| - |x - 5| ​</strong> A)​   The function does not have inverse. B)​   The function does not have inverse. C)​   The function does not have inverse. D)​   The function does not have inverse. E)   The function does not have inverse. <div style=padding-top: 35px> The function does not have inverse.
C)​ <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​ G(x)= |x + 5| - |x - 5| ​</strong> A)​   The function does not have inverse. B)​   The function does not have inverse. C)​   The function does not have inverse. D)​   The function does not have inverse. E)   The function does not have inverse. <div style=padding-top: 35px> The function does not have inverse.
D)​ <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​ G(x)= |x + 5| - |x - 5| ​</strong> A)​   The function does not have inverse. B)​   The function does not have inverse. C)​   The function does not have inverse. D)​   The function does not have inverse. E)   The function does not have inverse. <div style=padding-top: 35px> The function does not have inverse.
E) <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​ G(x)= |x + 5| - |x - 5| ​</strong> A)​   The function does not have inverse. B)​   The function does not have inverse. C)​   The function does not have inverse. D)​   The function does not have inverse. E)   The function does not have inverse. <div style=padding-top: 35px> The function does not have inverse.
سؤال
Select the correct graph,showing f and g are inverse functions.? f(x)=6x2,g(x)=6x,x6f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6 ?

A)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
سؤال
Select the correct graph,showing f and g are inverse functions.? f(x)=x1x+8,g(x)=8x+1x1f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 } ?

A)?  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 }  ?</strong> A)?   B)?   C)   D)   E)   <div style=padding-top: 35px>
B)?  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 }  ?</strong> A)?   B)?   C)   D)   E)   <div style=padding-top: 35px>
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 }  ?</strong> A)?   B)?   C)   D)   E)   <div style=padding-top: 35px>
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 }  ?</strong> A)?   B)?   C)   D)   E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 }  ?</strong> A)?   B)?   C)   D)   E)   <div style=padding-top: 35px>
سؤال
Does the function have an inverse function?​ <strong>Does the function have an inverse function?​   ​</strong> A)No B)Yes <div style=padding-top: 35px>

A)No
B)Yes
سؤال
Select the correct graph,showing f and g are inverse functions.? f(x)=6x+1,g(x)=x16f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 } ?

A)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
سؤال
Find the inverse function of f informally. ?
F(x)= x4
?

A) f1(x)=4xf ^ { - 1 } ( x ) = 4 \sqrt { x } ?
B) f1(x)=x4f ^ { - 1 } ( x ) = \sqrt [ 4 ] { x }
C) f1(x)=1x4f ^ { - 1 } ( x ) = \frac { 1 } { \sqrt [ 4 ] { x } }
D) f1(x)=(x4)4f ^ { - 1 } ( x ) = ( \sqrt [ 4 ] { x } ) ^ { 4 }
E) f1(x)=x4f ^ { - 1 } ( x ) = - \sqrt [ 4 ] { x }
سؤال
Select the graph of f and f-1 on the same set of coordinate axes. ​
F(x)= 2x - 3

A) <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes. ​ F(x)= 2x - 3 ​</strong> A)   B)   C)   D)   E)​   <div style=padding-top: 35px>
B) <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes. ​ F(x)= 2x - 3 ​</strong> A)   B)   C)   D)   E)​   <div style=padding-top: 35px>
C) <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes. ​ F(x)= 2x - 3 ​</strong> A)   B)   C)   D)   E)​   <div style=padding-top: 35px>
D) <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes. ​ F(x)= 2x - 3 ​</strong> A)   B)   C)   D)   E)​   <div style=padding-top: 35px>
E)​ <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes. ​ F(x)= 2x - 3 ​</strong> A)   B)   C)   D)   E)​   <div style=padding-top: 35px>
سؤال
Select the correct graph,showing f and g are inverse functions.? f(x)=x37,g(x)=7x3f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x } ?

A)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x }  ?</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
سؤال
Find the inverse function of g(x)= x2 - 3 informally. ?

A) g1(x)=x32g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x - 3 }
B) g1(x)=(x+3)2g ^ { - 1 } ( x ) = ( x + 3 ) ^ { 2 }
C) g1(x)=x2+3g ^ { - 1 } ( x ) = x ^ { 2 } + 3
D) g1(x)=x+32g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x + 3 }
E) g1(x)=(x3)2g ^ { - 1 } ( x ) = ( x - 3 ) ^ { 2 }
سؤال
Find the inverse function of f informally. ?
F(x)= 6x
?

A)f-1(x)= 6 - x
B)f-1(x)= 6 + x
C) f1(x)=16xf ^ { - 1 } ( x ) = \frac { 1 } { 6 } x
D)f-1(x)= x - 6
E)f(x)= 6x
سؤال
Find the inverse function of f informally. ?
F(x)= x - 5
?

A)f-1(x)= - (x + 5)
B)? f1(x)=5xf ^ { - 1 } ( x ) = \frac { 5 } { x }
C) f1(x)=x5f ^ { - 1 } ( x ) = \frac { x } { 5 }
D)f-1(x)= 5 - x
E)f-1(x)= x + 5
سؤال
Use the tables of values for y = f(x)to complete a table for y = f -1(x).
x320123f(x)422468\begin{array} { | r | l | l | l | l | l | l | } \hline x & - 3 & - 2 & 0 & 1 & 2 & 3 \\\hline f ( x ) & - 4 & - 2 & 2 & 4 & 6 & 8 \\\hline\end{array}

A) x422468f1(x)320183\begin{array} { | l | l | l | l | l | l | l | } \hline x & - 4 & - 2 & 2 & 4 & 6 & 8 \\\hline f ^ { - 1 } ( x ) & - 3 & - 2 & 0 & 1 & 8 & 3 \\\hline\end{array}
B) x422466f1(x)220123\begin{array} { | l | l | l | l | l | l | l | } \hline x & - 4 & - 2 & 2 & 4 & 6 & 6 \\\hline f ^ { - 1 } ( x ) & - 2 & - 2 & 0 & 1 & 2 & 3 \\\hline\end{array}
C) x422468f1(x)301183\begin{array} { | l | l | l | l | l | l | l | } \hline x & - 4 & - 2 & 2 & 4 & 6 & 8 \\\hline f ^ { - 1 } ( x ) & - 3 & 0 & 1 & 1 & 8 & 3 \\\hline\end{array}
D) x422468f1(x)320623\begin{array} { | l | l | l | l | l | l | l | } \hline x & - 4 & - 2 & 2 & 4 & 6 & 8 \\\hline f ^ { - 1 } ( x ) & - 3 & - 2 & 0 & 6 & 2 & 3 \\\hline\end{array}
E) x422468f1(x)320123\begin{array} { | l | l | l | l | l | l | l | } \hline x & - 4 & - 2 & 2 & 4 & 6 & 8 \\\hline f ^ { - 1 } ( x ) & - 3 & - 2 & 0 & 1 & 2 & 3 \\\hline\end{array}
سؤال
Restrict the domain of the function f so that the function is one-to-one and has an inverse function.Then find the inverse function f-1.State the domains and ranges of f and f-1. ​
F(x)= |x - 9| + 1

A)f-1(x)= x + 8 The domain of f and the range of f-1 are all real numbers x such that x ≥ 9.The domain of f-1 and the range of f are all real numbers x such that x ≥ 1.
B)f-1(x)= x - 8 The domain of f and the range of f-1 are all real numbers x such that x ≥ 9.The domain of f-1 and the range of f are all real numbers x such that x ≥ 1.
C)f-1(x)= -x - 8 The domain of f and the range of f-1 are all real numbers x such that x ≥ 1.The domain of f-1 and the range of f are all real numbers x such that x ≥ -9.
D)f-1(x)= x + 8 The domain of f and the range of f-1 are all real numbers x such that x ≥ -9.The domain of f-1 and the range of f are all real numbers x such that x ≥ 1.
E)f-1(x)= -x + 8 The domain of f and the range of f-1 are all real numbers x such that x ≥ 1.The domain of f-1 and the range of f are all real numbers x such that x ≥ 9.
سؤال
Restrict the domain of the function f so that the function is one-to-one and has an inverse function.Then find the inverse function f-1.State the domains and ranges of f and f-1. ?
F(x)= -6x2 + 2
?

A) f1(x)=6(x2)6f ^ { - 1 } ( x ) = \frac { \sqrt { - 6 ( x - 2 ) } } { 6 } The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? 2.?
B) f1(x)=2(x6)2f ^ { - 1 } ( x ) = \frac { \sqrt { - 2 ( x - 6 ) } } { 2 } The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? 2.?
C) f1(x)=6(x2)6f ^ { - 1 } ( x ) = \frac { \sqrt { - 6 ( x - 2 ) } } { - 6 } The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? 2.?
D) f1(x)=6(x2)6f ^ { - 1 } ( x ) = \frac { \sqrt { - 6 ( x - 2 ) } } { 6 } The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? -2.?
E) f1(x)=6(x+2)6f ^ { - 1 } ( x ) = \frac { \sqrt { - 6 ( x + 2 ) } } { 6 } The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? 2.
سؤال
Determine whether the function has an inverse function.If it does,find the inverse function. ?
F(x)= (x + 4)2,x ? -4
?

