Deck 15: Process Improvement Using Control Charts

ملء الشاشة (f)
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سؤال
A sequence of steadily decreasing points on a control chart is called run down.
استخدم زر المسافة أو
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لقلب البطاقة.
سؤال
For a given control chart,zone boundaries consist of the UCL and LCL.
سؤال
Unusual sources of variation that can be attributed to specific causes are called the common causes of process variation.
سؤال
Periodic sampling is observing the output of a process at random intervals.
سؤال
A goal of statistical process control is continuous process improvement.
سؤال
A cause-and-effect diagram enumerates the potential causes of an undesirable effect on the process to discover sources of process variation and to identify opportunities for process improvement.
سؤال
When using When using   and R charts to analyze and improve a process,first,the   chart is analyzed and the necessary action(s)to correct assignable causes of variation is (are)taken before the R chart is analyzed.<div style=padding-top: 35px> and R charts to analyze and improve a process,first,the When using   and R charts to analyze and improve a process,first,the   chart is analyzed and the necessary action(s)to correct assignable causes of variation is (are)taken before the R chart is analyzed.<div style=padding-top: 35px> chart is analyzed and the necessary action(s)to correct assignable causes of variation is (are)taken before the R chart is analyzed.
سؤال
Process leeway is the distance between natural tolerance limits and control limits.
سؤال
Sigma level capability is the number of estimated process standard deviations between the estimated process mean and the specification limit closest to the estimated process mean.
سؤال
If a process is stable and in statistical control,it is not influenced by assignable causes of variation.
سؤال
How well the design of the product meets and exceeds the needs and expectations of the customers is called the quality of performance.
سؤال
If a process is only influenced by common causes of variation,we can state that the process is in statistical control.
سؤال
A control chart is a graph whose purpose is to detect assignable causes of variation in a process.
سؤال
A p chart is a control chart on which the proportions of nonconforming units are plotted versus time.
سؤال
An An   chart is a control chart on which individual process measurements are plotted versus time.<div style=padding-top: 35px> chart is a control chart on which individual process measurements are plotted versus time.
سؤال
How well a process is able to meet the requirements set forth by the process design is called the quality of design.
سؤال
Reducing common causes of variation usually requires action by management.
سؤال
Control charts are used to reduce common causes of variation.
سؤال
If a manufacturing process is in statistical control,it means that the process is capable of producing products that meet the needs of the customers.
سؤال
A range chart is a control chart on which ranges between individual process measurements within a subgroup are plotted.
سؤال
The natural tolerance limits for a normally distributed process that is in statistical control:

A)Extend beyond the specification limits when a process is capable.
B)Are within the specification limits when a process is capable.
C)Contain approximately 99.73 percent of the individual process measurements.
D)Both are within the specification limits when a process is capable and contain approximately 99.73 percent of the individual process measurements are correct.
E)Both extend beyond the specification limits when a process is capable and contain approximately 99.73 percent of the individual process measurements are correct.
سؤال
If a control chart is used correctly,and the necessary corrective actions are taken,as the control limits get ____________,the potential quality of the product _____________.

A)Looser,increases
B)Tighter,decreases
C)Tighter,increases
D)None of these
سؤال
Rational subgrouping allows us to detect changes ____________ subgroups.

A)Within
B)Between
C)In the sizes of
D)None of these
سؤال
When a process is influenced only by common causes of variation:

A)The process may also be influenced by assignable causes of variation.
B)Many plot points on a control chart will be outside the control limits.
C)The process is always capable of meeting customer requirements.
D)The process is in statistical control.
E)The process is never capable of meeting customer requirements.
سؤال
If the ________ limits are within the ________ limits,then it can be concluded that the process is __________.

A)Specification,natural,capable
B)Natural,specification,stable
C)Specification,natural,stable
D)Natural,specification,capable
سؤال
Observing the output of a process at fixed time intervals is referred to as ___________ sampling.

A)Consecutive
B)Random
C)Fixed
D)Periodic
سؤال
Which of the following control charts is designed to control the proportion of nonconforming units?

A)p chart
B) <strong>Which of the following control charts is designed to control the proportion of nonconforming units?</strong> A)p chart B)   C)R chart <div style=padding-top: 35px>
C)R chart
سؤال
How well a product or service performs in the marketplace is called:

A)Process capability.
B)Quality of conformance.
C)Quality of performance.
D)Quality of design.
E)Process control.
سؤال
A(n)_______ chart monitors the number of nonconforming units in a subgroup.

A) <strong>A(n)_______ chart monitors the number of nonconforming units in a subgroup.</strong> A)   B)R C)C D)p <div style=padding-top: 35px>
B)R
C)C
D)p
سؤال
When employing measurement data to study a process,the ____________ monitors the process mean.

A) <strong>When employing measurement data to study a process,the ____________ monitors the process mean.</strong> A)   B)p-bar chart C)R chart D)Natural tolerance E)Pattern analysis <div style=padding-top: 35px>
B)p-bar chart
C)R chart
D)Natural tolerance
E)Pattern analysis
سؤال
How well the design of a product or service meets and exceeds the needs and expectations of the customer is called:

A)Process capability.
B)Quality of conformance.
C)Quality of performance.
D)Quality of design.
E)Process control.
سؤال
If a company is using an If a company is using an   chart for a given process with measurement data,it is generally not important or necessary to use an R chart or s chart.<div style=padding-top: 35px> chart for a given process with measurement data,it is generally not important or necessary to use an R chart or s chart.
سؤال
When employing measurement data to study a process,the __________ monitors the process variation.

A) <strong>When employing measurement data to study a process,the __________ monitors the process variation.</strong> A)   B)R chart C)p chart D)Natural tolerance E)Pattern analysis <div style=padding-top: 35px>
B)R chart
C)p chart
D)Natural tolerance
E)Pattern analysis
سؤال
In 25 samples of 100 units each,75 units were found to be defective.Find the appropriate UCL and LCL for the p chart.

