Deck 3: Exponential and Logarithmic Functions

ملء الشاشة (f)
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سؤال
Carbon dating presumes that, as long as a plant or animal is alive, the proportion of its carbon that is 14C is constant.The amount of 14C in an object made from harvested plants, like paper, will decline exponentially according to the equation A=A0e0.0001213tA = A _ { 0 } e ^ { - 0.0001213 t } , where A represents the amount of 14C in the object, Ao represents the amount of 14C in living organisms, and t is the time in years since the plant was harvested.If an archeological artifact has 35% as much 14C as a living organism, how old would you predict it to be? Round to the nearest year.

A)5715 years
B)29,310 years
C)93 years
D)8655 years
E)15,427 years
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سؤال
The value V (in millions of dollars) of a famous painting can be modeled by V=10eitV = 10 e ^ { i t } where t represents the year, with t = 0 corresponding to 2000.In 2008, the same painting was sold for $65 million.Predict the value of the painting in 2018.(Round your answer to two decimal places.)

A)$674.61 million
B)$874.61 million
C)$474.61 million
D)$774.61 million
E)$574.61 million
سؤال
The population P (in thousands) of Orlando, Florida from 2000 through 2007 can be modeled by P=1530.6ektP = 1530.6 e ^ { k t } where t represents the year, with t=0t = 0 corresponding to 2000.In 2006, the population of Orlando, Florida was about 1,883,000.00.Find the value of k.

A)k = 0.03183
B)k = 0.02863
C)k = 0.02163
D)k = 0.03453
E)k = 0.03063
سؤال
Select the correct graph for the given function y=7ex/4y = 7 e ^ { - x / 4 }

A)  <strong>Select the correct graph for the given function  y = 7 e ^ { - x / 4 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B)  <strong>Select the correct graph for the given function  y = 7 e ^ { - x / 4 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C)  <strong>Select the correct graph for the given function  y = 7 e ^ { - x / 4 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D)  <strong>Select the correct graph for the given function  y = 7 e ^ { - x / 4 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph for the given function  y = 7 e ^ { - x / 4 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
سؤال
Find the exponential model y=ae0.7675xy = a e ^ { 0.7675 x } that fits the points shown in the graph.  <strong>Find the exponential model  y = a e ^ { 0.7675 x }  that fits the points shown in the graph.    </strong> A)  y = e ^ { - 0.7675 x }  B)  y = e ^ { 0.7675 x }  C)  y = - e ^ { - 0.7675 x }  D)  y = x e ^ { 0.7675 }  E)  y = - x e ^ { - 0.7675 }  <div style=padding-top: 35px>

A) y=e0.7675xy = e ^ { - 0.7675 x }
B) y=e0.7675xy = e ^ { 0.7675 x }
C) y=e0.7675xy = - e ^ { - 0.7675 x }
D) y=xe0.7675y = x e ^ { 0.7675 }
E) y=xe0.7675y = - x e ^ { - 0.7675 }
سؤال
Select the correct graph for the given function y=5e(x2)2/5y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }

A)  <strong>Select the correct graph for the given function   y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B)  <strong>Select the correct graph for the given function   y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C)  <strong>Select the correct graph for the given function   y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D)  <strong>Select the correct graph for the given function   y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph for the given function   y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
سؤال
Select the correct graph for the given function y=61+e2xy = \frac { 6 } { 1 + e ^ { - 2 x } }

A)  <strong>Select the correct graph for the given function   y = \frac { 6 } { 1 + e ^ { - 2 x } }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B)  <strong>Select the correct graph for the given function   y = \frac { 6 } { 1 + e ^ { - 2 x } }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C)  <strong>Select the correct graph for the given function   y = \frac { 6 } { 1 + e ^ { - 2 x } }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D)  <strong>Select the correct graph for the given function   y = \frac { 6 } { 1 + e ^ { - 2 x } }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph for the given function   y = \frac { 6 } { 1 + e ^ { - 2 x } }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
سؤال
Select a scatter plot of the given data. r7%8%11%12%14%15%t16.2414.2710.539.698.387.86\begin{array}{|c|c|c|c|c|c|c|}\hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\\hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\\hline\end{array}

A) <strong>Select a scatter plot of the given data.  \begin{array}{|c|c|c|c|c|c|c|} \hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\ \hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\ \hline \end{array} </strong> A)  B)   C)   D)  E)  <div style=padding-top: 35px>
B)  <strong>Select a scatter plot of the given data.  \begin{array}{|c|c|c|c|c|c|c|} \hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\ \hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\ \hline \end{array} </strong> A)  B)   C)   D)  E)  <div style=padding-top: 35px>
C)  <strong>Select a scatter plot of the given data.  \begin{array}{|c|c|c|c|c|c|c|} \hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\ \hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\ \hline \end{array} </strong> A)  B)   C)   D)  E)  <div style=padding-top: 35px>
D) <strong>Select a scatter plot of the given data.  \begin{array}{|c|c|c|c|c|c|c|} \hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\ \hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\ \hline \end{array} </strong> A)  B)   C)   D)  E)  <div style=padding-top: 35px>
E) <strong>Select a scatter plot of the given data.  \begin{array}{|c|c|c|c|c|c|c|} \hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\ \hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\ \hline \end{array} </strong> A)  B)   C)   D)  E)  <div style=padding-top: 35px>
سؤال
The populations P (in thousands) of Pittsburgh, Pennsylvania from 2000 through 2007 can be modeled by P=26321+0.083e0.0500tP = \frac { 2632 } { 1 + 0.083 e ^ { 0.0500 t } } where t represents the year, with t=0t = 0 corresponding to 2000.Use the model to find the numbers of cell sites in the year 2009.

A)2,326,853.00
B)2,327,853.00
C)2,329,853.00
D)2,328,853.00
E)2,330,853.00
سؤال
An initial investment of $5000 doubles in value in 6.3 years.Assuming continuous compounding, what was the interest rate? Round to the nearest tenth of a percent.

A)11.0%
B)4.8%
C)5.5%
D)6.3%
E)100%
سؤال
Select the correct graph for the given function y=ln(x+2)y = \ln ( x + 2 )

A) <strong>Select the correct graph for the given function   y = \ln ( x + 2 )  </strong> A)  B)   C)  D)   E)   <div style=padding-top: 35px>
B)  <strong>Select the correct graph for the given function   y = \ln ( x + 2 )  </strong> A)  B)   C)  D)   E)   <div style=padding-top: 35px>
C) <strong>Select the correct graph for the given function   y = \ln ( x + 2 )  </strong> A)  B)   C)  D)   E)   <div style=padding-top: 35px>
D)  <strong>Select the correct graph for the given function   y = \ln ( x + 2 )  </strong> A)  B)   C)  D)   E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph for the given function   y = \ln ( x + 2 )  </strong> A)  B)   C)  D)   E)   <div style=padding-top: 35px>
سؤال
The population P of a bacteria culture is modeled by P=4100ektP = 4100 e ^ { k t } , where t is the time in hours.If the population of the culture was 5800 after 40 hours, how long does it take for the population to double? Round to the nearest tenth of an hour.

A)54.8 hours
B)8.9 hours
C)79.9 hours
D)81.7 hours
E)56.6 hours
سؤال
The population P (in thousands) of Reno, Nevada from 2000 through 2007 can be modeled by P=346.8ektP = 346.8 e ^ { k t } where t represents the year, with t=0t = 0 corresponding to 2000.In 2005, the population of Reno was about 395,000.According to the model, during what year will the population reach 486,000.00?

A)2013
B)2005
C)2021
D)2017
E)2009
سؤال
An initial investment of $4000 grows at an annual interest rate of 5% compounded continuously.How long will it take to double the investment?

A)1 year
B)14.40 years
C)13.86 years
D)14.86 years
E)13.40 years
سؤال
If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by A=1+0.075t or A=e0.07tA = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t } depending on whether the account pays simple interest at 712%7 \frac { 1 } { 2 } \% or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?

A)  <strong>If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by  A = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t }  depending on whether the account pays simple interest at  7 \frac { 1 } { 2 } \%  or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?  </strong> A)    B)    C)    D)   E)   <div style=padding-top: 35px>
B)  <strong>If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by  A = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t }  depending on whether the account pays simple interest at  7 \frac { 1 } { 2 } \%  or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?  </strong> A)    B)    C)    D)   E)   <div style=padding-top: 35px>
C)  <strong>If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by  A = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t }  depending on whether the account pays simple interest at  7 \frac { 1 } { 2 } \%  or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?  </strong> A)    B)    C)    D)   E)   <div style=padding-top: 35px>
D)  <strong>If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by  A = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t }  depending on whether the account pays simple interest at  7 \frac { 1 } { 2 } \%  or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?  </strong> A)    B)    C)    D)   E)   <div style=padding-top: 35px>
E)  <strong>If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by  A = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t }  depending on whether the account pays simple interest at  7 \frac { 1 } { 2 } \%  or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?  </strong> A)    B)    C)    D)   E)   <div style=padding-top: 35px>
سؤال
Select the correct graph for the given function y=4ex/2y = 4 e ^ { x / 2 }