A) f1(x)=x+4f ^ { - 1 } ( x ) = \sqrt { x } + 4
B)f-1(x)= -(x + 4)2
C)f-1(x)= (x + 4)-2
D)? f1(x)=x4f ^ { - 1 } ( x ) = \sqrt { x } - 4
E)No inverse
سؤال
Your wage is $11.00 per hour plus $0.50 for each unit produced per hour.So,your hourly wage in terms of the number of units produced x is y = 11 + 0.50x.Find the inverse function.What does each variable represent in the inverse function? ?

A) y=x110.50y = \frac { x - 11 } { 0.50 } x = hourly wage;y = numbers of units produced
B)y = 11 + 0.50x x = hourly wage;y = numbers of units produced
?
C) y=x+110.50y = \frac { x + 11 } { 0.50 } x = hourly wage;y = numbers of units produced
?
D) y=11x0.50y = \frac { 11 - x } { 0.50 } x = hourly wage;y = numbers of units produced
?
E)y = 11 - 0.50x x = hourly wage;y = numbers of units produced
?
سؤال
Restrict the domain of the function f so that the function is one-to-one and has an inverse function.Then find the inverse function f-1.State the domains and ranges of f and f-1. ?
F(x)= (x - 5)2
?

A) f1(x)=x5f ^ { - 1 } ( x ) = \sqrt { x } - 5 ?
The domain of f and the range of f-1 are all real numbers x such that x ? 5.The domain of f-1 and the range of f are all real numbers x such that x ? 0.
B) f1(x)=x+5f ^ { - 1 } ( x ) = \sqrt { x } + 5 ?
The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? -5.
C) f1(x)=x+5f ^ { - 1 } ( x ) = \sqrt { x } + 5 ?
The domain of f and the range of f-1 are all real numbers x such that x ? 5.The domain of f-1 and the range of f are all real numbers x such that x ? 0.
D) f1(x)=x+5f ^ { - 1 } ( x ) = \sqrt { x } + 5 ?
The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? 5.
E) f1(x)=x5f ^ { - 1 } ( x ) = \sqrt { x } - 5 ?
The domain of f and the range of f-1 are all real numbers x such that x ? -5.The domain of f-1 and the range of f are all real numbers x such that x ? 0.
سؤال
Use the functions given by f(x)=18x5f ( x ) = \frac { 1 } { 8 } x - 5 and g(x)= x3 to find (f-1 º f-1)(-5). ?

A)36
B)44
C)40
D)38
E)42
سؤال
Use the functions given by f(x)= x + 6 and g(x)= 7x - 3 to find g-1 º f-1. ?

A) x37\frac { - x - 3 } { 7 }
B) x+37\frac { x + 3 } { 7 }
C) x37\frac { x - 3 } { 7 }
D) x37\frac { x - 3 } { - 7 }
E) x73\frac { x - 7 } { 3 }
سؤال
Determine whether the function has an inverse function.If it does,find the inverse function.? h(x)=4x2h ( x ) = - \frac { 4 } { x ^ { 2 } } ?

A) h1(x)=4x2h ^ { - 1 } ( x ) = \frac { 4 } { x ^ { 2 } }
B) h1(x)=x24h ^ { - 1 } ( x ) = - \frac { x ^ { 2 } } { 4 }
C) h1(x)=4x2h ^ { - 1 } ( x ) = - \frac { 4 } { x ^ { 2 } }
D) h1(x)=x24h ^ { - 1 } ( x ) = \frac { x ^ { 2 } } { 4 }
E)No inverse
سؤال
Use the functions given by f(x)=1125x1f ( x ) = \frac { 1 } { 125 } x - 1 and g(x)= x3 to find (f º g)-1. ?

A) 5x135 \sqrt [ 3 ] { x - 1 }
B) 125x13125 \sqrt [ 3 ] { x - 1 }
C) 5x+135 \sqrt [ 3 ] { x + 1 }
D) 125x+13125 \sqrt [ 3 ] { x + 1 }
E) 5x+15 \sqrt { x + 1 }
سؤال
Use the functions given by f(x)=164x4f ( x ) = \frac { 1 } { 64 } x - 4 and g(x)= x3 to find g-1 º f-1. ?

A) 4(4x)34 \sqrt [ 3 ] { ( 4 - x ) }
B) 4(x+4)3- 4 \sqrt [ 3 ] { ( x + 4 ) }
C) 4(x4)3- 4 \sqrt [ 3 ] { ( x - 4 ) }
D) 4(x4)34 \sqrt [ 3 ] { ( x - 4 ) }
E) 4(x+4)34 \sqrt [ 3 ] { ( x + 4 ) }
سؤال
Determine whether the function has an inverse function.If it does,find the inverse function.? f(x)=7x+8f ( x ) = \sqrt { 7 x + 8 } ?

A) f1(x)=x2+87f ^ { - 1 } ( x ) = - \frac { x ^ { 2 } + 8 } { 7 }
B) f1(x)=x287f ^ { - 1 } ( x ) = - \frac { x ^ { 2 } - 8 } { 7 }
C) f1(x)=x287f ^ { - 1 } ( x ) = \frac { x ^ { 2 } - 8 } { 7 }
D) f1(x)=x2+87f ^ { - 1 } ( x ) = \frac { x ^ { 2 } + 8 } { 7 }
E)No Inverse
سؤال
Determine whether the function has an inverse function.If it does,find the inverse function. ?
F(x)= -2
?

A)f-1(x)= 2
B) f1(x)=12f ^ { - 1 } ( x ) = - \frac { 1 } { 2 }
C) f1(x)=12f ^ { - 1 } ( x ) = \frac { 1 } { 2 }
D)f-1(x)= -2
E)No inverse
سؤال
Determine whether the function has an inverse function.If it does,find the inverse function.? g(x)=x5g ( x ) = \frac { x } { 5 } ?

A) g1(x)=5xg ^ { - 1 } ( x ) = - 5 x
B) g1(x)=5xg ^ { - 1 } ( x ) = 5 x
C) g1(x)=5xg ^ { - 1 } ( x ) = \frac { 5 } { x }
D) g1(x)=x5g ^ { - 1 } ( x ) = - \frac { x } { 5 }
E)No inverse
سؤال
Use the functions given by f(x)= x + 2 and g(x)= 2x - 5 to find (f º g)-1. ?

A) x+32\frac { x + 3 } { 2 }
B) x32\frac { x - 3 } { - 2 }
C) x43\frac { x - 4 } { 3 }
D) x32\frac { x - 3 } { 2 }
E) x32\frac { - x - 3 } { 2 }
سؤال
Restrict the domain of the function f so that the function is one-to-one and has an inverse function.Then find the inverse function f-1.State the domains and ranges of f and f-1. ​
F(x)= |x + 5|

A)f​-1(x)= x - 5 ​
The domain of f and the range of f-1 are all real numbers x such that x ≥ -5.The domain of f-1 and the range of f are all real numbers x such that x ≥ 0.
B)f​-1(x)= x + 5 ​
The domain of f and the range of f-1 are all real numbers x such that x ≥ 0.The domain of f-1 and the range of f are all real numbers x such that x ≥ -5.
C)f​-1(x)= x - 5 ​
The domain of f and the range of f-1 are all real numbers x such that x ≥ 0.The domain of f-1 and the range of f are all real numbers x such that x ≥ 5.
D)f​-1(x)= x + 5 ​
The domain of f and the range of f-1 are all real numbers x such that x ≥ 5.The domain of f-1 and the range of f are all real numbers x such that x ≥ 0.
E)f​-1(x)= x - 5 ​
The domain of f and the range of f-1 are all real numbers x such that x ≥ 5.The domain of f-1 and the range of f are all real numbers x such that x ≥ 0.
سؤال
?Use the graph of the function f to create a table of values for the given points.Then create a second table that can be used to find f-1. ??  <strong>?Use the graph of the function f to create a table of values for the given points.Then create a second table that can be used to find f<sup>-1</sup>. ??   ?</strong> A)  \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline y & 1 & 4 & 7 & 9 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 8 \\ \hline \end{array} \end{array}  B)  \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline y & 1 & 4 & 7 & 8 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\ \hline \end{array} \end{array}  C)  \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline y & 1 & 4 & 7 & 9 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\ \hline \end{array} \end{array}  D)  \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\ \hline y & 1 & 4 & 7 & 8 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\ \hline \end{array} \end{array}  E)  \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\ \hline y & 1 & 4 & 7 & 8 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\ \hline \end{array} \end{array}  <div style=padding-top: 35px>  ?