A)0 to .0642
B)0 to .0828
C)0 to .0812
D).0129 to .0471
E)0 to .1324
سؤال
In a manufacturing process,if the limits for a control chart are set too _____________,the risk of unnecessarily tampering with the process ____________.

A)Tight,increases
B)Loose,increases
C)Tight,decreases
D)None of these
سؤال
Common causes of variation represent the inherent variability of a given process.
سؤال
How well a process is able to meet the requirements set forth by the process design is called:

A)Process leeway.
B)Quality of conformance.
C)Quality of performance.
D)Quality of design.
سؤال
If the process variability steadily increases,we would observe:

A)An alternating pattern of a high value followed by a low value on the R chart.
B)An upward trend on the R chart.
C)A downward trend on the R chart.
D)A increasing gradual funnel pattern on the R chart.
E)A decreasing gradual funnel pattern on the R chart.
سؤال
In a manufacturing process,if the limits for a control chart are set too _____________,the risk of not investigating a special cause of variation and possibly not taking a corrective action ____________.

A)Tight,increases
B)Loose,increases
C)Loose,decreases
D)None of these
سؤال
Common causes of process variation:

A)Are sources of unusual process variation.
B)Usually must be remedied by management.
C)Usually must be remedied by local supervision.
D)Always exist together with assignable causes of variation.
E)Can never be remedied or reduced.
سؤال
A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Calculate the control limits for the   chart.</strong> A).99781 to 1.00219 B).99801 to 1.00238 C).99830 to 1.00713 D).99847 to 1.00193 E).995 to 1.005 <div style=padding-top: 35px> = 1.0002 inches, <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Calculate the control limits for the   chart.</strong> A).99781 to 1.00219 B).99801 to 1.00238 C).99830 to 1.00713 D).99847 to 1.00193 E).995 to 1.005 <div style=padding-top: 35px> = .003 inches,and subgroup size of 5.Calculate the control limits for the <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Calculate the control limits for the   chart.</strong> A).99781 to 1.00219 B).99801 to 1.00238 C).99830 to 1.00713 D).99847 to 1.00193 E).995 to 1.005 <div style=padding-top: 35px> chart.

A).99781 to 1.00219
B).99801 to 1.00238
C).99830 to 1.00713
D).99847 to 1.00193
E).995 to 1.005
سؤال
For a manufacturing process, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the natural tolerance limits for this process.</strong> A)[9.526,10.474] B)[9.510,10.490] C)[9.484,10.516] D)[9.807,10.193] E)[9.769,10.231] <div style=padding-top: 35px> = 10 inches, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the natural tolerance limits for this process.</strong> A)[9.526,10.474] B)[9.510,10.490] C)[9.484,10.516] D)[9.807,10.193] E)[9.769,10.231] <div style=padding-top: 35px> = .4 inches,and the subgroup sample size is 6 units.Calculate the natural tolerance limits for this process.

A)[9.526,10.474]
B)[9.510,10.490]
C)[9.484,10.516]
D)[9.807,10.193]
E)[9.769,10.231]
سؤال
A sequence of steadily increasing plot points on a control chart is referred to as ___________.

A)funneling
B)a run up
C)a cycle
D)out of control
سؤال
A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.What are the natural tolerance limits for this process? Is the process capable?</strong> A).99847 to 1.00193,yes B).99847 to 1.00193,no C).99633 to 1.004,yes D).99633 to 1.004,no E).995 to 1.005,yes <div style=padding-top: 35px> = 1.0002 inches, <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.What are the natural tolerance limits for this process? Is the process capable?</strong> A).99847 to 1.00193,yes B).99847 to 1.00193,no C).99633 to 1.004,yes D).99633 to 1.004,no E).995 to 1.005,yes <div style=padding-top: 35px> = .003 inches,and subgroup size of 5.What are the natural tolerance limits for this process? Is the process capable?

A).99847 to 1.00193,yes
B).99847 to 1.00193,no
C).99633 to 1.004,yes
D).99633 to 1.004,no
E).995 to 1.005,yes
سؤال
A ___________ is a set of process observations that are examined for the purpose of constructing control charts.

A)Subgroup
B)Sample
C)Zone
D)List of common causes
سؤال
A(n)____________ process has the ability to produce products or services that meet customer requirements.

A)in-control
B)assignable
C)capable
D)statistical
سؤال
Sources of process variations that are inherent to the process design are called ___________ causes of variation.

A)common
B)assignable
C)unusual
D)expected
سؤال
The distance between natural tolerance limits and customer specifications is called ____________.

A)process leeway
B)sigma level
C)control limits
D)a zone
سؤال
For a manufacturing process, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the R chart.</strong> A)0 and .846 B)0 and .802 C)0 and .77 D)0 and 1.0 E)-.09 and .89 <div style=padding-top: 35px> = 10 inches, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the R chart.</strong> A)0 and .846 B)0 and .802 C)0 and .77 D)0 and 1.0 E)-.09 and .89 <div style=padding-top: 35px> = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the R chart.

A)0 and .846
B)0 and .802
C)0 and .77
D)0 and 1.0
E)-.09 and .89
سؤال
If a control chart is used correctly and the necessary corrective actions are taken,then as the control limits get close to each other,the potential quality of the product _____________.

A)decreases
B)increases
C)stays the same
D)fluctuates
سؤال
A control chart on which subgroup ranges are plotted versus time is a(n)_____ chart.

A) <strong>A control chart on which subgroup ranges are plotted versus time is a(n)_____ chart.</strong> A)   B)R C)p D)C <div style=padding-top: 35px>
B)R
C)p
D)C
سؤال
A systematic method for analyzing process data in which we monitor process variation is called ______________.