A)  <strong>Select the correct graph for the given function   y = 4 e ^ { x / 2 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B)  <strong>Select the correct graph for the given function   y = 4 e ^ { x / 2 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C)  <strong>Select the correct graph for the given function   y = 4 e ^ { x / 2 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D)  <strong>Select the correct graph for the given function   y = 4 e ^ { x / 2 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph for the given function   y = 4 e ^ { x / 2 }  </strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
سؤال
Select the correct graph for the given function
y=5+log(x+2)y = 5 + \log ( x + 2 )

A) <strong>Select the correct graph for the given function  y = 5 + \log ( x + 2 )  </strong> A)  B)   C)   D)  E)   <div style=padding-top: 35px>
B)  <strong>Select the correct graph for the given function  y = 5 + \log ( x + 2 )  </strong> A)  B)   C)   D)  E)   <div style=padding-top: 35px>
C)  <strong>Select the correct graph for the given function  y = 5 + \log ( x + 2 )  </strong> A)  B)   C)   D)  E)   <div style=padding-top: 35px>
D) <strong>Select the correct graph for the given function  y = 5 + \log ( x + 2 )  </strong> A)  B)   C)   D)  E)   <div style=padding-top: 35px>
E)  <strong>Select the correct graph for the given function  y = 5 + \log ( x + 2 )  </strong> A)  B)   C)   D)  E)   <div style=padding-top: 35px>
سؤال
Find the exponential model y=ae0.5756xy = a e ^ { 0.5756 x } that fits the points shown in the graph.  <strong>Find the exponential model  y = a e ^ { 0.5756 x }  that fits the points shown in the graph.    </strong> A)  y = \frac { 1 } { 2 } e ^ { - 0.5756 x }  B)  y = - \frac { 1 } { 2 } x e ^ { - 0.5756 }  C)  y = \frac { 1 } { 2 } x e ^ { 0.5756 }  D)  y = \frac { 1 } { 2 } e ^ { 0.5756 x }  E)  y = - \frac { 1 } { 2 } e ^ { - 0.5756 x }  <div style=padding-top: 35px>

A) y=12e0.5756xy = \frac { 1 } { 2 } e ^ { - 0.5756 x }
B) y=12xe0.5756y = - \frac { 1 } { 2 } x e ^ { - 0.5756 }
C) y=12xe0.5756y = \frac { 1 } { 2 } x e ^ { 0.5756 }
D) y=12e0.5756xy = \frac { 1 } { 2 } e ^ { 0.5756 x }
E) y=12e0.5756xy = - \frac { 1 } { 2 } e ^ { - 0.5756 x }
سؤال
The population P of a culture of bacteria is described by the equation P=1300e0.052tP = 1300 e ^ { 0.052 t } , where t is the time, in hours, relative to the time at which the population was 1300.What was the population at t=3t = 3 hours?

A) P(3)1419P ( 3 ) \approx 1419
B) P(3)1519P ( 3 ) \approx 1519
C) P(3)1319P ( 3 ) \approx 1319
D) P(3)1619P ( 3 ) \approx 1619
E) P(3)1719P ( 3 ) \approx 1719
سؤال
The number y of hits a new search-engine website receives each month can be modeled by y=4080ekty = 4080 e ^ { k t } where t represents the number of months the website has been operating.In the website's third month, there were 10,000 hits.Find the value of k, and use this value to predict the number of hits the website will receive after 22 months.

A) k=0.2988k = 0.2988 ; About 184,894,691,979 hits
B) k=0.2988k = 0.2988 ; About 2,921,047 hits
C) k=0.2988k = 0.2988 ; About 22,832,533,585 hits
D) k=0.2988k = 0.2988 ; About 57,970,933 hits
E) k=0.2988k = 0.2988 ; About 1,150,488,266 hits
سؤال
Find the intensity I of an earthquake measuring R on the Richter scale ( let I0=1)\left( \text { let } I _ { 0 } = 1 \right) .
Southern Sumatra, Indonesia in 2007, R=8.25R = 8.25

A) 108.25177,822,94110 ^ { 8.25 } \approx 177,822,941
B) 108.25177,827,94110 ^ { 8.25 } \approx 177,827,941
C) 108.25177,825,94110 ^ { 8.25 } \approx 177,825,941
D) 108.25177,832,94110 ^ { 8.25 } \approx 177,832,941
E) 108.25177,829,94110 ^ { 8.25 } \approx 177,829,941
سؤال
Find the magnitude R of an earthquake of intensity I( let I0=1 ) I \left( \text { let } I _ { 0 } = 1 \right. \text { ) } . I=16000I = 16000

A)3.20
B)5.20
C)4.20
D)2.20
E)6.20
سؤال
Determine whether the given x-value is a solution (or an approximate solution) of the equation. 43x10=16x=4\begin{array} { l } 4 ^ { 3 x - 10 } = 16 \\x = 4\end{array}
سؤال
Tritium, a radioactive isotope of hydrogen, has a half-life of 12.4 years.Of an initial sample of 33 grams, how much will remain after 69 years? ​

A)0 grams
B)29.1351 grams
C)10.9074 grams
D)8.2500 grams
E)0.6973 grams
سؤال
Solve for x. 6x=366 ^ { x } = 36

A)8
B)2
C)-2
D)-6
E)6
سؤال
The chemical acidity of a solution is measured in units of pH: pH=log[H+]\mathrm { pH } = - \log \left[ \mathrm { H } ^ { + } \right] , where [H+]\left[ \mathrm { H } ^ { + } \right] is the hydrogen ion concentration in the solution.What is [H+]\left[ \mathrm { H } ^ { + } \right] if the pH=3.8\mathrm { pH } = 3.8

A)3.800
B) 6.31×1046.31 \times 10 ^ { - 4 }
C) 6.31×1036.31 \times 10 ^ { - 3 }
D) 1.58×1031.58 \times 10 ^ { - 3 }
E) 1.58×1041.58 \times 10 ^ { - 4 }
سؤال
An initial investment of $2000 grows at an annual interest rate of 4% compounded continuously.How long will it take to double the investment?

A)17.33 years
B)18.33 years
C)18.00 years
D)17.00 years
E)1 year
سؤال
A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones.The numbers of cell sites from 1985 through 2008 can be modeled by y=237,1011+1950e0.355ty = \frac { 237,101 } { 1 + 1950 e ^ { - 0.355 t } } where t represents the year, with t=5t = 5 corresponding to 1985.Use the model to find the numbers of cell sites in the year 2007 .

A)211,071
B)209,071
C)208,071
D)207,071
E)210,071
سؤال
Carbon dating presumes that, as long as a plant or animal is alive, the proportion of its carbon that is 14C is constant.The amount of 14C in an object made from harvested plants, like paper, will decline exponentially according to the equation A=A0e0.0001213tA = A _ { 0 } e ^ { - 0.0001213 t } , where A represents the amount of 14C in the object, Ao represents the amount of 14C in living organisms, and t is the time in years since the plant was harvested.If an archeological artifact has 30% as much 14C as a living organism, how old would you predict it to be? Round to the nearest year.

A)28,040 years
B)5715 years
C)9926 years
D)14,758 years
E)100 years
سؤال
Determine whether the given x-value is a solution (or an approximate solution) of the equation. 45x5=256x=2\begin{array} { l } 4 ^ { 5 x - 5 } = 256 \\x = 2\end{array}
سؤال
The chemical acidity of a solution is measured in units of pH: pH=log[H+]\mathrm { pH } = - \log \left[ \mathrm { H } ^ { + } \right] , where [H+]\left[ \mathrm { H } ^ { + } \right] is the hydrogen ion concentration in the solution.What is [H+]\left[ \mathrm { H } ^ { + } \right] if the pH=6.8\mathrm { pH } = 6.8 ?

A) 1.58×1071.58 \times 10 ^ { - 7 }
B) 6.31×1076.31 \times 10 ^ { - 7 }
C) 6.31×1066.31 \times 10 ^ { - 6 }
D) 1.58×1061.58 \times 10 ^ { - 6 }
E)6.800
سؤال
The chemical acidity of a solution is measured in units of pH: pH=log[H+]\mathrm { pH } = - \log \left[ \mathrm { H } ^ { + } \right] , where [H+]\left[ \mathrm { H } ^ { + } \right] is the hydrogen ion concentration in the solution.If a sample of rain has a pH of 3.3, how many times higher is its [H+]\left[ \mathrm { H } ^ { + } \right] than pure water's, which has a pH of 7?