A) x1478y1479x1479f1(x)1478\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\\hline y & 1 & 4 & 7 & 9 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\\hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 8 \\\hline\end{array}\end{array}
B) x1479y1478x1478f1(x)1479\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\\hline y & 1 & 4 & 7 & 8 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\\hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\\hline\end{array}\end{array}
C) x1478y1479x1479f1(x)1478\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\\hline y & 1 & 4 & 7 & 9 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\\hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\\hline\end{array}\end{array}
D) x1479y1478x1478f1(x)1479\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\\hline y & 1 & 4 & 7 & 8 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\\hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\\hline\end{array}\end{array}
E) x1479y1478x1479f1(x)1478\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\\hline y & 1 & 4 & 7 & 8 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\\hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\\hline\end{array}\end{array}
سؤال
The function given by y = 0.03x2 + 245.50,0 < x < 100 approximates the exhaust temperature y in degrees Fahrenheit,x where is the percent load for a diesel engine.Find the inverse function. ?

A) y=x+245.500.03y = \frac { x + 245.50 } { - 0.03 }
B) y=x245.500.03y = \sqrt { \frac { x - 245.50 } { 0.03 } }
C) y=x245.500.03y = \frac { x - 245.50 } { 0.03 }
D) y=x+245.500.03y = \sqrt { \frac { x + 245.50 } { 0.03 } }
E) y=x+245.500.03y = \frac { x + 245.50 } { 0.03 }
سؤال
Determine whether the function has an inverse function.If it does,find the inverse function.? f ( x ) = \left\{ \begin{array} { l } x + 2 , x < 0 \\2 - x , x \geq 0\end{array} \\) ?</strong><div>A) \(f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } 2 + x , x \geq 0 \\x - 2 , x < 0\end{array} \right. .

B) f1(x)={2+x,x0x2,x<0f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } 2 + x , x \geq 0 \\x - 2 , x < 0\end{array} \right.

C) f1(x)={x2,x02+x,x<0f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } x - 2 , x \geq 0 \\2 + x , x < 0\end{array} \right.

D) f1(x)={x+2,x02x,x<0f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } x + 2 , x \geq 0 \\2 - x , x < 0\end{array} \right. .

E)No inverse
سؤال
Use the functions given by f(x)=18x5f ( x ) = \frac { 1 } { 8 } x - 5 and g(x)= x3 to find (g-1 º f-1)(-5). ?

A)-2
B)0
C)-4
D)2
E)4
سؤال
Use the functions given by f(x)=18x1f ( x ) = \frac { 1 } { 8 } x - 1 and g(x)= x3 to find (f-1 º g-1)(1). ?

A)14
B)12
C)16
D)20
E)18
سؤال
Find the inverse of the one-to-one function.? y=18xy = \frac { 1 } { 8 x } ?

A) f1(x)=8xf ^ { - 1 } ( x ) = \frac { 8 } { x }
B) f1(x)=x8f ^ { - 1 } ( x ) = \frac { x } { 8 }
C) f1(x)=8xf ^ { - 1 } ( x ) = 8 x
D) f1(x)=18xf ^ { - 1 } ( x ) = \frac { 1 } { 8 x }
E)inverse does not exist
سؤال
Find the inverse of the one-to-one function. ?
Y = 3x
?

A) f1(x)=3x2f ^ { - 1 } ( x ) = 3 x ^ { 2 }
B)f -1(x)= 3x
C) f1(x)=x3f ^ { - 1 } ( x ) = \frac { x } { 3 }
D) f1(x)=3xf ^ { - 1 } ( x ) = \frac { 3 } { x }
E)f -1(x)= 9x
سؤال
Find the inverse of the one-to-one function.

y = 6x

f -1(x)= __________
سؤال
Restrict the domain of f(x)= x2 + 5 to x ≥ 0.Use a graphing utility to graph the function. ​

A)​ <strong>Restrict the domain of f(x)= x<sup>2</sup> + 5 to x ≥ 0.Use a graphing utility to graph the function. ​</strong> A)​   B)   C)​   D)​   E)   <div style=padding-top: 35px>
B) <strong>Restrict the domain of f(x)= x<sup>2</sup> + 5 to x ≥ 0.Use a graphing utility to graph the function. ​</strong> A)​   B)   C)​   D)​   E)   <div style=padding-top: 35px>
C)​ <strong>Restrict the domain of f(x)= x<sup>2</sup> + 5 to x ≥ 0.Use a graphing utility to graph the function. ​</strong> A)​   B)   C)​   D)​   E)   <div style=padding-top: 35px>
D)​ <strong>Restrict the domain of f(x)= x<sup>2</sup> + 5 to x ≥ 0.Use a graphing utility to graph the function. ​</strong> A)​   B)   C)​   D)​   E)   <div style=padding-top: 35px>
E) <strong>Restrict the domain of f(x)= x<sup>2</sup> + 5 to x ≥ 0.Use a graphing utility to graph the function. ​</strong> A)​   B)   C)​   D)​   E)   <div style=padding-top: 35px>
سؤال
Find the inverse of the one-to-one function. ?
Y = 5x + 9
?

A) f1(x)=x+95f ^ { - 1 } ( x ) = \frac { x + 9 } { 5 }
B) f1(x)=x95f ^ { - 1 } ( x ) = \frac { x - 9 } { 5 }
C) f1(x)=5x9f ^ { - 1 } ( x ) = \frac { 5 } { x - 9 }
D) f1(x)=x59f ^ { - 1 } ( x ) = \frac { x - 5 } { 9 }
E)none of the above
سؤال
Show algebraically that f and g are inverse functions.
f(x)= 9x + 9 Show algebraically that f and g are inverse functions. f(x)= 9x + 9  <div style=padding-top: 35px>
سؤال
Find the inverse of the one-to-one function.

y = 5x + 4

f -1(x)= __________
سؤال
Consider the functions given by f(x)= x + 3 and f-1(x)= x - 3.Evaluate f(f-1(x))and f-1(f(x))for the indicated values of x.What can you conclude about the functions
x10449f(f1(x))f1(f(x))\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & & & & \\\hline f ^ { - 1 } ( f ( x ) ) & & & & \\\hline\end{array}

A) x10449f(f1(x))10449f1(f(x))10449\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & - 1 & 0 & - 4 & - 49 \\\hline f ^ { - 1 } ( f ( x ) ) & - 1 & 0 & 4 & 49 \\\hline\end{array} We can conclude that, both the functions have the same value for negative variables
B) x10449f(f1(x))10449f1(f(x))10449\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & - 1 & 0 & 4 & 49 \\\hline f ^ { - 1 } ( f ( x ) ) & - 1 & 0 & 4 & 49 \\\hline\end{array} We can conclude that, both the functions have the same value
C) x10449f(f1(x))10449f1(f(x))10449\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & - 1 & 0 & 4 & 49 \\\hline f ^ { - 1 } ( f ( x ) ) & - 1 & 0 & - 4 & - 49 \\\hline\end{array} We can conclude that, both the functions have the same value for negative variables.
D) x10449f(f1(x))10449f1(f(x))10449\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & - 1 & 0 & - 4 & 49 \\\hline f ^ { - 1 } ( f ( x ) ) & - 1 & 0 & 4 & - 49 \\\hline\end{array} We can conclude that, both the functions are opposite of each other.
E) x10449f(f1(x))10449f1(f(x))10449\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & - 1 & 0 & 4 & - 49 \\\hline f ^ { - 1 } ( f ( x ) ) & - 1 & 0 & - 4 & 49 \\\hline\end{array}
We can conclude that, both the functions are opposite of each other.
سؤال
Graph the given function. f(x)= (x - 3)2 <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>

A) <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
سؤال
Find the inverse of the one-to-one function.​ Find the inverse of the one-to-one function.​   ​ f <sup>-1</sup>(x)= __________<div style=padding-top: 35px>
f -1(x)= __________
سؤال
Show algebraically that f and g are inverse functions. Show algebraically that f and g are inverse functions.   ,x ≥ 8 g(x)= x<sup>2</sup> + 8,x ≥ 0<div style=padding-top: 35px> ,x ≥ 8 g(x)= x2 + 8,x ≥ 0
سؤال
Determine algebraically whether f and g are inverse functions. f(x)= 5x - 3 g(x)=x+35g ( x ) = \frac { x + 3 } { 5 }

A)Yes,f and g are inverse functions. f(g(x))=f(x+35)=5(x+35)3=x+33=xf ( g ( x ) ) = f \left( \frac { x + 3 } { 5 } \right) = 5 \left( \frac { x + 3 } { 5 } \right) - 3 = x + 3 - 3 = x g(f(x))=g(5x3)=5x3+35=5x5=xg ( f ( x ) ) = g ( 5 x - 3 ) = \frac { 5 x - 3 + 3 } { 5 } = \frac { 5 x } { 5 } = x
B)No,f and g are not inverse functions. f(g(x))=f(x+35)=5(x+35)3=x+33=xf ( g ( x ) ) = f \left( \frac { x + 3 } { 5 } \right) = 5 \left( \frac { x + 3 } { 5 } \right) - 3 = x + 3 - 3 = x g(f(x))=g(5x3)=5x3+35=5x5=xg ( f ( x ) ) = g ( 5 x - 3 ) = \frac { 5 x - 3 + 3 } { 5 } = \frac { 5 x } { 5 } = - x
سؤال
The function f(x)= x2 - 2 is one-to-one on the domain (x ? 0).Find f -1(x). ?