A)control charting
B)sigma level capability
C)statistical process control
D)rational subgrouping
سؤال
A control chart on which the proportions of nonconforming units in subgroups of size n are plotted versus time is a(n)_____ chart.

A) <strong>A control chart on which the proportions of nonconforming units in subgroups of size n are plotted versus time is a(n)_____ chart.</strong> A)   B)R C)p D)C <div style=padding-top: 35px>
B)R
C)p
D)C
سؤال
A control chart on which subgroup means are plotted versus time is a(n)_________ chart.

A) <strong>A control chart on which subgroup means are plotted versus time is a(n)_________ chart.</strong> A)   B)R C)p D)C <div style=padding-top: 35px>
B)R
C)p
D)C
سؤال
A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.What is the sigma level capability for this process?</strong> A)3.0 B)3.72 C)1.6 D)1.0 E)2.72 <div style=padding-top: 35px> = 1.0002 inches, <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.What is the sigma level capability for this process?</strong> A)3.0 B)3.72 C)1.6 D)1.0 E)2.72 <div style=padding-top: 35px> = .003 inches,and subgroup size of 5.What is the sigma level capability for this process?

A)3.0
B)3.72
C)1.6
D)1.0
E)2.72
سؤال
___________ causes of variation may be remedied by local supervision.

A)Common
B)Assignable
C)Usual
D)Expected
سؤال
A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Calculate the estimated proportion of out-of-specification sleeve inside diameters.</strong> A).0471 B).0217 C).0001 D).4783 E).0139 <div style=padding-top: 35px> = 1.0002 inches, <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Calculate the estimated proportion of out-of-specification sleeve inside diameters.</strong> A).0471 B).0217 C).0001 D).4783 E).0139 <div style=padding-top: 35px> = .003 inches,and subgroup size of 5.Calculate the estimated proportion of out-of-specification sleeve inside diameters.

A).0471
B).0217
C).0001
D).4783
E).0139
سؤال
A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Determine the estimated number of standard deviations of process leeway.</strong> A)3 B)1.667 C)3.72 D)1.443 E).72 <div style=padding-top: 35px> = 1.0002 inches, <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Determine the estimated number of standard deviations of process leeway.</strong> A)3 B)1.667 C)3.72 D)1.443 E).72 <div style=padding-top: 35px> = .003 inches,and subgroup size of 5.Determine the estimated number of standard deviations of process leeway.

A)3
B)1.667
C)3.72
D)1.443
E).72
سؤال
For a manufacturing process, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the   chart.</strong> A)9.526 and 10.474 B)9.769 and 10.231 C)9.807 and 10.193 D)9.484 and 10.516 E)8.80 and 11.20 <div style=padding-top: 35px> = 10 inches, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the   chart.</strong> A)9.526 and 10.474 B)9.769 and 10.231 C)9.807 and 10.193 D)9.484 and 10.516 E)8.80 and 11.20 <div style=padding-top: 35px> = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the   chart.</strong> A)9.526 and 10.474 B)9.769 and 10.231 C)9.807 and 10.193 D)9.484 and 10.516 E)8.80 and 11.20 <div style=padding-top: 35px> chart.

A)9.526 and 10.474
B)9.769 and 10.231
C)9.807 and 10.193
D)9.484 and 10.516
E)8.80 and 11.20
سؤال
Auxiliary lines drawn on a control chart for accomplishing pattern analysis are called ___________ boundaries.

A)sigma
B)range
C)zone
D)mean
سؤال
In 20 samples,there are 80 units defective.If each sample consists of 100 units,find the appropriate UCL and the LCL for the p chart.

A)[.0269,.0531]
B)[.0204,.0596]
C)[.0380,.0420]
D)[0,.0988]
سؤال
How well a process is able to meet the requirements set forth by the process design is called the quality of _____________.

A)performance
B)conformance
C)design
D)control
سؤال
If <strong>If   = 5.2,   = .3,and n = 4,calculate the natural tolerance limits.</strong> A)[5.054,5.346] B)[4.3,6.1] C)[4.806,5.594] D)[4.763,5.637] <div style=padding-top: 35px> = 5.2, <strong>If   = 5.2,   = .3,and n = 4,calculate the natural tolerance limits.</strong> A)[5.054,5.346] B)[4.3,6.1] C)[4.806,5.594] D)[4.763,5.637] <div style=padding-top: 35px> = .3,and n = 4,calculate the natural tolerance limits.

A)[5.054,5.346]
B)[4.3,6.1]
C)[4.806,5.594]
D)[4.763,5.637]
سؤال
The number of estimated process standard deviations between <strong>The number of estimated process standard deviations between   and the closest specification limit is the _____________ of the process.</strong> A)sigma level capability B)leeway C)mean D)capability <div style=padding-top: 35px> and the closest specification limit is the _____________ of the process.

A)sigma level capability
B)leeway
C)mean
D)capability
سؤال
If <strong>If   = 5.2,   = .3,and n = 4,and if the specifications are [4.6,5.8],is the process capable?</strong> A)Yes B)No <div style=padding-top: 35px> = 5.2, <strong>If   = 5.2,   = .3,and n = 4,and if the specifications are [4.6,5.8],is the process capable?</strong> A)Yes B)No <div style=padding-top: 35px> = .3,and n = 4,and if the specifications are [4.6,5.8],is the process capable?

A)Yes
B)No
سؤال
If <strong>If   and R charts are used to control a manufacturing process,an ______ chart is analyzed first and brought into a state of statistical control before preparing the _______ chart.</strong> A)R,   B)   <div style=padding-top: 35px> and R charts are used to control a manufacturing process,an ______ chart is analyzed first and brought into a state of statistical control before preparing the _______ chart.