A) 5.0×1045.0 \times 10 ^ { 4 }
B) 2.0×1042.0 \times 10 ^ { 4 }
C) 2.0×1032.0 \times 10 ^ { 3 }
D) 5.0×1035.0 \times 10 ^ { 3 }
E)7
سؤال
Find the magnitude R of an earthquake of intensity I (let I0=1)\left. I \text { (let } I _ { 0 } = 1 \right) . I=270300000I = 270300000

A)7.43
B)6.43
C)8.43
D)10.43
E)9.43
سؤال
Solve for x.Approximate the result to three decimal places. ex=4e ^ { x } = 4

A) ln41.466\ln 4 \approx 1.466
B) ln41.476\ln 4 \approx 1.476
C) ln41.436\ln 4 \approx 1.436
D) ln41.386\ln 4 \approx 1.386
E) ln41.456\ln 4 \approx 1.456
سؤال
Solve for x. lnxln5=0\ln x - \ln 5 = 0

A) 15- \frac { 1 } { 5 }
B) 5- 5
C) 15\frac { 1 } { 5 }
D) 525 ^ { - 2 }
E)5
سؤال
Solve for x. (14)x=64\left( \frac { 1 } { 4 } \right) ^ { x } = 64

A)4
B) 3- 3
C)7
D)3
E) 4- 4
سؤال
Find the intensity I of an earthquake measuring R on the Richter scale  (let I0=1 ) \text { (let } I _ { 0 } = 1 \text { ) } .
Costa Rica in 2009, R=5.70R = 5.70

A) 105.70503,18710 ^ { 5.70 } \approx 503,187
B) 105.70501,18710 ^ { 5.70 } \approx 501,187
C) 105.70506,18710 ^ { 5.70 } \approx 506,187
D) 105.70496,18710 ^ { 5.70 } \approx 496,187
E) 105.70499,18710 ^ { 5.70 } \approx 499,187
سؤال
The population P of a culture of bacteria is described by the equation The population P of a culture of bacteria is described by the equation   , where t is the time, in hours, relative to the time at which the population was 1600. (a) What was the population at   hours? Show your work. (b) After how many hours will the population reach 10000.00? Round to the nearest tenth of an hour.Show your work.<div style=padding-top: 35px> , where t is the time, in hours, relative to the time at which the population was 1600.
(a) What was the population at The population P of a culture of bacteria is described by the equation   , where t is the time, in hours, relative to the time at which the population was 1600. (a) What was the population at   hours? Show your work. (b) After how many hours will the population reach 10000.00? Round to the nearest tenth of an hour.Show your work.<div style=padding-top: 35px> hours? Show your work.
(b) After how many hours will the population reach 10000.00? Round to the nearest tenth of an hour.Show your work.
سؤال
A population growing at an annual rate r will triple in a time t given by the formula t=ln3rt = \frac { \ln 3 } { r } .If the growth rate remains constant and equals 9% per year, how long will it take the population of the town to triple?

A)2.2 years
B)5.3 years
C)6.6 years
D)1 years
E)12.2 years
سؤال
The chemical acidity of a solution is measured in units of pH: pH=log[H+]\mathrm { pH } = - \log \left[ \mathrm { H } ^ { + } \right] , where [H+]\left[ \mathrm { H } ^ { + } \right] is the hydrogen ion concentration in the solution.If a sample of rain has a pH of 3.4, how many times higher is its [H+]\left[ \mathrm { H } ^ { + } \right] than pure water's, which has a pH of 7?

A) 4.0×1034.0 \times 10 ^ { 3 }
B) 2.5×1042.5 \times 10 ^ { 4 }
C)7
D) 2.5×1032.5 \times 10 ^ { 3 }
E) 4.0×1044.0 \times 10 ^ { 4 }
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. 3ex=153 e ^ { x } = 15

A) ln51.609\ln 5 \approx - 1.609
B) ln51.099\ln 5 \approx 1.099
C) ln51.099\ln 5 \approx - 1.099
D) ln51.609\ln 5 \approx 1.609
E) ln52.708\ln 5 \approx 2.708
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. 2(52x)=122 \left( 5 ^ { 2 - x } \right) = 12

A) 2ln6ln53.8872 - \frac { \ln 6 } { \ln 5 } \approx 3.887
B) 2ln6ln51.8872 - \frac { \ln 6 } { \ln 5 } \approx 1.887
C) 2ln6ln50.8872 - \frac { \ln 6 } { \ln 5 } \approx 0.887
D) 2ln6ln54.8872 - \frac { \ln 6 } { \ln 5 } \approx 4.887
E) 2ln6ln52.8872 - \frac { \ln 6 } { \ln 5 } \approx 2.887
سؤال
Solve for x. logx=4\log x = - 4

A) 4- 4
B)0.0001
C) 0.0001- 0.0001
D) 44
E)1.386
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. 4(5x5)=244 \left( 5 ^ { x - 5 } \right) = 24

A) 5+ln6ln57.1135 + \frac { \ln 6 } { \ln 5 } \approx 7.113
B) 5+ln6ln59.1135 + \frac { \ln 6 } { \ln 5 } \approx 9.113
C) 5+ln6ln56.1135 + \frac { \ln 6 } { \ln 5 } \approx 6.113
D) 5+ln6ln58.1135 + \frac { \ln 6 } { \ln 5 } \approx 8.113
E) 5+ln6ln510.1135 + \frac { \ln 6 } { \ln 5 } \approx 10.113
سؤال
Solve for x.Approximate the result to three decimal places. log7x=12\log _ { 7 } x = \frac { 1 } { 2 }

A) 72.828\sqrt { 7 } \approx 2.828
B) 7=2.646\sqrt { 7 } = 2.646
C) 72.646\sqrt { 7 } \approx - 2.646
D) 72.646\sqrt { 7 } \approx 2.646
E) 772.646\frac { \sqrt { 7 } } { 7 } \approx 2.646
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. 2x5=162 ^ { x - 5 } = 16

A)10
B)11
C)9
D)-9
E)12
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. ex=ex212e ^ { x } = e ^ { x ^ { 2 } - 12 }

A) 3,43 , - 4
B) 3,4- 3 , - 4
C) 3,43,4
D) 3,4- 3,4
E) 3,3- 3,3
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. 1000e4x=751000 e ^ { - 4 x } = 75

A) 14ln3402.648- \frac { 1 } { 4 } \ln \frac { 3 } { 40 } \approx 2.648
B) 14ln3401.352- \frac { 1 } { 4 } \ln \frac { 3 } { 40 } \approx - 1.352
C) 14ln3401.648- \frac { 1 } { 4 } \ln \frac { 3 } { 40 } \approx 1.648
D) 14ln3400.648- \frac { 1 } { 4 } \ln \frac { 3 } { 40 } \approx 0.648
E) 14ln3400.352- \frac { 1 } { 4 } \ln \frac { 3 } { 40 } \approx - 0.352
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places.
e2x7ex8=0e ^ { 2 x } - 7 e ^ { x } - 8 = 0

A) ln83.079\ln 8 \approx 3.079
B) ln82.079\ln 8 \approx 2.079
C) ln84.079\ln 8 \approx 4.079
D) ln81.079\ln 8 \approx 1.079
E) ln80.079\ln 8 \approx 0.079
سؤال
Solve for x.Approximate the result to three decimal places. lnx=2\ln x = - 2

A) e27.389e ^ { - 2 } \approx 7.389
B) e20.368e ^ { - 2 } \approx 0.368
C) e22.718e ^ { - 2 } \approx 2.718
D) e20.135e ^ { - 2 } \approx 0.135
E) e21.000e ^ { - 2 } \approx 1.000
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. 65x=0.506 ^ { - 5 x } = 0.50

A) ln(0.50)5ln60.072- \frac { \ln ( 0.50 ) } { 5 \ln 6 } \approx 0.072
B) ln(0.50)5ln60.517\frac { \ln ( 0.50 ) } { 5 \ln 6 } \approx 0.517
C) ln(0.50)5ln60.387- \frac { \ln ( 0.50 ) } { 5 \ln 6 } \approx 0.387
D) ln(0.50)5ln60.077- \frac { \ln ( 0.50 ) } { 5 \ln 6 } \approx 0.077
E) ln(0.50)5ln60.077- \frac { \ln ( 0.50 ) } { 5 \ln 6 } \approx - 0.077
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. e4x2=e3x214xe ^ { - 4 x ^ { 2 } } = e ^ { 3 x ^ { 2 } - 14 x }

A) 4,24,2
B) 3,23,2
C) 4,2- 4,2
D) 0,20,2
E) 0,20 , - 2
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. 6x+8=576 ^ { x } + 8 = 57

A) ln49ln62.172\frac { \ln 49 } { \ln 6 } \approx 2.172
B) ln49ln60.460\frac { \ln 49 } { \ln 6 } \approx - 0.460
C) ln49ln60.514\frac { \ln 49 } { \ln 6 } \approx 0.514
D) ln49ln60.460\frac { \ln 49 } { \ln 6 } \approx 0.460
E) ln49ln62.172\frac { \ln 49 } { \ln 6 } \approx - 2.172
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. ex6=13e ^ { x } - 6 = 13

A) ln192.565\ln 19 \approx - 2.565
B) ln192.944\ln 19 \approx 2.944
C) ln191.792\ln 19 \approx 1.792
D) ln192.565\ln 19 \approx 2.565
E) ln192.944\ln 19 \approx - 2.944
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places.
22+4ex=13- 22 + 4 e ^ { x } = 13

A) ln3541.169\ln \frac { 35 } { 4 } \approx 1.169
B) ln3544.169\ln \frac { 35 } { 4 } \approx 4.169
C) ln3542.169\ln \frac { 35 } { 4 } \approx 2.169
D) ln3540.169\ln \frac { 35 } { 4 } \approx 0.169
E) ln3543.169\ln \frac { 35 } { 4 } \approx 3.169
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. 4ex=334 e ^ { x } = 33

A) ln3342.110\ln \frac { 33 } { 4 } \approx 2.110
B) ln3342.110\ln \frac { 33 } { 4 } \approx - 2.110
C) ln4332.110\ln \frac { 4 } { 33 } \approx 2.110
D) ln3343.497\ln \frac { 33 } { 4 } \approx 3.497
E) ln3340.114\ln \frac { 33 } { 4 } \approx 0.114
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. 2(3x)=362 \left( 3 ^ { x } \right) = 36