A) f1(x)=x+2f ^ { - 1 } ( x ) = - \sqrt { x + 2 }
B) f1(x)=1x22f ^ { - 1 } ( x ) = \frac { 1 } { x ^ { 2 } - 2 }
C) f1(x)=x+2f ^ { - 1 } ( x ) = \sqrt { x + 2 }
D) f1(x)=x2f ^ { - 1 } ( x ) = \sqrt { x - 2 }
E)f -1(x)= x2 + 2
سؤال
Determine whether the function has an inverse function.If it does,find the inverse function. f(x)= x2 + 5

A) f1(x)=x+5,x0f ^ { - 1 } ( x ) = \sqrt { x } + 5 , x \geq 0
B) f1(x)=x5f ^ { - 1 } ( x ) = \sqrt { x - 5 }
C) f1(x)=x5f ^ { - 1 } ( x ) = \sqrt { x } - 5
D) f1(x)=x+5,x5f ^ { - 1 } ( x ) = \sqrt { x + 5 } , x \geq - 5
E)No inverse function exists.
سؤال
Determine whether the function is one-to- one. ​
Y = 3x

A)No,it isn't one-to-one.
B)Yes,it is one-to-one.
سؤال
Determine algebraically whether f and g are inverse functions. f(x)=x+6f ( x ) = \sqrt { x + 6 } g(x)= x2 - 6,x ? 0

A)Yes,f and g are inverse functions. f(g(x))=f(x26)=(x26)+6=x2=xf ( g ( x ) ) = f \left( x ^ { 2 } - 6 \right) = \sqrt { \left( x ^ { 2 } - 6 \right) + 6 } = \sqrt { x ^ { 2 } } = x g(f(x))=g(x+6)=(x+6)26=x+66=xg ( f ( x ) ) = g ( \sqrt { x + 6 } ) = ( \sqrt { x + 6 } ) ^ { 2 } - 6 = x + 6 - 6 = x
B)No,f and g are not inverse functions. f(g(x))=f(x26)=(x26)+6=x2=xf ( g ( x ) ) = f \left( x ^ { 2 } - 6 \right) = \sqrt { \left( x ^ { 2 } - 6 \right) + 6 } = \sqrt { x ^ { 2 } } = x g(f(x))=g(x+6)=(x+6)26=x+66=xg ( f ( x ) ) = g ( \sqrt { x + 6 } ) = ( \sqrt { x + 6 } ) ^ { 2 } - 6 = - x + 6 - 6 = - x
سؤال
?Use the functions given by f(x)=x81f ( x ) = \frac { x } { 8 } - 1 and g(x)= x3 to find the indicated value. (f º g)-1(5)

A)? 387512- \frac { 387 } { 512 }
B)? 2632 \sqrt [ 3 ] { 6 }
C)? 263- 2 \sqrt [ 3 ] { 6 }
D)? 2432 \sqrt [ 3 ] { 4 }
E)?Undefined
سؤال
Determine whether the function has an inverse function.If it does,find the inverse function. f(x)={8x+13,x<2(x+2)23,x2f ( x ) = \left\{ \begin{array} { l } 8 x + 13 , x < - 2 \\( x + 2 ) ^ { 2 } - 3 , x \geq - 2\end{array} \right.

A) f1(x)={x138,x<2x+32,x2f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } \frac { x - 13 } { 8 } , x < - 2 \\\\\sqrt { x + 3 } - 2 , x \geq - 2\end{array} \right.
B)? f1(x)={x138,x<2x+1,x2f ^ { - 1 } ( x ) = \left\{ \begin{array} { c } \frac { x - 13 } { 8 } , x < - 2 \\\\\sqrt { x + 1 } , x \geq - 2\end{array} \right.
C) f1(x)={x138,x<3x+32,x3f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } \frac { x - 13 } { 8 } , x < - 3 \\\\\sqrt { x + 3 } - 2 , x \geq - 3\end{array} \right.
D) f1(x)={x+138,x<3x+32,x3f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } \frac { x + 13 } { 8 } , x < - 3 \\\\\sqrt { x + 3 } - 2 , x \geq - 3\end{array} \right.
E)No inverse function exists.
سؤال
Determine whether the function is one-to-one. ​
Y = (x - 5)2;x ≥ 5

A)No,it isn't one-to-one.
B)Yes,it is one-to-one.
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Deck 9: Inverse Functions
1
Select the correct graph,showing f and g are inverse functions.? f(x)=x3,g(x)=x2+3,x0f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0 ?

A)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0  ?</strong> A)   B)   C)   D)   E)
B)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0  ?</strong> A)   B)   C)   D)   E)
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0  ?</strong> A)   B)   C)   D)   E)
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0  ?</strong> A)   B)   C)   D)   E)
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \sqrt { x - 3 } , g ( x ) = x ^ { 2 } + 3 , x \geq 0  ?</strong> A)   B)   C)   D)   E)

2
Determine whether the function has an inverse function.If it does,find the inverse function. ?
G(x)= x7
?

A) g1(x)=7xg ^ { - 1 } ( x ) = \frac { 7 } { x }
B)g-1(x)= -7x
C)? g1(x)=x7g ^ { - 1 } ( x ) = - \frac { x } { 7 }
D)g-1(x)= 7x
E)The inverse exists,but none of the above
The inverse exists,but none of the above
3
Find the inverse function of f(x)=36x2,0x6f ( x ) = \sqrt { 36 - x ^ { 2 } } , 0 \leq x \leq 6 . ?

A) f1(x)=36x2,0x6f ^ { - 1 } ( x ) = \sqrt { 36 - x ^ { 2 } } , 0 \leq x \leq 6
B) f1(x)=x236,0x6f ^ { - 1 } ( x ) = \sqrt { x ^ { 2 } - 36 } , 0 \leq x \leq 6
C) f1(x)=36x2,0x6f ^ { - 1 } ( x ) = 36 - x ^ { 2 } , 0 \leq x \leq 6
D) f1(x)=36+x2,0x6f ^ { - 1 } ( x ) = \sqrt { 36 + x ^ { 2 } } , 0 \leq x \leq 6
E) f1(x)=36+x2,0x6f ^ { - 1 } ( x ) = 36 + x ^ { 2 } , 0 \leq x \leq 6
f1(x)=36x2,0x6f ^ { - 1 } ( x ) = \sqrt { 36 - x ^ { 2 } } , 0 \leq x \leq 6
4
Select the graph of f and f-1 on the same set of coordinate axes.? f(x)=3xf ( x ) = \frac { 3 } { x } ?

A)  <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes.?  f ( x ) = \frac { 3 } { x }  ?</strong> A)   ? B)   C)?   D)?   E)    ?
B)  <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes.?  f ( x ) = \frac { 3 } { x }  ?</strong> A)   ? B)   C)?   D)?   E)
C)?  <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes.?  f ( x ) = \frac { 3 } { x }  ?</strong> A)   ? B)   C)?   D)?   E)
D)?  <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes.?  f ( x ) = \frac { 3 } { x }  ?</strong> A)   ? B)   C)?   D)?   E)
E)  <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes.?  f ( x ) = \frac { 3 } { x }  ?</strong> A)   ? B)   C)?   D)?   E)
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5
Select the correct graph,showing f and g are inverse functions.? f(x)=9x,g(x)=x9f ( x ) = 9 x , g ( x ) = \frac { x } { 9 } ?

A)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 9 x , g ( x ) = \frac { x } { 9 }  ?</strong> A)   B)   C)   D)   E)
B)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 9 x , g ( x ) = \frac { x } { 9 }  ?</strong> A)   B)   C)   D)   E)
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 9 x , g ( x ) = \frac { x } { 9 }  ?</strong> A)   B)   C)   D)   E)
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 9 x , g ( x ) = \frac { x } { 9 }  ?</strong> A)   B)   C)   D)   E)
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 9 x , g ( x ) = \frac { x } { 9 }  ?</strong> A)   B)   C)   D)   E)
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6
Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.? g(x)=4x5g ( x ) = \frac { 4 - x } { 5 } ? ?