A)R, <strong>If   and R charts are used to control a manufacturing process,an ______ chart is analyzed first and brought into a state of statistical control before preparing the _______ chart.</strong> A)R,   B)   <div style=padding-top: 35px>
B) <strong>If   and R charts are used to control a manufacturing process,an ______ chart is analyzed first and brought into a state of statistical control before preparing the _______ chart.</strong> A)R,   B)   <div style=padding-top: 35px>
سؤال
If <strong>If   = 2.0144,   = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the R chart.</strong> A)[.045,.1498] B)[.0972,.2055] C)[0,.2055] D)[0.2,114] <div style=padding-top: 35px> = 2.0144, <strong>If   = 2.0144,   = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the R chart.</strong> A)[.045,.1498] B)[.0972,.2055] C)[0,.2055] D)[0.2,114] <div style=padding-top: 35px> = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the R chart.

A)[.045,.1498]
B)[.0972,.2055]
C)[0,.2055]
D)[0.2,114]
سؤال
_________ is the set of international standards on quality management and quality assurance systems.It establishes processes for assuring that goods and services offered by the company meet a consistent level of quality acceptable to customers.

A)Control Charting
B)SQC
C)ISO 9000
D)ASQC
سؤال
If <strong>If   = 2.0144,   = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the   chart.</strong> A)[1.999,2.029] B)[1.958,2.071] C)[1.917,2.112] D)[1.437,2.591] <div style=padding-top: 35px> = 2.0144, <strong>If   = 2.0144,   = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the   chart.</strong> A)[1.999,2.029] B)[1.958,2.071] C)[1.917,2.112] D)[1.437,2.591] <div style=padding-top: 35px> = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the <strong>If   = 2.0144,   = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the   chart.</strong> A)[1.999,2.029] B)[1.958,2.071] C)[1.917,2.112] D)[1.437,2.591] <div style=padding-top: 35px> chart.

A)[1.999,2.029]
B)[1.958,2.071]
C)[1.917,2.112]
D)[1.437,2.591]
سؤال
Unusual sources of process variation that can be attributed to specific reasons are called ____________ causes of variation.

A)common
B)assignable
C)usual
D)expected
سؤال
If 20 samples of size 7 are drawn,with <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what is the A-B upper boundary for the   chart?</strong> A)35.697 B)34.908 C)34.347 D)34.008 <div style=padding-top: 35px> = 33.33 and <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what is the A-B upper boundary for the   chart?</strong> A)35.697 B)34.908 C)34.347 D)34.008 <div style=padding-top: 35px> = 5.65,what is the A-B upper boundary for the <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what is the A-B upper boundary for the   chart?</strong> A)35.697 B)34.908 C)34.347 D)34.008 <div style=padding-top: 35px> chart?

A)35.697
B)34.908
C)34.347
D)34.008
سؤال
From 20 samples of size 100,a total of 80 units are defective.What is the centerline for the p chart?

A).04
B).4
C).8
D).08
سؤال
If <strong>If   = 16.1,   = .03,and n = 6,and if the specifications are [15.9,16.3],is the process capable?</strong> A)Yes B)No <div style=padding-top: 35px> = 16.1, <strong>If   = 16.1,   = .03,and n = 6,and if the specifications are [15.9,16.3],is the process capable?</strong> A)Yes B)No <div style=padding-top: 35px> = .03,and n = 6,and if the specifications are [15.9,16.3],is the process capable?

A)Yes
B)No
سؤال
If <strong>If   = .0139 and 25 shipments of 20 items each were examined,what are the UCL and the LCL for the p chart?</strong> A)[.0118,.0159] B)[0,.0401] C)[.008,.0198] D)[0,.0924] <div style=padding-top: 35px> = .0139 and 25 shipments of 20 items each were examined,what are the UCL and the LCL for the p chart?

A)[.0118,.0159]
B)[0,.0401]
C)[.008,.0198]
D)[0,.0924]
سؤال
A unit that fails to meet specifications is called a _____________ unit.

A)conforming
B)capable
C)defective
D)common cause
سؤال
If 20 samples of size 7 are drawn,with <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what are the LCL and UCL for the R chart?</strong> A)[2.345,8.955] B)[.076,1.924] C)[.415,1.585] D)[.429,10.871] <div style=padding-top: 35px> = 33.33 and <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what are the LCL and UCL for the R chart?</strong> A)[2.345,8.955] B)[.076,1.924] C)[.415,1.585] D)[.429,10.871] <div style=padding-top: 35px> = 5.65,what are the LCL and UCL for the R chart?

A)[2.345,8.955]
B)[.076,1.924]
C)[.415,1.585]
D)[.429,10.871]
سؤال
If 20 samples of size 7 are drawn,with <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what are the LCL and the UCL for the   chart?</strong> A)[32.313,34.347] B)[30.963,35.697] C)[27.68,38,98] D)[32.911,33.749] <div style=padding-top: 35px> = 33.33 and <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what are the LCL and the UCL for the   chart?</strong> A)[32.313,34.347] B)[30.963,35.697] C)[27.68,38,98] D)[32.911,33.749] <div style=padding-top: 35px> = 5.65,what are the LCL and the UCL for the <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what are the LCL and the UCL for the   chart?</strong> A)[32.313,34.347] B)[30.963,35.697] C)[27.68,38,98] D)[32.911,33.749] <div style=padding-top: 35px> chart?

A)[32.313,34.347]
B)[30.963,35.697]
C)[27.68,38,98]
D)[32.911,33.749]
سؤال
How well a product or a service performs in the marketplace is called the quality of ______________.