A) ln18ln30.380\frac { \ln 18 } { \ln 3 } \approx 0.380
B) ln18ln30.380\frac { \ln 18 } { \ln 3 } \approx - 0.380
C) ln18ln32.631\frac { \ln 18 } { \ln 3 } \approx - 2.631
D) ln3ln182.631\frac { \ln 3 } { \ln 18 } \approx 2.631
E) ln18ln32.631\frac { \ln 18 } { \ln 3 } \approx 2.631
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. 38x=24003 ^ { 8 x } = 2400

A) ln24008ln30.018\frac { \ln 2400 } { 8 \ln 3 } \approx 0.018
B) ln24008ln30.886\frac { \ln 2400 } { 8 \ln 3 } \approx 0.886
C) ln24008ln30.089\frac { \ln 2400 } { 8 \ln 3 } \approx 0.089
D) ln24008ln30.886\frac { \ln 2400 } { 8 \ln 3 } \approx - 0.886
E) ln24008ln31.248\frac { \ln 2400 } { 8 \ln 3 } \approx 1.248
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. e3x=75e ^ { 3 x } = 75

A) ln7530.439\frac { \ln 75 } { 3 } \approx 0.439
B) ln7532.439\frac { \ln 75 } { 3 } \approx 2.439
C) ln7530.561\frac { \ln 75 } { 3 } \approx - 0.561
D) ln7533.439\frac { \ln 75 } { 3 } \approx 3.439
E) ln7531.439\frac { \ln 75 } { 3 } \approx 1.439
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places. ex=ex230e ^ { x } = e ^ { x ^ { 2 } - 30 }

A) 6,5- 6 , - 5
B) 1,301 , - 30
C) 6,56,5
D) 6,5- 6,5
E) 6,56 , - 5
سؤال
$3000 is invested in an account at interest rate r, compounded continuously.Find the time required for the amount to triple.(Approximate the result to two decimal places.) r=0.03r = 0.03

A)37.62 yr
B)36.62 yr
C)35.62 yr
D)34.62 yr
E)38.62 yr
سؤال
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. 8+71lnx=148 + 71 \ln x = 14

A) e6/73.356e ^ { 6 / 7 } \approx 3.356
B) e6/71.356e ^ { 6 / 7 } \approx 1.356
C) e6/74.356e ^ { 6 / 7 } \approx 4.356
D) e6/72.356e ^ { 6 / 7 } \approx 2.356
E) e6/70.356e ^ { 6 / 7 } \approx 0.356
سؤال
Solve (14)x=64\left( \frac { 1 } { 4 } \right) ^ { x } = 64 for x.

A)-3
B)-4
C)-1
D)1
E)no solution
سؤال
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. 6lnx=56 \ln x = 5

A) e5/60.301e ^ { 5 / 6 } \approx 0.301
B) e5/61.301e ^ { 5 / 6 } \approx 1.301
C) e5/63.301e ^ { 5 / 6 } \approx 3.301
D) e5/62.301e ^ { 5 / 6 } \approx 2.301
E) e5/64.301e ^ { 5 / 6 } \approx 4.301
سؤال
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. 2log3(0.5x)=52 \log _ { 3 } ( 0.5 x ) = 5

A) 2(35/2)33.1772 \left( 3 ^ { 5 / 2 } \right) \approx 33.177
B) 2(35/2)30.1772 \left( 3 ^ { 5 / 2 } \right) \approx 30.177
C) 2(35/2)31.1772 \left( 3 ^ { 5 / 2 } \right) \approx 31.177
D) 2(35/2)29.1772 \left( 3 ^ { 5 / 2 } \right) \approx 29.177
E) 2(35/2)32.1772 \left( 3 ^ { 5 / 2 } \right) \approx 32.177
سؤال
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. ln2x=3\ln 2 x = 3

A) e328.043\frac { e ^ { 3 } } { 2 } \approx 8.043
B) e3210.043\frac { e ^ { 3 } } { 2 } \approx 10.043
C) e3212.043\frac { e ^ { 3 } } { 2 } \approx 12.043
D) e3211.043\frac { e ^ { 3 } } { 2 } \approx 11.043
E) e3213.043\frac { e ^ { 3 } } { 2 } \approx 13.043
سؤال
Solve for x: 7(10x3)=237 \left( 10 ^ { x - 3 } \right) = 23 .Round to 3 decimal places.

A)0.517
B)no solution
C)3.517
D)-1.362
E)1.362
سؤال
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. logx=4\log x = 4

A)1,000
B)1,000,000
C)10,000
D)100,000
E)100
سؤال
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. lnx=5\ln x = - 5

A) e52.007e ^ { - 5 } \approx 2.007
B) e51.007e ^ { - 5 } \approx 1.007
C) e53.007e ^ { - 5 } \approx 3.007
D) e51.993e ^ { - 5 } \approx - 1.993
E) e50.007e ^ { - 5 } \approx 0.007
سؤال
Solve for x: 5x/3=0.00525 ^ { - x / 3 } = 0.0052 .Round to 3 decimal places.

A)-20.606
B)9.803
C)20.606
D)-3.268
E)15.777
سؤال
Determine whether or not x=37x = \frac { 3 } { 7 } is a solution to 33x3=813 ^ { 3 x - 3 } = 81 .
سؤال
$4500 is invested in an account at interest rate r, compounded continuously.Find the time required for the amount to triple.(Approximate the result to two decimal places.) r=0.0315r = 0.0315

A)21.00 yr
B)20.00 yr
C)34.88 yr
D)24.00 yr
E)23.00 yr
سؤال
Solve the equation algebraically.Round the result to three decimal places. 3+lnx8=0\frac { 3 + \ln x } { 8 } = 0

A) e32,980.958e ^ { - 3 } \approx 2,980.958
B) e30e ^ { - 3 } \approx 0
C) e354.598e ^ { - 3 } \approx 54.598
D) e30.050e ^ { - 3 } \approx 0.050
E) e320.086e ^ { - 3 } \approx 20.086
سؤال
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. log5(5x3)=log5(4x+4)\log _ { 5 } ( 5 x - 3 ) = \log _ { 5 } ( 4 x + 4 )

A)8
B)6
C)-1
D)7
E)9
سؤال
$2500 is invested in an account at interest rate r, compounded continuously.Find the time required for the amount to double.(Approximate the result to two decimal places.) r=0.06r = 0.06

A)13.55 yr
B)10.55 yr
C)12.55 yr
D)9.55 yr
E)11.55 yr
سؤال
$5500 is invested in an account at interest rate r, compounded continuously.Find the time required for the amount to double.(Approximate the result to two decimal places.) r=0.0540r = 0.0540

A)13.84 yr
B)10.84 yr
C)12.84 yr
D)11.84 yr
E)14.84 yr
سؤال
Solve the exponential equation algebraically.Approximate the result to three decimal places.
e2x7ex8=0e ^ { 2 x } - 7 e ^ { x } - 8 = 0

A) ln83.079\ln 8 \approx 3.079
B) ln81.079\ln 8 \approx 1.079
C) ln82.079\ln 8 \approx 2.079
D) ln80.079\ln 8 \approx 0.079
E) ln84.079\ln 8 \approx 4.079
سؤال
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. lnx8=7\ln \sqrt { x - 8 } = 7

A) e14+81,202,611.284e ^ { 14 } + 8 \approx 1,202,611.284
B) e14+81,202,614.284e ^ { 14 } + 8 \approx 1,202,614.284
C) e14+81,202,612.284e ^ { 14 } + 8 \approx 1,202,612.284
D) e14+81,202,610.284e ^ { 14 } + 8 \approx 1,202,610.284
E) e14+81,202,613.284e ^ { 14 } + 8 \approx 1,202,613.284
سؤال
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. 9+2lnx=49 + 2 \ln x = 4

A) e5/21.082e ^ { - 5 / 2 } \approx 1.082
B) e5/20.918e ^ { - 5 / 2 } \approx - 0.918
C) e5/21.918e ^ { - 5 / 2 } \approx - 1.918
D) e5/20.082e ^ { - 5 / 2 } \approx 0.082
E) e5/22.082e ^ { - 5 / 2 } \approx 2.082
سؤال
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. lnx5=0\ln x - 5 = 0

A) e5151.413e ^ { 5 } \approx 151.413
B) e5146.413e ^ { 5 } \approx 146.413
C) e5148.413e ^ { 5 } \approx 148.413
D) e5149.413e ^ { 5 } \approx 149.413
E) e5150.413e ^ { 5 } \approx 150.413
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Deck 3: Exponential and Logarithmic Functions
1
Carbon dating presumes that, as long as a plant or animal is alive, the proportion of its carbon that is 14C is constant.The amount of 14C in an object made from harvested plants, like paper, will decline exponentially according to the equation A=A0e0.0001213tA = A _ { 0 } e ^ { - 0.0001213 t } , where A represents the amount of 14C in the object, Ao represents the amount of 14C in living organisms, and t is the time in years since the plant was harvested.If an archeological artifact has 35% as much 14C as a living organism, how old would you predict it to be? Round to the nearest year.

A)5715 years
B)29,310 years
C)93 years
D)8655 years
E)15,427 years
8655 years
2
The value V (in millions of dollars) of a famous painting can be modeled by V=10eitV = 10 e ^ { i t } where t represents the year, with t = 0 corresponding to 2000.In 2008, the same painting was sold for $65 million.Predict the value of the painting in 2018.(Round your answer to two decimal places.)