A)  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = \frac { 4 - x } { 5 }  ? ?</strong> A)   The function has an inverse. B)?   The function has an inverse. C)?   The function has an inverse. D)?   The function has an inverse. E)?   The function has an inverse.  The function has an inverse.
B)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = \frac { 4 - x } { 5 }  ? ?</strong> A)   The function has an inverse. B)?   The function has an inverse. C)?   The function has an inverse. D)?   The function has an inverse. E)?   The function has an inverse.  The function has an inverse.
C)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = \frac { 4 - x } { 5 }  ? ?</strong> A)   The function has an inverse. B)?   The function has an inverse. C)?   The function has an inverse. D)?   The function has an inverse. E)?   The function has an inverse.  The function has an inverse.
D)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = \frac { 4 - x } { 5 }  ? ?</strong> A)   The function has an inverse. B)?   The function has an inverse. C)?   The function has an inverse. D)?   The function has an inverse. E)?   The function has an inverse.  The function has an inverse.
E)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = \frac { 4 - x } { 5 }  ? ?</strong> A)   The function has an inverse. B)?   The function has an inverse. C)?   The function has an inverse. D)?   The function has an inverse. E)?   The function has an inverse.  The function has an inverse.
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7
Does the function have an inverse function?​ <strong>Does the function have an inverse function?​   ​</strong> A)No B)Yes

A)No
B)Yes
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8
Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.? g(x)=2x6x2g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } } ? ?

A)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } }  ? ?</strong> A)?   The function does not have inverse. B)?   The function does not have inverse. C)?   The function does not have inverse. D)?   The function does not have inverse. E)?   The function does not have inverse.  The function does not have inverse.
B)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } }  ? ?</strong> A)?   The function does not have inverse. B)?   The function does not have inverse. C)?   The function does not have inverse. D)?   The function does not have inverse. E)?   The function does not have inverse.  The function does not have inverse.
C)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } }  ? ?</strong> A)?   The function does not have inverse. B)?   The function does not have inverse. C)?   The function does not have inverse. D)?   The function does not have inverse. E)?   The function does not have inverse.  The function does not have inverse.
D)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } }  ? ?</strong> A)?   The function does not have inverse. B)?   The function does not have inverse. C)?   The function does not have inverse. D)?   The function does not have inverse. E)?   The function does not have inverse.  The function does not have inverse.
E)?  <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function.?  g ( x ) = - 2 x \sqrt { 6 - x ^ { 2 } }  ? ?</strong> A)?   The function does not have inverse. B)?   The function does not have inverse. C)?   The function does not have inverse. D)?   The function does not have inverse. E)?   The function does not have inverse.  The function does not have inverse.
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9
Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​
G(x)= |x + 5| - |x - 5|

A)​ <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​ G(x)= |x + 5| - |x - 5| ​</strong> A)​   The function does not have inverse. B)​   The function does not have inverse. C)​   The function does not have inverse. D)​   The function does not have inverse. E)   The function does not have inverse. The function does not have inverse.
B)​ <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​ G(x)= |x + 5| - |x - 5| ​</strong> A)​   The function does not have inverse. B)​   The function does not have inverse. C)​   The function does not have inverse. D)​   The function does not have inverse. E)   The function does not have inverse. The function does not have inverse.
C)​ <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​ G(x)= |x + 5| - |x - 5| ​</strong> A)​   The function does not have inverse. B)​   The function does not have inverse. C)​   The function does not have inverse. D)​   The function does not have inverse. E)   The function does not have inverse. The function does not have inverse.
D)​ <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​ G(x)= |x + 5| - |x - 5| ​</strong> A)​   The function does not have inverse. B)​   The function does not have inverse. C)​   The function does not have inverse. D)​   The function does not have inverse. E)   The function does not have inverse. The function does not have inverse.
E) <strong>Select the graph of the function,and use the Horizontal Line Test to determine whether the function is one-to-one and so has an inverse function. ​ G(x)= |x + 5| - |x - 5| ​</strong> A)​   The function does not have inverse. B)​   The function does not have inverse. C)​   The function does not have inverse. D)​   The function does not have inverse. E)   The function does not have inverse. The function does not have inverse.
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10
Select the correct graph,showing f and g are inverse functions.? f(x)=6x2,g(x)=6x,x6f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6 ?

A)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6  ?</strong> A)   B)   C)   D)   E)
B)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6  ?</strong> A)   B)   C)   D)   E)
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6  ?</strong> A)   B)   C)   D)   E)
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6  ?</strong> A)   B)   C)   D)   E)
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 - x ^ { 2 } , g ( x ) = \sqrt { 6 - x } , x \leq 6  ?</strong> A)   B)   C)   D)   E)
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11
Select the correct graph,showing f and g are inverse functions.? f(x)=x1x+8,g(x)=8x+1x1f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 } ?

A)?  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 }  ?</strong> A)?   B)?   C)   D)   E)
B)?  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 }  ?</strong> A)?   B)?   C)   D)   E)
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 }  ?</strong> A)?   B)?   C)   D)   E)
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 }  ?</strong> A)?   B)?   C)   D)   E)
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x - 1 } { x + 8 } , g ( x ) = - \frac { 8 x + 1 } { x - 1 }  ?</strong> A)?   B)?   C)   D)   E)
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12
Does the function have an inverse function?​ <strong>Does the function have an inverse function?​   ​</strong> A)No B)Yes

A)No
B)Yes
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13
Select the correct graph,showing f and g are inverse functions.? f(x)=6x+1,g(x)=x16f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 } ?

A)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 }  ?</strong> A)   B)   C)   D)   E)
B)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 }  ?</strong> A)   B)   C)   D)   E)
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 }  ?</strong> A)   B)   C)   D)   E)
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 }  ?</strong> A)   B)   C)   D)   E)
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = 6 x + 1 , g ( x ) = \frac { x - 1 } { 6 }  ?</strong> A)   B)   C)   D)   E)
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14
Find the inverse function of f informally. ?
F(x)= x4
?

A) f1(x)=4xf ^ { - 1 } ( x ) = 4 \sqrt { x } ?
B) f1(x)=x4f ^ { - 1 } ( x ) = \sqrt [ 4 ] { x }
C) f1(x)=1x4f ^ { - 1 } ( x ) = \frac { 1 } { \sqrt [ 4 ] { x } }
D) f1(x)=(x4)4f ^ { - 1 } ( x ) = ( \sqrt [ 4 ] { x } ) ^ { 4 }
E) f1(x)=x4f ^ { - 1 } ( x ) = - \sqrt [ 4 ] { x }
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15
Select the graph of f and f-1 on the same set of coordinate axes. ​
F(x)= 2x - 3

A) <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes. ​ F(x)= 2x - 3 ​</strong> A)   B)   C)   D)   E)​
B) <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes. ​ F(x)= 2x - 3 ​</strong> A)   B)   C)   D)   E)​
C) <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes. ​ F(x)= 2x - 3 ​</strong> A)   B)   C)   D)   E)​
D) <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes. ​ F(x)= 2x - 3 ​</strong> A)   B)   C)   D)   E)​
E)​ <strong>Select the graph of f and f<sup>-1</sup> on the same set of coordinate axes. ​ F(x)= 2x - 3 ​</strong> A)   B)   C)   D)   E)​
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16
Select the correct graph,showing f and g are inverse functions.? f(x)=x37,g(x)=7x3f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x } ?

A)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x }  ?</strong> A)   B)   C)   D)   E)
B)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x }  ?</strong> A)   B)   C)   D)   E)
C)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x }  ?</strong> A)   B)   C)   D)   E)
D)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x }  ?</strong> A)   B)   C)   D)   E)
E)  <strong>Select the correct graph,showing f and g are inverse functions.?  f ( x ) = \frac { x ^ { 3 } } { 7 } , g ( x ) = \sqrt [ 3 ] { 7 x }  ?</strong> A)   B)   C)   D)   E)
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17
Find the inverse function of g(x)= x2 - 3 informally. ?

A) g1(x)=x32g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x - 3 }
B) g1(x)=(x+3)2g ^ { - 1 } ( x ) = ( x + 3 ) ^ { 2 }
C) g1(x)=x2+3g ^ { - 1 } ( x ) = x ^ { 2 } + 3
D) g1(x)=x+32g ^ { - 1 } ( x ) = \sqrt [ 2 ] { x + 3 }
E) g1(x)=(x3)2g ^ { - 1 } ( x ) = ( x - 3 ) ^ { 2 }
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18
Find the inverse function of f informally. ?
F(x)= 6x
?

A)f-1(x)= 6 - x
B)f-1(x)= 6 + x
C) f1(x)=16xf ^ { - 1 } ( x ) = \frac { 1 } { 6 } x
D)f-1(x)= x - 6
E)f(x)= 6x
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19
Find the inverse function of f informally. ?
F(x)= x - 5
?