A)performance
B)conformance
C)design
D)control
سؤال
If <strong>If   = 16.1,   = .03,and n = 6,calculate the natural tolerance limits.</strong> A)[16.065,16.135] B)[16.088,16.112] C)[15.745,16.455] D)[16.055,16.145] <div style=padding-top: 35px> = 16.1, <strong>If   = 16.1,   = .03,and n = 6,calculate the natural tolerance limits.</strong> A)[16.065,16.135] B)[16.088,16.112] C)[15.745,16.455] D)[16.055,16.145] <div style=padding-top: 35px> = .03,and n = 6,calculate the natural tolerance limits.

A)[16.065,16.135]
B)[16.088,16.112]
C)[15.745,16.455]
D)[16.055,16.145]
سؤال
Assume that 25 samples of 50 each are taken and the total number of defectives is 34.Calculate <strong>Assume that 25 samples of 50 each are taken and the total number of defectives is 34.Calculate  </strong> A).680 B).453 C).816 D).0272 <div style=padding-top: 35px>

A).680
B).453
C).816
D).0272
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Deck 15: Process Improvement Using Control Charts
1
A sequence of steadily decreasing points on a control chart is called run down.
True
2
For a given control chart,zone boundaries consist of the UCL and LCL.
False
3
Unusual sources of variation that can be attributed to specific causes are called the common causes of process variation.
False
4
Periodic sampling is observing the output of a process at random intervals.
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5
A goal of statistical process control is continuous process improvement.
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6
A cause-and-effect diagram enumerates the potential causes of an undesirable effect on the process to discover sources of process variation and to identify opportunities for process improvement.
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7
When using When using   and R charts to analyze and improve a process,first,the   chart is analyzed and the necessary action(s)to correct assignable causes of variation is (are)taken before the R chart is analyzed. and R charts to analyze and improve a process,first,the When using   and R charts to analyze and improve a process,first,the   chart is analyzed and the necessary action(s)to correct assignable causes of variation is (are)taken before the R chart is analyzed. chart is analyzed and the necessary action(s)to correct assignable causes of variation is (are)taken before the R chart is analyzed.
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8
Process leeway is the distance between natural tolerance limits and control limits.
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9
Sigma level capability is the number of estimated process standard deviations between the estimated process mean and the specification limit closest to the estimated process mean.
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10
If a process is stable and in statistical control,it is not influenced by assignable causes of variation.
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11
How well the design of the product meets and exceeds the needs and expectations of the customers is called the quality of performance.
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12
If a process is only influenced by common causes of variation,we can state that the process is in statistical control.
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13
A control chart is a graph whose purpose is to detect assignable causes of variation in a process.
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14
A p chart is a control chart on which the proportions of nonconforming units are plotted versus time.
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15
An An   chart is a control chart on which individual process measurements are plotted versus time. chart is a control chart on which individual process measurements are plotted versus time.
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16
How well a process is able to meet the requirements set forth by the process design is called the quality of design.
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17
Reducing common causes of variation usually requires action by management.
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18
Control charts are used to reduce common causes of variation.
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19
If a manufacturing process is in statistical control,it means that the process is capable of producing products that meet the needs of the customers.
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20
A range chart is a control chart on which ranges between individual process measurements within a subgroup are plotted.
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21
The natural tolerance limits for a normally distributed process that is in statistical control:

A)Extend beyond the specification limits when a process is capable.
B)Are within the specification limits when a process is capable.
C)Contain approximately 99.73 percent of the individual process measurements.
D)Both are within the specification limits when a process is capable and contain approximately 99.73 percent of the individual process measurements are correct.
E)Both extend beyond the specification limits when a process is capable and contain approximately 99.73 percent of the individual process measurements are correct.
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22
If a control chart is used correctly,and the necessary corrective actions are taken,as the control limits get ____________,the potential quality of the product _____________.

A)Looser,increases
B)Tighter,decreases
C)Tighter,increases
D)None of these
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23
Rational subgrouping allows us to detect changes ____________ subgroups.

A)Within
B)Between
C)In the sizes of
D)None of these
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24
When a process is influenced only by common causes of variation:

A)The process may also be influenced by assignable causes of variation.
B)Many plot points on a control chart will be outside the control limits.
C)The process is always capable of meeting customer requirements.
D)The process is in statistical control.
E)The process is never capable of meeting customer requirements.
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25
If the ________ limits are within the ________ limits,then it can be concluded that the process is __________.

A)Specification,natural,capable
B)Natural,specification,stable
C)Specification,natural,stable
D)Natural,specification,capable
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26
Observing the output of a process at fixed time intervals is referred to as ___________ sampling.

A)Consecutive
B)Random
C)Fixed
D)Periodic
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27
Which of the following control charts is designed to control the proportion of nonconforming units?

A)p chart
B) <strong>Which of the following control charts is designed to control the proportion of nonconforming units?</strong> A)p chart B)   C)R chart
C)R chart
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28
How well a product or service performs in the marketplace is called:

A)Process capability.
B)Quality of conformance.
C)Quality of performance.
D)Quality of design.
E)Process control.
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29
A(n)_______ chart monitors the number of nonconforming units in a subgroup.

A) <strong>A(n)_______ chart monitors the number of nonconforming units in a subgroup.</strong> A)   B)R C)C D)p
B)R
C)C
D)p
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30
When employing measurement data to study a process,the ____________ monitors the process mean.

A) <strong>When employing measurement data to study a process,the ____________ monitors the process mean.</strong> A)   B)p-bar chart C)R chart D)Natural tolerance E)Pattern analysis
B)p-bar chart
C)R chart
D)Natural tolerance
E)Pattern analysis
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31
How well the design of a product or service meets and exceeds the needs and expectations of the customer is called:

A)Process capability.
B)Quality of conformance.
C)Quality of performance.
D)Quality of design.
E)Process control.
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32
If a company is using an If a company is using an   chart for a given process with measurement data,it is generally not important or necessary to use an R chart or s chart. chart for a given process with measurement data,it is generally not important or necessary to use an R chart or s chart.
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33
When employing measurement data to study a process,the __________ monitors the process variation.