A)$674.61 million
B)$874.61 million
C)$474.61 million
D)$774.61 million
E)$574.61 million
$674.61 million
3
The population P (in thousands) of Orlando, Florida from 2000 through 2007 can be modeled by P=1530.6ektP = 1530.6 e ^ { k t } where t represents the year, with t=0t = 0 corresponding to 2000.In 2006, the population of Orlando, Florida was about 1,883,000.00.Find the value of k.

A)k = 0.03183
B)k = 0.02863
C)k = 0.02163
D)k = 0.03453
E)k = 0.03063
k = 0.03453
4
Select the correct graph for the given function y=7ex/4y = 7 e ^ { - x / 4 }

A)  <strong>Select the correct graph for the given function  y = 7 e ^ { - x / 4 }  </strong> A)   B)   C)   D)   E)
B)  <strong>Select the correct graph for the given function  y = 7 e ^ { - x / 4 }  </strong> A)   B)   C)   D)   E)
C)  <strong>Select the correct graph for the given function  y = 7 e ^ { - x / 4 }  </strong> A)   B)   C)   D)   E)
D)  <strong>Select the correct graph for the given function  y = 7 e ^ { - x / 4 }  </strong> A)   B)   C)   D)   E)
E)  <strong>Select the correct graph for the given function  y = 7 e ^ { - x / 4 }  </strong> A)   B)   C)   D)   E)
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5
Find the exponential model y=ae0.7675xy = a e ^ { 0.7675 x } that fits the points shown in the graph.  <strong>Find the exponential model  y = a e ^ { 0.7675 x }  that fits the points shown in the graph.    </strong> A)  y = e ^ { - 0.7675 x }  B)  y = e ^ { 0.7675 x }  C)  y = - e ^ { - 0.7675 x }  D)  y = x e ^ { 0.7675 }  E)  y = - x e ^ { - 0.7675 }

A) y=e0.7675xy = e ^ { - 0.7675 x }
B) y=e0.7675xy = e ^ { 0.7675 x }
C) y=e0.7675xy = - e ^ { - 0.7675 x }
D) y=xe0.7675y = x e ^ { 0.7675 }
E) y=xe0.7675y = - x e ^ { - 0.7675 }
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6
Select the correct graph for the given function y=5e(x2)2/5y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }

A)  <strong>Select the correct graph for the given function   y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }  </strong> A)   B)   C)   D)   E)
B)  <strong>Select the correct graph for the given function   y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }  </strong> A)   B)   C)   D)   E)
C)  <strong>Select the correct graph for the given function   y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }  </strong> A)   B)   C)   D)   E)
D)  <strong>Select the correct graph for the given function   y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }  </strong> A)   B)   C)   D)   E)
E)  <strong>Select the correct graph for the given function   y = 5 e ^ { - ( x - 2 ) ^ { 2 } / 5 }  </strong> A)   B)   C)   D)   E)
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7
Select the correct graph for the given function y=61+e2xy = \frac { 6 } { 1 + e ^ { - 2 x } }

A)  <strong>Select the correct graph for the given function   y = \frac { 6 } { 1 + e ^ { - 2 x } }  </strong> A)   B)   C)   D)   E)
B)  <strong>Select the correct graph for the given function   y = \frac { 6 } { 1 + e ^ { - 2 x } }  </strong> A)   B)   C)   D)   E)
C)  <strong>Select the correct graph for the given function   y = \frac { 6 } { 1 + e ^ { - 2 x } }  </strong> A)   B)   C)   D)   E)
D)  <strong>Select the correct graph for the given function   y = \frac { 6 } { 1 + e ^ { - 2 x } }  </strong> A)   B)   C)   D)   E)
E)  <strong>Select the correct graph for the given function   y = \frac { 6 } { 1 + e ^ { - 2 x } }  </strong> A)   B)   C)   D)   E)
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8
Select a scatter plot of the given data. r7%8%11%12%14%15%t16.2414.2710.539.698.387.86\begin{array}{|c|c|c|c|c|c|c|}\hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\\hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\\hline\end{array}

A) <strong>Select a scatter plot of the given data.  \begin{array}{|c|c|c|c|c|c|c|} \hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\ \hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\ \hline \end{array} </strong> A)  B)   C)   D)  E)
B)  <strong>Select a scatter plot of the given data.  \begin{array}{|c|c|c|c|c|c|c|} \hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\ \hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\ \hline \end{array} </strong> A)  B)   C)   D)  E)
C)  <strong>Select a scatter plot of the given data.  \begin{array}{|c|c|c|c|c|c|c|} \hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\ \hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\ \hline \end{array} </strong> A)  B)   C)   D)  E)
D) <strong>Select a scatter plot of the given data.  \begin{array}{|c|c|c|c|c|c|c|} \hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\ \hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\ \hline \end{array} </strong> A)  B)   C)   D)  E)
E) <strong>Select a scatter plot of the given data.  \begin{array}{|c|c|c|c|c|c|c|} \hline r & 7 \% & 8 \% & 11 \% & 12 \% & 14 \% & 15 \% \\ \hline t & 16.24 & 14.27 & 10.53 & 9.69 & 8.38 & 7.86 \\ \hline \end{array} </strong> A)  B)   C)   D)  E)
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9
The populations P (in thousands) of Pittsburgh, Pennsylvania from 2000 through 2007 can be modeled by P=26321+0.083e0.0500tP = \frac { 2632 } { 1 + 0.083 e ^ { 0.0500 t } } where t represents the year, with t=0t = 0 corresponding to 2000.Use the model to find the numbers of cell sites in the year 2009.

A)2,326,853.00
B)2,327,853.00
C)2,329,853.00
D)2,328,853.00
E)2,330,853.00
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10
An initial investment of $5000 doubles in value in 6.3 years.Assuming continuous compounding, what was the interest rate? Round to the nearest tenth of a percent.

A)11.0%
B)4.8%
C)5.5%
D)6.3%
E)100%
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11
Select the correct graph for the given function y=ln(x+2)y = \ln ( x + 2 )

A) <strong>Select the correct graph for the given function   y = \ln ( x + 2 )  </strong> A)  B)   C)  D)   E)
B)  <strong>Select the correct graph for the given function   y = \ln ( x + 2 )  </strong> A)  B)   C)  D)   E)
C) <strong>Select the correct graph for the given function   y = \ln ( x + 2 )  </strong> A)  B)   C)  D)   E)
D)  <strong>Select the correct graph for the given function   y = \ln ( x + 2 )  </strong> A)  B)   C)  D)   E)
E)  <strong>Select the correct graph for the given function   y = \ln ( x + 2 )  </strong> A)  B)   C)  D)   E)
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12
The population P of a bacteria culture is modeled by P=4100ektP = 4100 e ^ { k t } , where t is the time in hours.If the population of the culture was 5800 after 40 hours, how long does it take for the population to double? Round to the nearest tenth of an hour.

A)54.8 hours
B)8.9 hours
C)79.9 hours
D)81.7 hours
E)56.6 hours
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13
The population P (in thousands) of Reno, Nevada from 2000 through 2007 can be modeled by P=346.8ektP = 346.8 e ^ { k t } where t represents the year, with t=0t = 0 corresponding to 2000.In 2005, the population of Reno was about 395,000.According to the model, during what year will the population reach 486,000.00?

A)2013
B)2005
C)2021
D)2017
E)2009
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14
An initial investment of $4000 grows at an annual interest rate of 5% compounded continuously.How long will it take to double the investment?

A)1 year
B)14.40 years
C)13.86 years
D)14.86 years
E)13.40 years
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15
If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by A=1+0.075t or A=e0.07tA = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t } depending on whether the account pays simple interest at 712%7 \frac { 1 } { 2 } \% or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?

A)  <strong>If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by  A = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t }  depending on whether the account pays simple interest at  7 \frac { 1 } { 2 } \%  or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?  </strong> A)    B)    C)    D)   E)
B)  <strong>If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by  A = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t }  depending on whether the account pays simple interest at  7 \frac { 1 } { 2 } \%  or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?  </strong> A)    B)    C)    D)   E)
C)  <strong>If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by  A = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t }  depending on whether the account pays simple interest at  7 \frac { 1 } { 2 } \%  or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?  </strong> A)    B)    C)    D)   E)
D)  <strong>If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by  A = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t }  depending on whether the account pays simple interest at  7 \frac { 1 } { 2 } \%  or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?  </strong> A)    B)    C)    D)   E)
E)  <strong>If $1 is invested in an account over a 10-year period, the amount in the account, where t represents the time in years, is given by  A = 1 + 0.075 \| t \mid \| \text { or } A = e ^ { 0.07 t }  depending on whether the account pays simple interest at  7 \frac { 1 } { 2 } \%  or continuous compound interest at 7%.Graph each function on the same set of axes.Which grows at a higher rate?  </strong> A)    B)    C)    D)   E)
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16
Select the correct graph for the given function y=4ex/2y = 4 e ^ { x / 2 }