A)f-1(x)= - (x + 5)
B)? f1(x)=5xf ^ { - 1 } ( x ) = \frac { 5 } { x }
C) f1(x)=x5f ^ { - 1 } ( x ) = \frac { x } { 5 }
D)f-1(x)= 5 - x
E)f-1(x)= x + 5
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20
Use the tables of values for y = f(x)to complete a table for y = f -1(x).
x320123f(x)422468\begin{array} { | r | l | l | l | l | l | l | } \hline x & - 3 & - 2 & 0 & 1 & 2 & 3 \\\hline f ( x ) & - 4 & - 2 & 2 & 4 & 6 & 8 \\\hline\end{array}

A) x422468f1(x)320183\begin{array} { | l | l | l | l | l | l | l | } \hline x & - 4 & - 2 & 2 & 4 & 6 & 8 \\\hline f ^ { - 1 } ( x ) & - 3 & - 2 & 0 & 1 & 8 & 3 \\\hline\end{array}
B) x422466f1(x)220123\begin{array} { | l | l | l | l | l | l | l | } \hline x & - 4 & - 2 & 2 & 4 & 6 & 6 \\\hline f ^ { - 1 } ( x ) & - 2 & - 2 & 0 & 1 & 2 & 3 \\\hline\end{array}
C) x422468f1(x)301183\begin{array} { | l | l | l | l | l | l | l | } \hline x & - 4 & - 2 & 2 & 4 & 6 & 8 \\\hline f ^ { - 1 } ( x ) & - 3 & 0 & 1 & 1 & 8 & 3 \\\hline\end{array}
D) x422468f1(x)320623\begin{array} { | l | l | l | l | l | l | l | } \hline x & - 4 & - 2 & 2 & 4 & 6 & 8 \\\hline f ^ { - 1 } ( x ) & - 3 & - 2 & 0 & 6 & 2 & 3 \\\hline\end{array}
E) x422468f1(x)320123\begin{array} { | l | l | l | l | l | l | l | } \hline x & - 4 & - 2 & 2 & 4 & 6 & 8 \\\hline f ^ { - 1 } ( x ) & - 3 & - 2 & 0 & 1 & 2 & 3 \\\hline\end{array}
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21
Restrict the domain of the function f so that the function is one-to-one and has an inverse function.Then find the inverse function f-1.State the domains and ranges of f and f-1. ​
F(x)= |x - 9| + 1

A)f-1(x)= x + 8 The domain of f and the range of f-1 are all real numbers x such that x ≥ 9.The domain of f-1 and the range of f are all real numbers x such that x ≥ 1.
B)f-1(x)= x - 8 The domain of f and the range of f-1 are all real numbers x such that x ≥ 9.The domain of f-1 and the range of f are all real numbers x such that x ≥ 1.
C)f-1(x)= -x - 8 The domain of f and the range of f-1 are all real numbers x such that x ≥ 1.The domain of f-1 and the range of f are all real numbers x such that x ≥ -9.
D)f-1(x)= x + 8 The domain of f and the range of f-1 are all real numbers x such that x ≥ -9.The domain of f-1 and the range of f are all real numbers x such that x ≥ 1.
E)f-1(x)= -x + 8 The domain of f and the range of f-1 are all real numbers x such that x ≥ 1.The domain of f-1 and the range of f are all real numbers x such that x ≥ 9.
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22
Restrict the domain of the function f so that the function is one-to-one and has an inverse function.Then find the inverse function f-1.State the domains and ranges of f and f-1. ?
F(x)= -6x2 + 2
?

A) f1(x)=6(x2)6f ^ { - 1 } ( x ) = \frac { \sqrt { - 6 ( x - 2 ) } } { 6 } The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? 2.?
B) f1(x)=2(x6)2f ^ { - 1 } ( x ) = \frac { \sqrt { - 2 ( x - 6 ) } } { 2 } The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? 2.?
C) f1(x)=6(x2)6f ^ { - 1 } ( x ) = \frac { \sqrt { - 6 ( x - 2 ) } } { - 6 } The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? 2.?
D) f1(x)=6(x2)6f ^ { - 1 } ( x ) = \frac { \sqrt { - 6 ( x - 2 ) } } { 6 } The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? -2.?
E) f1(x)=6(x+2)6f ^ { - 1 } ( x ) = \frac { \sqrt { - 6 ( x + 2 ) } } { 6 } The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? 2.
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23
Determine whether the function has an inverse function.If it does,find the inverse function. ?
F(x)= (x + 4)2,x ? -4
?

A) f1(x)=x+4f ^ { - 1 } ( x ) = \sqrt { x } + 4
B)f-1(x)= -(x + 4)2
C)f-1(x)= (x + 4)-2
D)? f1(x)=x4f ^ { - 1 } ( x ) = \sqrt { x } - 4
E)No inverse
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24
Your wage is $11.00 per hour plus $0.50 for each unit produced per hour.So,your hourly wage in terms of the number of units produced x is y = 11 + 0.50x.Find the inverse function.What does each variable represent in the inverse function? ?

A) y=x110.50y = \frac { x - 11 } { 0.50 } x = hourly wage;y = numbers of units produced
B)y = 11 + 0.50x x = hourly wage;y = numbers of units produced
?
C) y=x+110.50y = \frac { x + 11 } { 0.50 } x = hourly wage;y = numbers of units produced
?
D) y=11x0.50y = \frac { 11 - x } { 0.50 } x = hourly wage;y = numbers of units produced
?
E)y = 11 - 0.50x x = hourly wage;y = numbers of units produced
?
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25
Restrict the domain of the function f so that the function is one-to-one and has an inverse function.Then find the inverse function f-1.State the domains and ranges of f and f-1. ?
F(x)= (x - 5)2
?

A) f1(x)=x5f ^ { - 1 } ( x ) = \sqrt { x } - 5 ?
The domain of f and the range of f-1 are all real numbers x such that x ? 5.The domain of f-1 and the range of f are all real numbers x such that x ? 0.
B) f1(x)=x+5f ^ { - 1 } ( x ) = \sqrt { x } + 5 ?
The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? -5.
C) f1(x)=x+5f ^ { - 1 } ( x ) = \sqrt { x } + 5 ?
The domain of f and the range of f-1 are all real numbers x such that x ? 5.The domain of f-1 and the range of f are all real numbers x such that x ? 0.
D) f1(x)=x+5f ^ { - 1 } ( x ) = \sqrt { x } + 5 ?
The domain of f and the range of f-1 are all real numbers x such that x ? 0.The domain of f-1 and the range of f are all real numbers x such that x ? 5.
E) f1(x)=x5f ^ { - 1 } ( x ) = \sqrt { x } - 5 ?
The domain of f and the range of f-1 are all real numbers x such that x ? -5.The domain of f-1 and the range of f are all real numbers x such that x ? 0.
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26
Use the functions given by f(x)=18x5f ( x ) = \frac { 1 } { 8 } x - 5 and g(x)= x3 to find (f-1 º f-1)(-5). ?

A)36
B)44
C)40
D)38
E)42
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27
Use the functions given by f(x)= x + 6 and g(x)= 7x - 3 to find g-1 º f-1. ?

A) x37\frac { - x - 3 } { 7 }
B) x+37\frac { x + 3 } { 7 }
C) x37\frac { x - 3 } { 7 }
D) x37\frac { x - 3 } { - 7 }
E) x73\frac { x - 7 } { 3 }
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28
Determine whether the function has an inverse function.If it does,find the inverse function.? h(x)=4x2h ( x ) = - \frac { 4 } { x ^ { 2 } } ?

A) h1(x)=4x2h ^ { - 1 } ( x ) = \frac { 4 } { x ^ { 2 } }
B) h1(x)=x24h ^ { - 1 } ( x ) = - \frac { x ^ { 2 } } { 4 }
C) h1(x)=4x2h ^ { - 1 } ( x ) = - \frac { 4 } { x ^ { 2 } }
D) h1(x)=x24h ^ { - 1 } ( x ) = \frac { x ^ { 2 } } { 4 }
E)No inverse
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29
Use the functions given by f(x)=1125x1f ( x ) = \frac { 1 } { 125 } x - 1 and g(x)= x3 to find (f º g)-1. ?

A) 5x135 \sqrt [ 3 ] { x - 1 }
B) 125x13125 \sqrt [ 3 ] { x - 1 }
C) 5x+135 \sqrt [ 3 ] { x + 1 }
D) 125x+13125 \sqrt [ 3 ] { x + 1 }
E) 5x+15 \sqrt { x + 1 }
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30
Use the functions given by f(x)=164x4f ( x ) = \frac { 1 } { 64 } x - 4 and g(x)= x3 to find g-1 º f-1. ?

A) 4(4x)34 \sqrt [ 3 ] { ( 4 - x ) }
B) 4(x+4)3- 4 \sqrt [ 3 ] { ( x + 4 ) }
C) 4(x4)3- 4 \sqrt [ 3 ] { ( x - 4 ) }
D) 4(x4)34 \sqrt [ 3 ] { ( x - 4 ) }
E) 4(x+4)34 \sqrt [ 3 ] { ( x + 4 ) }
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31
Determine whether the function has an inverse function.If it does,find the inverse function.? f(x)=7x+8f ( x ) = \sqrt { 7 x + 8 } ?