A) <strong>When employing measurement data to study a process,the __________ monitors the process variation.</strong> A)   B)R chart C)p chart D)Natural tolerance E)Pattern analysis
B)R chart
C)p chart
D)Natural tolerance
E)Pattern analysis
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34
In 25 samples of 100 units each,75 units were found to be defective.Find the appropriate UCL and LCL for the p chart.

A)0 to .0642
B)0 to .0828
C)0 to .0812
D).0129 to .0471
E)0 to .1324
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35
In a manufacturing process,if the limits for a control chart are set too _____________,the risk of unnecessarily tampering with the process ____________.

A)Tight,increases
B)Loose,increases
C)Tight,decreases
D)None of these
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36
Common causes of variation represent the inherent variability of a given process.
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37
How well a process is able to meet the requirements set forth by the process design is called:

A)Process leeway.
B)Quality of conformance.
C)Quality of performance.
D)Quality of design.
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38
If the process variability steadily increases,we would observe:

A)An alternating pattern of a high value followed by a low value on the R chart.
B)An upward trend on the R chart.
C)A downward trend on the R chart.
D)A increasing gradual funnel pattern on the R chart.
E)A decreasing gradual funnel pattern on the R chart.
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39
In a manufacturing process,if the limits for a control chart are set too _____________,the risk of not investigating a special cause of variation and possibly not taking a corrective action ____________.

A)Tight,increases
B)Loose,increases
C)Loose,decreases
D)None of these
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40
Common causes of process variation:

A)Are sources of unusual process variation.
B)Usually must be remedied by management.
C)Usually must be remedied by local supervision.
D)Always exist together with assignable causes of variation.
E)Can never be remedied or reduced.
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41
A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Calculate the control limits for the   chart.</strong> A).99781 to 1.00219 B).99801 to 1.00238 C).99830 to 1.00713 D).99847 to 1.00193 E).995 to 1.005 = 1.0002 inches, <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Calculate the control limits for the   chart.</strong> A).99781 to 1.00219 B).99801 to 1.00238 C).99830 to 1.00713 D).99847 to 1.00193 E).995 to 1.005 = .003 inches,and subgroup size of 5.Calculate the control limits for the <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Calculate the control limits for the   chart.</strong> A).99781 to 1.00219 B).99801 to 1.00238 C).99830 to 1.00713 D).99847 to 1.00193 E).995 to 1.005 chart.

A).99781 to 1.00219
B).99801 to 1.00238
C).99830 to 1.00713
D).99847 to 1.00193
E).995 to 1.005
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42
For a manufacturing process, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the natural tolerance limits for this process.</strong> A)[9.526,10.474] B)[9.510,10.490] C)[9.484,10.516] D)[9.807,10.193] E)[9.769,10.231] = 10 inches, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the natural tolerance limits for this process.</strong> A)[9.526,10.474] B)[9.510,10.490] C)[9.484,10.516] D)[9.807,10.193] E)[9.769,10.231] = .4 inches,and the subgroup sample size is 6 units.Calculate the natural tolerance limits for this process.

A)[9.526,10.474]
B)[9.510,10.490]
C)[9.484,10.516]
D)[9.807,10.193]
E)[9.769,10.231]
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43
A sequence of steadily increasing plot points on a control chart is referred to as ___________.

A)funneling
B)a run up
C)a cycle
D)out of control
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44
A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.What are the natural tolerance limits for this process? Is the process capable?</strong> A).99847 to 1.00193,yes B).99847 to 1.00193,no C).99633 to 1.004,yes D).99633 to 1.004,no E).995 to 1.005,yes = 1.0002 inches, <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.What are the natural tolerance limits for this process? Is the process capable?</strong> A).99847 to 1.00193,yes B).99847 to 1.00193,no C).99633 to 1.004,yes D).99633 to 1.004,no E).995 to 1.005,yes = .003 inches,and subgroup size of 5.What are the natural tolerance limits for this process? Is the process capable?

A).99847 to 1.00193,yes
B).99847 to 1.00193,no
C).99633 to 1.004,yes
D).99633 to 1.004,no
E).995 to 1.005,yes
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45
A ___________ is a set of process observations that are examined for the purpose of constructing control charts.

A)Subgroup
B)Sample
C)Zone
D)List of common causes
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46
A(n)____________ process has the ability to produce products or services that meet customer requirements.

A)in-control
B)assignable
C)capable
D)statistical
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47
Sources of process variations that are inherent to the process design are called ___________ causes of variation.

A)common
B)assignable
C)unusual
D)expected
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48
The distance between natural tolerance limits and customer specifications is called ____________.

A)process leeway
B)sigma level
C)control limits
D)a zone
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49
For a manufacturing process, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the R chart.</strong> A)0 and .846 B)0 and .802 C)0 and .77 D)0 and 1.0 E)-.09 and .89 = 10 inches, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the R chart.</strong> A)0 and .846 B)0 and .802 C)0 and .77 D)0 and 1.0 E)-.09 and .89 = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the R chart.

A)0 and .846
B)0 and .802
C)0 and .77
D)0 and 1.0
E)-.09 and .89
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50
If a control chart is used correctly and the necessary corrective actions are taken,then as the control limits get close to each other,the potential quality of the product _____________.

A)decreases
B)increases
C)stays the same
D)fluctuates
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51
A control chart on which subgroup ranges are plotted versus time is a(n)_____ chart.

A) <strong>A control chart on which subgroup ranges are plotted versus time is a(n)_____ chart.</strong> A)   B)R C)p D)C
B)R
C)p
D)C
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52
A systematic method for analyzing process data in which we monitor process variation is called ______________.