A)  <strong>Select the correct graph for the given function   y = 4 e ^ { x / 2 }  </strong> A)   B)   C)   D)   E)
B)  <strong>Select the correct graph for the given function   y = 4 e ^ { x / 2 }  </strong> A)   B)   C)   D)   E)
C)  <strong>Select the correct graph for the given function   y = 4 e ^ { x / 2 }  </strong> A)   B)   C)   D)   E)
D)  <strong>Select the correct graph for the given function   y = 4 e ^ { x / 2 }  </strong> A)   B)   C)   D)   E)
E)  <strong>Select the correct graph for the given function   y = 4 e ^ { x / 2 }  </strong> A)   B)   C)   D)   E)
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17
Select the correct graph for the given function
y=5+log(x+2)y = 5 + \log ( x + 2 )

A) <strong>Select the correct graph for the given function  y = 5 + \log ( x + 2 )  </strong> A)  B)   C)   D)  E)
B)  <strong>Select the correct graph for the given function  y = 5 + \log ( x + 2 )  </strong> A)  B)   C)   D)  E)
C)  <strong>Select the correct graph for the given function  y = 5 + \log ( x + 2 )  </strong> A)  B)   C)   D)  E)
D) <strong>Select the correct graph for the given function  y = 5 + \log ( x + 2 )  </strong> A)  B)   C)   D)  E)
E)  <strong>Select the correct graph for the given function  y = 5 + \log ( x + 2 )  </strong> A)  B)   C)   D)  E)
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18
Find the exponential model y=ae0.5756xy = a e ^ { 0.5756 x } that fits the points shown in the graph.  <strong>Find the exponential model  y = a e ^ { 0.5756 x }  that fits the points shown in the graph.    </strong> A)  y = \frac { 1 } { 2 } e ^ { - 0.5756 x }  B)  y = - \frac { 1 } { 2 } x e ^ { - 0.5756 }  C)  y = \frac { 1 } { 2 } x e ^ { 0.5756 }  D)  y = \frac { 1 } { 2 } e ^ { 0.5756 x }  E)  y = - \frac { 1 } { 2 } e ^ { - 0.5756 x }

A) y=12e0.5756xy = \frac { 1 } { 2 } e ^ { - 0.5756 x }
B) y=12xe0.5756y = - \frac { 1 } { 2 } x e ^ { - 0.5756 }
C) y=12xe0.5756y = \frac { 1 } { 2 } x e ^ { 0.5756 }
D) y=12e0.5756xy = \frac { 1 } { 2 } e ^ { 0.5756 x }
E) y=12e0.5756xy = - \frac { 1 } { 2 } e ^ { - 0.5756 x }
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19
The population P of a culture of bacteria is described by the equation P=1300e0.052tP = 1300 e ^ { 0.052 t } , where t is the time, in hours, relative to the time at which the population was 1300.What was the population at t=3t = 3 hours?

A) P(3)1419P ( 3 ) \approx 1419
B) P(3)1519P ( 3 ) \approx 1519
C) P(3)1319P ( 3 ) \approx 1319
D) P(3)1619P ( 3 ) \approx 1619
E) P(3)1719P ( 3 ) \approx 1719
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20
The number y of hits a new search-engine website receives each month can be modeled by y=4080ekty = 4080 e ^ { k t } where t represents the number of months the website has been operating.In the website's third month, there were 10,000 hits.Find the value of k, and use this value to predict the number of hits the website will receive after 22 months.

A) k=0.2988k = 0.2988 ; About 184,894,691,979 hits
B) k=0.2988k = 0.2988 ; About 2,921,047 hits
C) k=0.2988k = 0.2988 ; About 22,832,533,585 hits
D) k=0.2988k = 0.2988 ; About 57,970,933 hits
E) k=0.2988k = 0.2988 ; About 1,150,488,266 hits
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21
Find the intensity I of an earthquake measuring R on the Richter scale ( let I0=1)\left( \text { let } I _ { 0 } = 1 \right) .
Southern Sumatra, Indonesia in 2007, R=8.25R = 8.25

A) 108.25177,822,94110 ^ { 8.25 } \approx 177,822,941
B) 108.25177,827,94110 ^ { 8.25 } \approx 177,827,941
C) 108.25177,825,94110 ^ { 8.25 } \approx 177,825,941
D) 108.25177,832,94110 ^ { 8.25 } \approx 177,832,941
E) 108.25177,829,94110 ^ { 8.25 } \approx 177,829,941
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22
Find the magnitude R of an earthquake of intensity I( let I0=1 ) I \left( \text { let } I _ { 0 } = 1 \right. \text { ) } . I=16000I = 16000

A)3.20
B)5.20
C)4.20
D)2.20
E)6.20
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23
Determine whether the given x-value is a solution (or an approximate solution) of the equation. 43x10=16x=4\begin{array} { l } 4 ^ { 3 x - 10 } = 16 \\x = 4\end{array}
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24
Tritium, a radioactive isotope of hydrogen, has a half-life of 12.4 years.Of an initial sample of 33 grams, how much will remain after 69 years? ​

A)0 grams
B)29.1351 grams
C)10.9074 grams
D)8.2500 grams
E)0.6973 grams
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25
Solve for x. 6x=366 ^ { x } = 36

A)8
B)2
C)-2
D)-6
E)6
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26
The chemical acidity of a solution is measured in units of pH: pH=log[H+]\mathrm { pH } = - \log \left[ \mathrm { H } ^ { + } \right] , where [H+]\left[ \mathrm { H } ^ { + } \right] is the hydrogen ion concentration in the solution.What is [H+]\left[ \mathrm { H } ^ { + } \right] if the pH=3.8\mathrm { pH } = 3.8

A)3.800
B) 6.31×1046.31 \times 10 ^ { - 4 }
C) 6.31×1036.31 \times 10 ^ { - 3 }
D) 1.58×1031.58 \times 10 ^ { - 3 }
E) 1.58×1041.58 \times 10 ^ { - 4 }
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27
An initial investment of $2000 grows at an annual interest rate of 4% compounded continuously.How long will it take to double the investment?

A)17.33 years
B)18.33 years
C)18.00 years
D)17.00 years
E)1 year
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28
A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones.The numbers of cell sites from 1985 through 2008 can be modeled by y=237,1011+1950e0.355ty = \frac { 237,101 } { 1 + 1950 e ^ { - 0.355 t } } where t represents the year, with t=5t = 5 corresponding to 1985.Use the model to find the numbers of cell sites in the year 2007 .

A)211,071
B)209,071
C)208,071
D)207,071
E)210,071
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29
Carbon dating presumes that, as long as a plant or animal is alive, the proportion of its carbon that is 14C is constant.The amount of 14C in an object made from harvested plants, like paper, will decline exponentially according to the equation A=A0e0.0001213tA = A _ { 0 } e ^ { - 0.0001213 t } , where A represents the amount of 14C in the object, Ao represents the amount of 14C in living organisms, and t is the time in years since the plant was harvested.If an archeological artifact has 30% as much 14C as a living organism, how old would you predict it to be? Round to the nearest year.

A)28,040 years
B)5715 years
C)9926 years
D)14,758 years
E)100 years
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30
Determine whether the given x-value is a solution (or an approximate solution) of the equation. 45x5=256x=2\begin{array} { l } 4 ^ { 5 x - 5 } = 256 \\x = 2\end{array}
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31
The chemical acidity of a solution is measured in units of pH: pH=log[H+]\mathrm { pH } = - \log \left[ \mathrm { H } ^ { + } \right] , where [H+]\left[ \mathrm { H } ^ { + } \right] is the hydrogen ion concentration in the solution.What is [H+]\left[ \mathrm { H } ^ { + } \right] if the pH=6.8\mathrm { pH } = 6.8 ?

A) 1.58×1071.58 \times 10 ^ { - 7 }
B) 6.31×1076.31 \times 10 ^ { - 7 }
C) 6.31×1066.31 \times 10 ^ { - 6 }
D) 1.58×1061.58 \times 10 ^ { - 6 }
E)6.800
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32
The chemical acidity of a solution is measured in units of pH: pH=log[H+]\mathrm { pH } = - \log \left[ \mathrm { H } ^ { + } \right] , where [H+]\left[ \mathrm { H } ^ { + } \right] is the hydrogen ion concentration in the solution.If a sample of rain has a pH of 3.3, how many times higher is its [H+]\left[ \mathrm { H } ^ { + } \right] than pure water's, which has a pH of 7?