A) f1(x)=x2+87f ^ { - 1 } ( x ) = - \frac { x ^ { 2 } + 8 } { 7 }
B) f1(x)=x287f ^ { - 1 } ( x ) = - \frac { x ^ { 2 } - 8 } { 7 }
C) f1(x)=x287f ^ { - 1 } ( x ) = \frac { x ^ { 2 } - 8 } { 7 }
D) f1(x)=x2+87f ^ { - 1 } ( x ) = \frac { x ^ { 2 } + 8 } { 7 }
E)No Inverse
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32
Determine whether the function has an inverse function.If it does,find the inverse function. ?
F(x)= -2
?

A)f-1(x)= 2
B) f1(x)=12f ^ { - 1 } ( x ) = - \frac { 1 } { 2 }
C) f1(x)=12f ^ { - 1 } ( x ) = \frac { 1 } { 2 }
D)f-1(x)= -2
E)No inverse
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33
Determine whether the function has an inverse function.If it does,find the inverse function.? g(x)=x5g ( x ) = \frac { x } { 5 } ?

A) g1(x)=5xg ^ { - 1 } ( x ) = - 5 x
B) g1(x)=5xg ^ { - 1 } ( x ) = 5 x
C) g1(x)=5xg ^ { - 1 } ( x ) = \frac { 5 } { x }
D) g1(x)=x5g ^ { - 1 } ( x ) = - \frac { x } { 5 }
E)No inverse
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34
Use the functions given by f(x)= x + 2 and g(x)= 2x - 5 to find (f º g)-1. ?

A) x+32\frac { x + 3 } { 2 }
B) x32\frac { x - 3 } { - 2 }
C) x43\frac { x - 4 } { 3 }
D) x32\frac { x - 3 } { 2 }
E) x32\frac { - x - 3 } { 2 }
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35
Restrict the domain of the function f so that the function is one-to-one and has an inverse function.Then find the inverse function f-1.State the domains and ranges of f and f-1. ​
F(x)= |x + 5|

A)f​-1(x)= x - 5 ​
The domain of f and the range of f-1 are all real numbers x such that x ≥ -5.The domain of f-1 and the range of f are all real numbers x such that x ≥ 0.
B)f​-1(x)= x + 5 ​
The domain of f and the range of f-1 are all real numbers x such that x ≥ 0.The domain of f-1 and the range of f are all real numbers x such that x ≥ -5.
C)f​-1(x)= x - 5 ​
The domain of f and the range of f-1 are all real numbers x such that x ≥ 0.The domain of f-1 and the range of f are all real numbers x such that x ≥ 5.
D)f​-1(x)= x + 5 ​
The domain of f and the range of f-1 are all real numbers x such that x ≥ 5.The domain of f-1 and the range of f are all real numbers x such that x ≥ 0.
E)f​-1(x)= x - 5 ​
The domain of f and the range of f-1 are all real numbers x such that x ≥ 5.The domain of f-1 and the range of f are all real numbers x such that x ≥ 0.
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36
?Use the graph of the function f to create a table of values for the given points.Then create a second table that can be used to find f-1. ??  <strong>?Use the graph of the function f to create a table of values for the given points.Then create a second table that can be used to find f<sup>-1</sup>. ??   ?</strong> A)  \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline y & 1 & 4 & 7 & 9 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 8 \\ \hline \end{array} \end{array}  B)  \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline y & 1 & 4 & 7 & 8 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\ \hline \end{array} \end{array}  C)  \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline y & 1 & 4 & 7 & 9 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\ \hline \end{array} \end{array}  D)  \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\ \hline y & 1 & 4 & 7 & 8 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\ \hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\ \hline \end{array} \end{array}  E)  \begin{array}{l} \begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\ \hline y & 1 & 4 & 7 & 8 \\ \hline \end{array}\\\\ \begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\ \hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\ \hline \end{array} \end{array}   ?

A) x1478y1479x1479f1(x)1478\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\\hline y & 1 & 4 & 7 & 9 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\\hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 8 \\\hline\end{array}\end{array}
B) x1479y1478x1478f1(x)1479\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\\hline y & 1 & 4 & 7 & 8 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\\hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\\hline\end{array}\end{array}
C) x1478y1479x1479f1(x)1478\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\\hline y & 1 & 4 & 7 & 9 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\\hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\\hline\end{array}\end{array}
D) x1479y1478x1478f1(x)1479\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\\hline y & 1 & 4 & 7 & 8 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 8 \\\hline f ^ { - 1 } ( x ) & 1 & 4 & 7 & 9 \\\hline\end{array}\end{array}
E) x1479y1478x1479f1(x)1478\begin{array}{l}\begin{array} { | l | l | l | l | l | } \hline x & - 1 & - 4 & - 7 & - 9 \\\hline y & 1 & 4 & 7 & 8 \\\hline\end{array}\\\\\begin{array} { | l | l | l | l | l | } \hline x & 1 & 4 & 7 & 9 \\\hline f ^ { - 1 } ( x ) & - 1 & - 4 & - 7 & - 8 \\\hline\end{array}\end{array}
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37
The function given by y = 0.03x2 + 245.50,0 < x < 100 approximates the exhaust temperature y in degrees Fahrenheit,x where is the percent load for a diesel engine.Find the inverse function. ?

A) y=x+245.500.03y = \frac { x + 245.50 } { - 0.03 }
B) y=x245.500.03y = \sqrt { \frac { x - 245.50 } { 0.03 } }
C) y=x245.500.03y = \frac { x - 245.50 } { 0.03 }
D) y=x+245.500.03y = \sqrt { \frac { x + 245.50 } { 0.03 } }
E) y=x+245.500.03y = \frac { x + 245.50 } { 0.03 }
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38
Determine whether the function has an inverse function.If it does,find the inverse function.? f ( x ) = \left\{ \begin{array} { l } x + 2 , x < 0 \\2 - x , x \geq 0\end{array} \\) ?</strong><div>A) \(f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } 2 + x , x \geq 0 \\x - 2 , x < 0\end{array} \right. .

B) f1(x)={2+x,x0x2,x<0f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } 2 + x , x \geq 0 \\x - 2 , x < 0\end{array} \right.

C) f1(x)={x2,x02+x,x<0f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } x - 2 , x \geq 0 \\2 + x , x < 0\end{array} \right.

D) f1(x)={x+2,x02x,x<0f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } x + 2 , x \geq 0 \\2 - x , x < 0\end{array} \right. .

E)No inverse
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39
Use the functions given by f(x)=18x5f ( x ) = \frac { 1 } { 8 } x - 5 and g(x)= x3 to find (g-1 º f-1)(-5). ?

A)-2
B)0
C)-4
D)2
E)4
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40
Use the functions given by f(x)=18x1f ( x ) = \frac { 1 } { 8 } x - 1 and g(x)= x3 to find (f-1 º g-1)(1). ?

A)14
B)12
C)16
D)20
E)18
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41
Find the inverse of the one-to-one function.? y=18xy = \frac { 1 } { 8 x } ?

A) f1(x)=8xf ^ { - 1 } ( x ) = \frac { 8 } { x }
B) f1(x)=x8f ^ { - 1 } ( x ) = \frac { x } { 8 }
C) f1(x)=8xf ^ { - 1 } ( x ) = 8 x
D) f1(x)=18xf ^ { - 1 } ( x ) = \frac { 1 } { 8 x }
E)inverse does not exist
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42
Find the inverse of the one-to-one function. ?
Y = 3x
?

A) f1(x)=3x2f ^ { - 1 } ( x ) = 3 x ^ { 2 }
B)f -1(x)= 3x
C) f1(x)=x3f ^ { - 1 } ( x ) = \frac { x } { 3 }
D) f1(x)=3xf ^ { - 1 } ( x ) = \frac { 3 } { x }
E)f -1(x)= 9x
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43
Find the inverse of the one-to-one function.

y = 6x

f -1(x)= __________
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44
Restrict the domain of f(x)= x2 + 5 to x ≥ 0.Use a graphing utility to graph the function. ​

A)​ <strong>Restrict the domain of f(x)= x<sup>2</sup> + 5 to x ≥ 0.Use a graphing utility to graph the function. ​</strong> A)​   B)   C)​   D)​   E)
B) <strong>Restrict the domain of f(x)= x<sup>2</sup> + 5 to x ≥ 0.Use a graphing utility to graph the function. ​</strong> A)​   B)   C)​   D)​   E)
C)​ <strong>Restrict the domain of f(x)= x<sup>2</sup> + 5 to x ≥ 0.Use a graphing utility to graph the function. ​</strong> A)​   B)   C)​   D)​   E)
D)​ <strong>Restrict the domain of f(x)= x<sup>2</sup> + 5 to x ≥ 0.Use a graphing utility to graph the function. ​</strong> A)​   B)   C)​   D)​   E)
E) <strong>Restrict the domain of f(x)= x<sup>2</sup> + 5 to x ≥ 0.Use a graphing utility to graph the function. ​</strong> A)​   B)   C)​   D)​   E)
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45
Find the inverse of the one-to-one function. ?
Y = 5x + 9
?