A)control charting
B)sigma level capability
C)statistical process control
D)rational subgrouping
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53
A control chart on which the proportions of nonconforming units in subgroups of size n are plotted versus time is a(n)_____ chart.

A) <strong>A control chart on which the proportions of nonconforming units in subgroups of size n are plotted versus time is a(n)_____ chart.</strong> A)   B)R C)p D)C
B)R
C)p
D)C
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54
A control chart on which subgroup means are plotted versus time is a(n)_________ chart.

A) <strong>A control chart on which subgroup means are plotted versus time is a(n)_________ chart.</strong> A)   B)R C)p D)C
B)R
C)p
D)C
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55
A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.What is the sigma level capability for this process?</strong> A)3.0 B)3.72 C)1.6 D)1.0 E)2.72 = 1.0002 inches, <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.What is the sigma level capability for this process?</strong> A)3.0 B)3.72 C)1.6 D)1.0 E)2.72 = .003 inches,and subgroup size of 5.What is the sigma level capability for this process?

A)3.0
B)3.72
C)1.6
D)1.0
E)2.72
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56
___________ causes of variation may be remedied by local supervision.

A)Common
B)Assignable
C)Usual
D)Expected
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57
A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Calculate the estimated proportion of out-of-specification sleeve inside diameters.</strong> A).0471 B).0217 C).0001 D).4783 E).0139 = 1.0002 inches, <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Calculate the estimated proportion of out-of-specification sleeve inside diameters.</strong> A).0471 B).0217 C).0001 D).4783 E).0139 = .003 inches,and subgroup size of 5.Calculate the estimated proportion of out-of-specification sleeve inside diameters.

A).0471
B).0217
C).0001
D).4783
E).0139
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58
A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Determine the estimated number of standard deviations of process leeway.</strong> A)3 B)1.667 C)3.72 D)1.443 E).72 = 1.0002 inches, <strong>A powder metal manufacturing company is producing sleeves for a locking mechanism.The target (nominal)value for the inside diameter is 1 inch.The inside diameter specifications are 1 ± .005 inches.Assume that the process is in statistical control with   = 1.0002 inches,   = .003 inches,and subgroup size of 5.Determine the estimated number of standard deviations of process leeway.</strong> A)3 B)1.667 C)3.72 D)1.443 E).72 = .003 inches,and subgroup size of 5.Determine the estimated number of standard deviations of process leeway.

A)3
B)1.667
C)3.72
D)1.443
E).72
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59
For a manufacturing process, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the   chart.</strong> A)9.526 and 10.474 B)9.769 and 10.231 C)9.807 and 10.193 D)9.484 and 10.516 E)8.80 and 11.20 = 10 inches, <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the   chart.</strong> A)9.526 and 10.474 B)9.769 and 10.231 C)9.807 and 10.193 D)9.484 and 10.516 E)8.80 and 11.20 = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the <strong>For a manufacturing process,   = 10 inches,   = .4 inches,and the subgroup sample size is 6 units.Calculate the standard control limits for the   chart.</strong> A)9.526 and 10.474 B)9.769 and 10.231 C)9.807 and 10.193 D)9.484 and 10.516 E)8.80 and 11.20 chart.

A)9.526 and 10.474
B)9.769 and 10.231
C)9.807 and 10.193
D)9.484 and 10.516
E)8.80 and 11.20
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60
Auxiliary lines drawn on a control chart for accomplishing pattern analysis are called ___________ boundaries.

A)sigma
B)range
C)zone
D)mean
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61
In 20 samples,there are 80 units defective.If each sample consists of 100 units,find the appropriate UCL and the LCL for the p chart.

A)[.0269,.0531]
B)[.0204,.0596]
C)[.0380,.0420]
D)[0,.0988]
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62
How well a process is able to meet the requirements set forth by the process design is called the quality of _____________.

A)performance
B)conformance
C)design
D)control
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63
If <strong>If   = 5.2,   = .3,and n = 4,calculate the natural tolerance limits.</strong> A)[5.054,5.346] B)[4.3,6.1] C)[4.806,5.594] D)[4.763,5.637] = 5.2, <strong>If   = 5.2,   = .3,and n = 4,calculate the natural tolerance limits.</strong> A)[5.054,5.346] B)[4.3,6.1] C)[4.806,5.594] D)[4.763,5.637] = .3,and n = 4,calculate the natural tolerance limits.

A)[5.054,5.346]
B)[4.3,6.1]
C)[4.806,5.594]
D)[4.763,5.637]
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64
The number of estimated process standard deviations between <strong>The number of estimated process standard deviations between   and the closest specification limit is the _____________ of the process.</strong> A)sigma level capability B)leeway C)mean D)capability and the closest specification limit is the _____________ of the process.

A)sigma level capability
B)leeway
C)mean
D)capability
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65
If <strong>If   = 5.2,   = .3,and n = 4,and if the specifications are [4.6,5.8],is the process capable?</strong> A)Yes B)No = 5.2, <strong>If   = 5.2,   = .3,and n = 4,and if the specifications are [4.6,5.8],is the process capable?</strong> A)Yes B)No = .3,and n = 4,and if the specifications are [4.6,5.8],is the process capable?

A)Yes
B)No
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66
If <strong>If   and R charts are used to control a manufacturing process,an ______ chart is analyzed first and brought into a state of statistical control before preparing the _______ chart.</strong> A)R,   B)   and R charts are used to control a manufacturing process,an ______ chart is analyzed first and brought into a state of statistical control before preparing the _______ chart.