A) 5.0×1045.0 \times 10 ^ { 4 }
B) 2.0×1042.0 \times 10 ^ { 4 }
C) 2.0×1032.0 \times 10 ^ { 3 }
D) 5.0×1035.0 \times 10 ^ { 3 }
E)7
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33
Find the magnitude R of an earthquake of intensity I (let I0=1)\left. I \text { (let } I _ { 0 } = 1 \right) . I=270300000I = 270300000

A)7.43
B)6.43
C)8.43
D)10.43
E)9.43
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34
Solve for x.Approximate the result to three decimal places. ex=4e ^ { x } = 4

A) ln41.466\ln 4 \approx 1.466
B) ln41.476\ln 4 \approx 1.476
C) ln41.436\ln 4 \approx 1.436
D) ln41.386\ln 4 \approx 1.386
E) ln41.456\ln 4 \approx 1.456
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35
Solve for x. lnxln5=0\ln x - \ln 5 = 0

A) 15- \frac { 1 } { 5 }
B) 5- 5
C) 15\frac { 1 } { 5 }
D) 525 ^ { - 2 }
E)5
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36
Solve for x. (14)x=64\left( \frac { 1 } { 4 } \right) ^ { x } = 64

A)4
B) 3- 3
C)7
D)3
E) 4- 4
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37
Find the intensity I of an earthquake measuring R on the Richter scale  (let I0=1 ) \text { (let } I _ { 0 } = 1 \text { ) } .
Costa Rica in 2009, R=5.70R = 5.70

A) 105.70503,18710 ^ { 5.70 } \approx 503,187
B) 105.70501,18710 ^ { 5.70 } \approx 501,187
C) 105.70506,18710 ^ { 5.70 } \approx 506,187
D) 105.70496,18710 ^ { 5.70 } \approx 496,187
E) 105.70499,18710 ^ { 5.70 } \approx 499,187
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38
The population P of a culture of bacteria is described by the equation The population P of a culture of bacteria is described by the equation   , where t is the time, in hours, relative to the time at which the population was 1600. (a) What was the population at   hours? Show your work. (b) After how many hours will the population reach 10000.00? Round to the nearest tenth of an hour.Show your work. , where t is the time, in hours, relative to the time at which the population was 1600.
(a) What was the population at The population P of a culture of bacteria is described by the equation   , where t is the time, in hours, relative to the time at which the population was 1600. (a) What was the population at   hours? Show your work. (b) After how many hours will the population reach 10000.00? Round to the nearest tenth of an hour.Show your work. hours? Show your work.
(b) After how many hours will the population reach 10000.00? Round to the nearest tenth of an hour.Show your work.
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39
A population growing at an annual rate r will triple in a time t given by the formula t=ln3rt = \frac { \ln 3 } { r } .If the growth rate remains constant and equals 9% per year, how long will it take the population of the town to triple?

A)2.2 years
B)5.3 years
C)6.6 years
D)1 years
E)12.2 years
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40
The chemical acidity of a solution is measured in units of pH: pH=log[H+]\mathrm { pH } = - \log \left[ \mathrm { H } ^ { + } \right] , where [H+]\left[ \mathrm { H } ^ { + } \right] is the hydrogen ion concentration in the solution.If a sample of rain has a pH of 3.4, how many times higher is its [H+]\left[ \mathrm { H } ^ { + } \right] than pure water's, which has a pH of 7?

A) 4.0×1034.0 \times 10 ^ { 3 }
B) 2.5×1042.5 \times 10 ^ { 4 }
C)7
D) 2.5×1032.5 \times 10 ^ { 3 }
E) 4.0×1044.0 \times 10 ^ { 4 }
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41
Solve the exponential equation algebraically.Approximate the result to three decimal places. 3ex=153 e ^ { x } = 15

A) ln51.609\ln 5 \approx - 1.609
B) ln51.099\ln 5 \approx 1.099
C) ln51.099\ln 5 \approx - 1.099
D) ln51.609\ln 5 \approx 1.609
E) ln52.708\ln 5 \approx 2.708
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42
Solve the exponential equation algebraically.Approximate the result to three decimal places. 2(52x)=122 \left( 5 ^ { 2 - x } \right) = 12

A) 2ln6ln53.8872 - \frac { \ln 6 } { \ln 5 } \approx 3.887
B) 2ln6ln51.8872 - \frac { \ln 6 } { \ln 5 } \approx 1.887
C) 2ln6ln50.8872 - \frac { \ln 6 } { \ln 5 } \approx 0.887
D) 2ln6ln54.8872 - \frac { \ln 6 } { \ln 5 } \approx 4.887
E) 2ln6ln52.8872 - \frac { \ln 6 } { \ln 5 } \approx 2.887
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43
Solve for x. logx=4\log x = - 4

A) 4- 4
B)0.0001
C) 0.0001- 0.0001
D) 44
E)1.386
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44
Solve the exponential equation algebraically.Approximate the result to three decimal places. 4(5x5)=244 \left( 5 ^ { x - 5 } \right) = 24

A) 5+ln6ln57.1135 + \frac { \ln 6 } { \ln 5 } \approx 7.113
B) 5+ln6ln59.1135 + \frac { \ln 6 } { \ln 5 } \approx 9.113
C) 5+ln6ln56.1135 + \frac { \ln 6 } { \ln 5 } \approx 6.113
D) 5+ln6ln58.1135 + \frac { \ln 6 } { \ln 5 } \approx 8.113
E) 5+ln6ln510.1135 + \frac { \ln 6 } { \ln 5 } \approx 10.113
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45
Solve for x.Approximate the result to three decimal places. log7x=12\log _ { 7 } x = \frac { 1 } { 2 }

A) 72.828\sqrt { 7 } \approx 2.828
B) 7=2.646\sqrt { 7 } = 2.646
C) 72.646\sqrt { 7 } \approx - 2.646
D) 72.646\sqrt { 7 } \approx 2.646
E) 772.646\frac { \sqrt { 7 } } { 7 } \approx 2.646
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46
Solve the exponential equation algebraically.Approximate the result to three decimal places. 2x5=162 ^ { x - 5 } = 16

A)10
B)11
C)9
D)-9
E)12
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47
Solve the exponential equation algebraically.Approximate the result to three decimal places. ex=ex212e ^ { x } = e ^ { x ^ { 2 } - 12 }

A) 3,43 , - 4
B) 3,4- 3 , - 4
C) 3,43,4
D) 3,4- 3,4
E) 3,3- 3,3
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48
Solve the exponential equation algebraically.Approximate the result to three decimal places. 1000e4x=751000 e ^ { - 4 x } = 75

A) 14ln3402.648- \frac { 1 } { 4 } \ln \frac { 3 } { 40 } \approx 2.648
B) 14ln3401.352- \frac { 1 } { 4 } \ln \frac { 3 } { 40 } \approx - 1.352
C) 14ln3401.648- \frac { 1 } { 4 } \ln \frac { 3 } { 40 } \approx 1.648
D) 14ln3400.648- \frac { 1 } { 4 } \ln \frac { 3 } { 40 } \approx 0.648
E) 14ln3400.352- \frac { 1 } { 4 } \ln \frac { 3 } { 40 } \approx - 0.352
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49
Solve the exponential equation algebraically.Approximate the result to three decimal places.
e2x7ex8=0e ^ { 2 x } - 7 e ^ { x } - 8 = 0

A) ln83.079\ln 8 \approx 3.079
B) ln82.079\ln 8 \approx 2.079
C) ln84.079\ln 8 \approx 4.079
D) ln81.079\ln 8 \approx 1.079
E) ln80.079\ln 8 \approx 0.079
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50
Solve for x.Approximate the result to three decimal places. lnx=2\ln x = - 2

A) e27.389e ^ { - 2 } \approx 7.389
B) e20.368e ^ { - 2 } \approx 0.368
C) e22.718e ^ { - 2 } \approx 2.718
D) e20.135e ^ { - 2 } \approx 0.135
E) e21.000e ^ { - 2 } \approx 1.000
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51
Solve the exponential equation algebraically.Approximate the result to three decimal places. 65x=0.506 ^ { - 5 x } = 0.50

A) ln(0.50)5ln60.072- \frac { \ln ( 0.50 ) } { 5 \ln 6 } \approx 0.072
B) ln(0.50)5ln60.517\frac { \ln ( 0.50 ) } { 5 \ln 6 } \approx 0.517
C) ln(0.50)5ln60.387- \frac { \ln ( 0.50 ) } { 5 \ln 6 } \approx 0.387
D) ln(0.50)5ln60.077- \frac { \ln ( 0.50 ) } { 5 \ln 6 } \approx 0.077
E) ln(0.50)5ln60.077- \frac { \ln ( 0.50 ) } { 5 \ln 6 } \approx - 0.077
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52
Solve the exponential equation algebraically.Approximate the result to three decimal places. e4x2=e3x214xe ^ { - 4 x ^ { 2 } } = e ^ { 3 x ^ { 2 } - 14 x }

A) 4,24,2
B) 3,23,2
C) 4,2- 4,2
D) 0,20,2
E) 0,20 , - 2
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53
Solve the exponential equation algebraically.Approximate the result to three decimal places. 6x+8=576 ^ { x } + 8 = 57

A) ln49ln62.172\frac { \ln 49 } { \ln 6 } \approx 2.172
B) ln49ln60.460\frac { \ln 49 } { \ln 6 } \approx - 0.460
C) ln49ln60.514\frac { \ln 49 } { \ln 6 } \approx 0.514
D) ln49ln60.460\frac { \ln 49 } { \ln 6 } \approx 0.460
E) ln49ln62.172\frac { \ln 49 } { \ln 6 } \approx - 2.172
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54
Solve the exponential equation algebraically.Approximate the result to three decimal places. ex6=13e ^ { x } - 6 = 13

A) ln192.565\ln 19 \approx - 2.565
B) ln192.944\ln 19 \approx 2.944
C) ln191.792\ln 19 \approx 1.792
D) ln192.565\ln 19 \approx 2.565
E) ln192.944\ln 19 \approx - 2.944
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55
Solve the exponential equation algebraically.Approximate the result to three decimal places.
22+4ex=13- 22 + 4 e ^ { x } = 13

A) ln3541.169\ln \frac { 35 } { 4 } \approx 1.169
B) ln3544.169\ln \frac { 35 } { 4 } \approx 4.169
C) ln3542.169\ln \frac { 35 } { 4 } \approx 2.169
D) ln3540.169\ln \frac { 35 } { 4 } \approx 0.169
E) ln3543.169\ln \frac { 35 } { 4 } \approx 3.169
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56
Solve the exponential equation algebraically.Approximate the result to three decimal places. 4ex=334 e ^ { x } = 33

