Question 1

How much charge is stored in a 0.022 ?F capacitor that drops 22 V?&#10;A) 48.4 ?C&#10;B) 0.484 ?C&#10;C) 4.84 ?C&#10;D) 0.0484 ?C

Accepted Answer

0.484 ?C&#10;

Question 2

If a 1 ?F, 2.2 ?F and 0.05 ?F capacitor are connected in series, C_T is less than ________. A) 0.001 ?F B) 0.05 ?F C) 1 ?F D) 2.2 ?F

Accepted Answer

When capacitors are connected in series, the total capacitance is less than the smallest individual capacitor, which is 0.05 ?F in this case.

Question 3

If four 0.022 ?F capacitors are connected in parallel, C_T equals ________. A) 0.049 ?F B) 0.022 ?F C) 0.044 ?F D) 0.088 ?F

Accepted Answer

When capacitors are connected in parallel, their capacitances add up. Therefore, four 0.022 µF capacitors in parallel have a total capacitance of 0.022 µF + 0.022 µF + 0.022 µF + 0.022 µF = 0.088 µF.

Question 4

If a 0.047 ?F, 0.047 ?F and 0.47 ?F capacitor are connected in series across a 25 V source, the total capacitance equals ________ and each 0.047 ?F capacitor drops ________.&#10;A) 0.564 ?F, 1.2 V&#10;B) 0.564 ?F, 11.9 V&#10;C) 0.022 ?F, 11.9 V&#10;D) 0.022 ?F, 25 V

Accepted Answer

The total capacitance (C_total) of capacitors in series is given by the reciprocal of the sum of the reciprocals of the individual capacitances: 1/C_total = 1/C1 + 1/C2 + 1/C3. Using the given values, 1/C_total = 1/0.047 + 1/0.047 + 1/0.47, which simplifies to C_total ≈ 0.022 µF. The voltage drop across each capacitor in a series circuit is proportional to its capacitance. The 0.047 µF capacitors have the same capacitance, so they will have the same voltage drop. Using the formula V = Q/C, where Q is the charge and is the same for all capacitors in series, and knowing the total voltage and total capacitance, we can find the voltage drop across the 0.047 µF capacitors to be approximately 11.9 V.

Question 5

7.07 V_PP is approximately equal to 2.5 V_RMS.

Accepted Answer

The peak-to-peak voltage (V_PP) is the difference between the maximum and minimum voltage values in an alternating current (AC) waveform. The root mean square (RMS) voltage is the square root of the average of the squared voltage values over a period of time. For a sinusoidal waveform, the RMS voltage is equal to the peak voltage divided by the square root of 2. Therefore, 7.07 V_PP is approximately equal to 2.5 V_RMS.

Question 6

Figure 8-2 -Calculate V_R2 in Figure 8-2. A) 4.84 V_P B) 6.84 V_P C) 6.84 V_PP D) 13.15 V_P

Accepted Answer

The correct calculation of V_R2 would result in a value that aligns with the specific parameters and operations defined in the given context, which in this case is option B, indicating a specific numerical value and configuration.

Question 7

Figure 8-2 -What is the approximate peak input voltage to the circuit in Figure 8-2? A) 14.1 V_P B) 20 V_P C) 28.3 V_P D) 10 V_P

Accepted Answer

The peak input voltage is typically calculated as the RMS (root mean square) voltage multiplied by the square root of 2 (approximately 1.414) for a sinusoidal AC signal. If the given RMS voltage is 20V (which seems to be implied by one of the options), multiplying 20V by 1.414 gives approximately 28.3V, indicating that the peak input voltage is around 28.3V.

Question 8

Figure 8-2 -Calculate V_R1 in Figure 8-2. A) 13.2 V_P B) 13.7 V_P C) 6.84 V_P D) 21.4 V_P

Accepted Answer

The answer of Figure 8-2 -Calculate V_R1 in Figure...

Question 9

Figure 8-2 -Find R_T in Figure 8-2. A) 4.7 k? B) 4.77 k? C) 6.2 k? D) 1.13 k?

Accepted Answer

The answer of Figure 8-2 -Find R_T in Figure...

Question 10

Figure 8-2 -Calculate I_T in Figure 8-2. A) 9.12 mA_PP B) 4.55 mA_PP C) 3.22 mA_PP D) 6.44 mA_PP

Accepted Answer

I_T = I₁ + I₂ = 4.55 mA_PP + 4.55 mA_PP = 9.12 mA_PP

Question 11

If a 10 k? resistor carries 5 mA_RMS of current, its voltage drop equals ________. A) 7.07 V_RMS B) 70.7 V_RMS C) 5 V_RMS D) 50 V_RMS

Accepted Answer

The answer of If a 10 k? resistor carries 5...

Question 12

In a two-resistor series circuit V_R1 = 6.5 V_RMS and V_R2 = 3.2 V_RMS. The source voltage is ________. A) 13.7 V_P B) 9.19 V_P C) 9.7 V_P D) 4.53 V_P

Accepted Answer

The answer of In a two-resistor series circuit V_R1 =...

Question 13

A formula for V_RMS is ________. A) 2.8 × V_P B) 2 × V_P C) 0.707 × V_PP D) 0.707 × V_P

Accepted Answer

The answer of A formula for V_RMS is ________. A) 2.8...

Question 14

A 12 V_P sine wave equals ________. A) 7.64 V_AVG B) 24 V_PP C) 8.48 V_RMS D) all of these

Accepted Answer

The answer of A 12 V_P sine wave equals ________. A)...

Question 15

The formula to convert degrees to radians is:&#10;A) radians =   &#215; degrees.&#10;B) degrees =   &#215; radians.&#10;C) 180&#176; = ? radians.&#10;D) all of these.

Accepted Answer

The answer of The formula to convert degrees to radians...

Deck 4: Capacitors, Introduction to Alternating Current and Voltage