A) f1(x)=x+95f ^ { - 1 } ( x ) = \frac { x + 9 } { 5 }
B) f1(x)=x95f ^ { - 1 } ( x ) = \frac { x - 9 } { 5 }
C) f1(x)=5x9f ^ { - 1 } ( x ) = \frac { 5 } { x - 9 }
D) f1(x)=x59f ^ { - 1 } ( x ) = \frac { x - 5 } { 9 }
E)none of the above
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46
Show algebraically that f and g are inverse functions.
f(x)= 9x + 9 Show algebraically that f and g are inverse functions. f(x)= 9x + 9
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47
Find the inverse of the one-to-one function.

y = 5x + 4

f -1(x)= __________
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48
Consider the functions given by f(x)= x + 3 and f-1(x)= x - 3.Evaluate f(f-1(x))and f-1(f(x))for the indicated values of x.What can you conclude about the functions
x10449f(f1(x))f1(f(x))\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & & & & \\\hline f ^ { - 1 } ( f ( x ) ) & & & & \\\hline\end{array}

A) x10449f(f1(x))10449f1(f(x))10449\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & - 1 & 0 & - 4 & - 49 \\\hline f ^ { - 1 } ( f ( x ) ) & - 1 & 0 & 4 & 49 \\\hline\end{array} We can conclude that, both the functions have the same value for negative variables
B) x10449f(f1(x))10449f1(f(x))10449\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & - 1 & 0 & 4 & 49 \\\hline f ^ { - 1 } ( f ( x ) ) & - 1 & 0 & 4 & 49 \\\hline\end{array} We can conclude that, both the functions have the same value
C) x10449f(f1(x))10449f1(f(x))10449\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & - 1 & 0 & 4 & 49 \\\hline f ^ { - 1 } ( f ( x ) ) & - 1 & 0 & - 4 & - 49 \\\hline\end{array} We can conclude that, both the functions have the same value for negative variables.
D) x10449f(f1(x))10449f1(f(x))10449\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & - 1 & 0 & - 4 & 49 \\\hline f ^ { - 1 } ( f ( x ) ) & - 1 & 0 & 4 & - 49 \\\hline\end{array} We can conclude that, both the functions are opposite of each other.
E) x10449f(f1(x))10449f1(f(x))10449\begin{array} { | l | l | l | l | l | } \hline x & - 1 & 0 & 4 & 49 \\\hline f \left( f ^ { - 1 } ( x ) \right) & - 1 & 0 & 4 & - 49 \\\hline f ^ { - 1 } ( f ( x ) ) & - 1 & 0 & - 4 & 49 \\\hline\end{array}
We can conclude that, both the functions are opposite of each other.
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49
Graph the given function. f(x)= (x - 3)2 <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)

A) <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)
B) <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)
C) <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)
D) <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)
E) <strong>Graph the given function. f(x)= (x - 3)<sup>2</sup>  </strong> A)   B)   C)   D)   E)
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50
Find the inverse of the one-to-one function.​ Find the inverse of the one-to-one function.​   ​ f <sup>-1</sup>(x)= __________
f -1(x)= __________
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51
Show algebraically that f and g are inverse functions. Show algebraically that f and g are inverse functions.   ,x ≥ 8 g(x)= x<sup>2</sup> + 8,x ≥ 0 ,x ≥ 8 g(x)= x2 + 8,x ≥ 0
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52
Determine algebraically whether f and g are inverse functions. f(x)= 5x - 3 g(x)=x+35g ( x ) = \frac { x + 3 } { 5 }

A)Yes,f and g are inverse functions. f(g(x))=f(x+35)=5(x+35)3=x+33=xf ( g ( x ) ) = f \left( \frac { x + 3 } { 5 } \right) = 5 \left( \frac { x + 3 } { 5 } \right) - 3 = x + 3 - 3 = x g(f(x))=g(5x3)=5x3+35=5x5=xg ( f ( x ) ) = g ( 5 x - 3 ) = \frac { 5 x - 3 + 3 } { 5 } = \frac { 5 x } { 5 } = x
B)No,f and g are not inverse functions. f(g(x))=f(x+35)=5(x+35)3=x+33=xf ( g ( x ) ) = f \left( \frac { x + 3 } { 5 } \right) = 5 \left( \frac { x + 3 } { 5 } \right) - 3 = x + 3 - 3 = x g(f(x))=g(5x3)=5x3+35=5x5=xg ( f ( x ) ) = g ( 5 x - 3 ) = \frac { 5 x - 3 + 3 } { 5 } = \frac { 5 x } { 5 } = - x
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53
The function f(x)= x2 - 2 is one-to-one on the domain (x ? 0).Find f -1(x). ?

A) f1(x)=x+2f ^ { - 1 } ( x ) = - \sqrt { x + 2 }
B) f1(x)=1x22f ^ { - 1 } ( x ) = \frac { 1 } { x ^ { 2 } - 2 }
C) f1(x)=x+2f ^ { - 1 } ( x ) = \sqrt { x + 2 }
D) f1(x)=x2f ^ { - 1 } ( x ) = \sqrt { x - 2 }
E)f -1(x)= x2 + 2
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54
Determine whether the function has an inverse function.If it does,find the inverse function. f(x)= x2 + 5

A) f1(x)=x+5,x0f ^ { - 1 } ( x ) = \sqrt { x } + 5 , x \geq 0
B) f1(x)=x5f ^ { - 1 } ( x ) = \sqrt { x - 5 }
C) f1(x)=x5f ^ { - 1 } ( x ) = \sqrt { x } - 5
D) f1(x)=x+5,x5f ^ { - 1 } ( x ) = \sqrt { x + 5 } , x \geq - 5
E)No inverse function exists.
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55
Determine whether the function is one-to- one. ​
Y = 3x

A)No,it isn't one-to-one.
B)Yes,it is one-to-one.
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56
Determine algebraically whether f and g are inverse functions. f(x)=x+6f ( x ) = \sqrt { x + 6 } g(x)= x2 - 6,x ? 0

A)Yes,f and g are inverse functions. f(g(x))=f(x26)=(x26)+6=x2=xf ( g ( x ) ) = f \left( x ^ { 2 } - 6 \right) = \sqrt { \left( x ^ { 2 } - 6 \right) + 6 } = \sqrt { x ^ { 2 } } = x g(f(x))=g(x+6)=(x+6)26=x+66=xg ( f ( x ) ) = g ( \sqrt { x + 6 } ) = ( \sqrt { x + 6 } ) ^ { 2 } - 6 = x + 6 - 6 = x
B)No,f and g are not inverse functions. f(g(x))=f(x26)=(x26)+6=x2=xf ( g ( x ) ) = f \left( x ^ { 2 } - 6 \right) = \sqrt { \left( x ^ { 2 } - 6 \right) + 6 } = \sqrt { x ^ { 2 } } = x g(f(x))=g(x+6)=(x+6)26=x+66=xg ( f ( x ) ) = g ( \sqrt { x + 6 } ) = ( \sqrt { x + 6 } ) ^ { 2 } - 6 = - x + 6 - 6 = - x
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57
?Use the functions given by f(x)=x81f ( x ) = \frac { x } { 8 } - 1 and g(x)= x3 to find the indicated value. (f º g)-1(5)

A)? 387512- \frac { 387 } { 512 }
B)? 2632 \sqrt [ 3 ] { 6 }
C)? 263- 2 \sqrt [ 3 ] { 6 }
D)? 2432 \sqrt [ 3 ] { 4 }
E)?Undefined
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58
Determine whether the function has an inverse function.If it does,find the inverse function. f(x)={8x+13,x<2(x+2)23,x2f ( x ) = \left\{ \begin{array} { l } 8 x + 13 , x < - 2 \\( x + 2 ) ^ { 2 } - 3 , x \geq - 2\end{array} \right.

A) f1(x)={x138,x<2x+32,x2f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } \frac { x - 13 } { 8 } , x < - 2 \\\\\sqrt { x + 3 } - 2 , x \geq - 2\end{array} \right.
B)? f1(x)={x138,x<2x+1,x2f ^ { - 1 } ( x ) = \left\{ \begin{array} { c } \frac { x - 13 } { 8 } , x < - 2 \\\\\sqrt { x + 1 } , x \geq - 2\end{array} \right.
C) f1(x)={x138,x<3x+32,x3f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } \frac { x - 13 } { 8 } , x < - 3 \\\\\sqrt { x + 3 } - 2 , x \geq - 3\end{array} \right.
D) f1(x)={x+138,x<3x+32,x3f ^ { - 1 } ( x ) = \left\{ \begin{array} { l } \frac { x + 13 } { 8 } , x < - 3 \\\\\sqrt { x + 3 } - 2 , x \geq - 3\end{array} \right.
E)No inverse function exists.
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59
Determine whether the function is one-to-one. ​
Y = (x - 5)2;x ≥ 5

A)No,it isn't one-to-one.
B)Yes,it is one-to-one.
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