A)R, <strong>If   and R charts are used to control a manufacturing process,an ______ chart is analyzed first and brought into a state of statistical control before preparing the _______ chart.</strong> A)R,   B)
B) <strong>If   and R charts are used to control a manufacturing process,an ______ chart is analyzed first and brought into a state of statistical control before preparing the _______ chart.</strong> A)R,   B)
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67
If <strong>If   = 2.0144,   = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the R chart.</strong> A)[.045,.1498] B)[.0972,.2055] C)[0,.2055] D)[0.2,114] = 2.0144, <strong>If   = 2.0144,   = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the R chart.</strong> A)[.045,.1498] B)[.0972,.2055] C)[0,.2055] D)[0.2,114] = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the R chart.

A)[.045,.1498]
B)[.0972,.2055]
C)[0,.2055]
D)[0.2,114]
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68
_________ is the set of international standards on quality management and quality assurance systems.It establishes processes for assuring that goods and services offered by the company meet a consistent level of quality acceptable to customers.

A)Control Charting
B)SQC
C)ISO 9000
D)ASQC
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69
If <strong>If   = 2.0144,   = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the   chart.</strong> A)[1.999,2.029] B)[1.958,2.071] C)[1.917,2.112] D)[1.437,2.591] = 2.0144, <strong>If   = 2.0144,   = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the   chart.</strong> A)[1.999,2.029] B)[1.958,2.071] C)[1.917,2.112] D)[1.437,2.591] = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the <strong>If   = 2.0144,   = .0972,and there are 25 subgroups of size 5,find the UCL and the LCL for the   chart.</strong> A)[1.999,2.029] B)[1.958,2.071] C)[1.917,2.112] D)[1.437,2.591] chart.

A)[1.999,2.029]
B)[1.958,2.071]
C)[1.917,2.112]
D)[1.437,2.591]
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70
Unusual sources of process variation that can be attributed to specific reasons are called ____________ causes of variation.

A)common
B)assignable
C)usual
D)expected
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71
If 20 samples of size 7 are drawn,with <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what is the A-B upper boundary for the   chart?</strong> A)35.697 B)34.908 C)34.347 D)34.008 = 33.33 and <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what is the A-B upper boundary for the   chart?</strong> A)35.697 B)34.908 C)34.347 D)34.008 = 5.65,what is the A-B upper boundary for the <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what is the A-B upper boundary for the   chart?</strong> A)35.697 B)34.908 C)34.347 D)34.008 chart?

A)35.697
B)34.908
C)34.347
D)34.008
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72
From 20 samples of size 100,a total of 80 units are defective.What is the centerline for the p chart?

A).04
B).4
C).8
D).08
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73
If <strong>If   = 16.1,   = .03,and n = 6,and if the specifications are [15.9,16.3],is the process capable?</strong> A)Yes B)No = 16.1, <strong>If   = 16.1,   = .03,and n = 6,and if the specifications are [15.9,16.3],is the process capable?</strong> A)Yes B)No = .03,and n = 6,and if the specifications are [15.9,16.3],is the process capable?

A)Yes
B)No
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74
If <strong>If   = .0139 and 25 shipments of 20 items each were examined,what are the UCL and the LCL for the p chart?</strong> A)[.0118,.0159] B)[0,.0401] C)[.008,.0198] D)[0,.0924] = .0139 and 25 shipments of 20 items each were examined,what are the UCL and the LCL for the p chart?

A)[.0118,.0159]
B)[0,.0401]
C)[.008,.0198]
D)[0,.0924]
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75
A unit that fails to meet specifications is called a _____________ unit.

A)conforming
B)capable
C)defective
D)common cause
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76
If 20 samples of size 7 are drawn,with <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what are the LCL and UCL for the R chart?</strong> A)[2.345,8.955] B)[.076,1.924] C)[.415,1.585] D)[.429,10.871] = 33.33 and <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what are the LCL and UCL for the R chart?</strong> A)[2.345,8.955] B)[.076,1.924] C)[.415,1.585] D)[.429,10.871] = 5.65,what are the LCL and UCL for the R chart?

A)[2.345,8.955]
B)[.076,1.924]
C)[.415,1.585]
D)[.429,10.871]
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77
If 20 samples of size 7 are drawn,with <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what are the LCL and the UCL for the   chart?</strong> A)[32.313,34.347] B)[30.963,35.697] C)[27.68,38,98] D)[32.911,33.749] = 33.33 and <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what are the LCL and the UCL for the   chart?</strong> A)[32.313,34.347] B)[30.963,35.697] C)[27.68,38,98] D)[32.911,33.749] = 5.65,what are the LCL and the UCL for the <strong>If 20 samples of size 7 are drawn,with   = 33.33 and   = 5.65,what are the LCL and the UCL for the   chart?</strong> A)[32.313,34.347] B)[30.963,35.697] C)[27.68,38,98] D)[32.911,33.749] chart?

A)[32.313,34.347]
B)[30.963,35.697]
C)[27.68,38,98]
D)[32.911,33.749]
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78
How well a product or a service performs in the marketplace is called the quality of ______________.

A)performance
B)conformance
C)design
D)control
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79
If <strong>If   = 16.1,   = .03,and n = 6,calculate the natural tolerance limits.</strong> A)[16.065,16.135] B)[16.088,16.112] C)[15.745,16.455] D)[16.055,16.145] = 16.1, <strong>If   = 16.1,   = .03,and n = 6,calculate the natural tolerance limits.</strong> A)[16.065,16.135] B)[16.088,16.112] C)[15.745,16.455] D)[16.055,16.145] = .03,and n = 6,calculate the natural tolerance limits.

A)[16.065,16.135]
B)[16.088,16.112]
C)[15.745,16.455]
D)[16.055,16.145]
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80
Assume that 25 samples of 50 each are taken and the total number of defectives is 34.Calculate <strong>Assume that 25 samples of 50 each are taken and the total number of defectives is 34.Calculate  </strong> A).680 B).453 C).816 D).0272

A).680
B).453
C).816
D).0272
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