A) ln3342.110\ln \frac { 33 } { 4 } \approx 2.110
B) ln3342.110\ln \frac { 33 } { 4 } \approx - 2.110
C) ln4332.110\ln \frac { 4 } { 33 } \approx 2.110
D) ln3343.497\ln \frac { 33 } { 4 } \approx 3.497
E) ln3340.114\ln \frac { 33 } { 4 } \approx 0.114
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57
Solve the exponential equation algebraically.Approximate the result to three decimal places. 2(3x)=362 \left( 3 ^ { x } \right) = 36

A) ln18ln30.380\frac { \ln 18 } { \ln 3 } \approx 0.380
B) ln18ln30.380\frac { \ln 18 } { \ln 3 } \approx - 0.380
C) ln18ln32.631\frac { \ln 18 } { \ln 3 } \approx - 2.631
D) ln3ln182.631\frac { \ln 3 } { \ln 18 } \approx 2.631
E) ln18ln32.631\frac { \ln 18 } { \ln 3 } \approx 2.631
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58
Solve the exponential equation algebraically.Approximate the result to three decimal places. 38x=24003 ^ { 8 x } = 2400

A) ln24008ln30.018\frac { \ln 2400 } { 8 \ln 3 } \approx 0.018
B) ln24008ln30.886\frac { \ln 2400 } { 8 \ln 3 } \approx 0.886
C) ln24008ln30.089\frac { \ln 2400 } { 8 \ln 3 } \approx 0.089
D) ln24008ln30.886\frac { \ln 2400 } { 8 \ln 3 } \approx - 0.886
E) ln24008ln31.248\frac { \ln 2400 } { 8 \ln 3 } \approx 1.248
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59
Solve the exponential equation algebraically.Approximate the result to three decimal places. e3x=75e ^ { 3 x } = 75

A) ln7530.439\frac { \ln 75 } { 3 } \approx 0.439
B) ln7532.439\frac { \ln 75 } { 3 } \approx 2.439
C) ln7530.561\frac { \ln 75 } { 3 } \approx - 0.561
D) ln7533.439\frac { \ln 75 } { 3 } \approx 3.439
E) ln7531.439\frac { \ln 75 } { 3 } \approx 1.439
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60
Solve the exponential equation algebraically.Approximate the result to three decimal places. ex=ex230e ^ { x } = e ^ { x ^ { 2 } - 30 }

A) 6,5- 6 , - 5
B) 1,301 , - 30
C) 6,56,5
D) 6,5- 6,5
E) 6,56 , - 5
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61
$3000 is invested in an account at interest rate r, compounded continuously.Find the time required for the amount to triple.(Approximate the result to two decimal places.) r=0.03r = 0.03

A)37.62 yr
B)36.62 yr
C)35.62 yr
D)34.62 yr
E)38.62 yr
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62
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. 8+71lnx=148 + 71 \ln x = 14

A) e6/73.356e ^ { 6 / 7 } \approx 3.356
B) e6/71.356e ^ { 6 / 7 } \approx 1.356
C) e6/74.356e ^ { 6 / 7 } \approx 4.356
D) e6/72.356e ^ { 6 / 7 } \approx 2.356
E) e6/70.356e ^ { 6 / 7 } \approx 0.356
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63
Solve (14)x=64\left( \frac { 1 } { 4 } \right) ^ { x } = 64 for x.

A)-3
B)-4
C)-1
D)1
E)no solution
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64
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. 6lnx=56 \ln x = 5

A) e5/60.301e ^ { 5 / 6 } \approx 0.301
B) e5/61.301e ^ { 5 / 6 } \approx 1.301
C) e5/63.301e ^ { 5 / 6 } \approx 3.301
D) e5/62.301e ^ { 5 / 6 } \approx 2.301
E) e5/64.301e ^ { 5 / 6 } \approx 4.301
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65
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. 2log3(0.5x)=52 \log _ { 3 } ( 0.5 x ) = 5

A) 2(35/2)33.1772 \left( 3 ^ { 5 / 2 } \right) \approx 33.177
B) 2(35/2)30.1772 \left( 3 ^ { 5 / 2 } \right) \approx 30.177
C) 2(35/2)31.1772 \left( 3 ^ { 5 / 2 } \right) \approx 31.177
D) 2(35/2)29.1772 \left( 3 ^ { 5 / 2 } \right) \approx 29.177
E) 2(35/2)32.1772 \left( 3 ^ { 5 / 2 } \right) \approx 32.177
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66
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. ln2x=3\ln 2 x = 3

A) e328.043\frac { e ^ { 3 } } { 2 } \approx 8.043
B) e3210.043\frac { e ^ { 3 } } { 2 } \approx 10.043
C) e3212.043\frac { e ^ { 3 } } { 2 } \approx 12.043
D) e3211.043\frac { e ^ { 3 } } { 2 } \approx 11.043
E) e3213.043\frac { e ^ { 3 } } { 2 } \approx 13.043
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67
Solve for x: 7(10x3)=237 \left( 10 ^ { x - 3 } \right) = 23 .Round to 3 decimal places.

A)0.517
B)no solution
C)3.517
D)-1.362
E)1.362
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68
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. logx=4\log x = 4

A)1,000
B)1,000,000
C)10,000
D)100,000
E)100
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69
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. lnx=5\ln x = - 5

A) e52.007e ^ { - 5 } \approx 2.007
B) e51.007e ^ { - 5 } \approx 1.007
C) e53.007e ^ { - 5 } \approx 3.007
D) e51.993e ^ { - 5 } \approx - 1.993
E) e50.007e ^ { - 5 } \approx 0.007
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70
Solve for x: 5x/3=0.00525 ^ { - x / 3 } = 0.0052 .Round to 3 decimal places.

A)-20.606
B)9.803
C)20.606
D)-3.268
E)15.777
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71
Determine whether or not x=37x = \frac { 3 } { 7 } is a solution to 33x3=813 ^ { 3 x - 3 } = 81 .
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72
$4500 is invested in an account at interest rate r, compounded continuously.Find the time required for the amount to triple.(Approximate the result to two decimal places.) r=0.0315r = 0.0315

A)21.00 yr
B)20.00 yr
C)34.88 yr
D)24.00 yr
E)23.00 yr
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73
Solve the equation algebraically.Round the result to three decimal places. 3+lnx8=0\frac { 3 + \ln x } { 8 } = 0

A) e32,980.958e ^ { - 3 } \approx 2,980.958
B) e30e ^ { - 3 } \approx 0
C) e354.598e ^ { - 3 } \approx 54.598
D) e30.050e ^ { - 3 } \approx 0.050
E) e320.086e ^ { - 3 } \approx 20.086
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74
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. log5(5x3)=log5(4x+4)\log _ { 5 } ( 5 x - 3 ) = \log _ { 5 } ( 4 x + 4 )

A)8
B)6
C)-1
D)7
E)9
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75
$2500 is invested in an account at interest rate r, compounded continuously.Find the time required for the amount to double.(Approximate the result to two decimal places.) r=0.06r = 0.06

A)13.55 yr
B)10.55 yr
C)12.55 yr
D)9.55 yr
E)11.55 yr
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76
$5500 is invested in an account at interest rate r, compounded continuously.Find the time required for the amount to double.(Approximate the result to two decimal places.) r=0.0540r = 0.0540

A)13.84 yr
B)10.84 yr
C)12.84 yr
D)11.84 yr
E)14.84 yr
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77
Solve the exponential equation algebraically.Approximate the result to three decimal places.
e2x7ex8=0e ^ { 2 x } - 7 e ^ { x } - 8 = 0

A) ln83.079\ln 8 \approx 3.079
B) ln81.079\ln 8 \approx 1.079
C) ln82.079\ln 8 \approx 2.079
D) ln80.079\ln 8 \approx 0.079
E) ln84.079\ln 8 \approx 4.079
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78
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. lnx8=7\ln \sqrt { x - 8 } = 7

A) e14+81,202,611.284e ^ { 14 } + 8 \approx 1,202,611.284
B) e14+81,202,614.284e ^ { 14 } + 8 \approx 1,202,614.284
C) e14+81,202,612.284e ^ { 14 } + 8 \approx 1,202,612.284
D) e14+81,202,610.284e ^ { 14 } + 8 \approx 1,202,610.284
E) e14+81,202,613.284e ^ { 14 } + 8 \approx 1,202,613.284
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79
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. 9+2lnx=49 + 2 \ln x = 4

A) e5/21.082e ^ { - 5 / 2 } \approx 1.082
B) e5/20.918e ^ { - 5 / 2 } \approx - 0.918
C) e5/21.918e ^ { - 5 / 2 } \approx - 1.918
D) e5/20.082e ^ { - 5 / 2 } \approx 0.082
E) e5/22.082e ^ { - 5 / 2 } \approx 2.082
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80
Solve the logarithmic equation algebraically.Approximate the result to three decimal places. lnx5=0\ln x - 5 = 0

A) e5151.413e ^ { 5 } \approx 151.413
B) e5146.413e ^ { 5 } \approx 146.413
C) e5148.413e ^ { 5 } \approx 148.413
D) e5149.413e ^ { 5 } \approx 149.413
E) e5150.413e ^ { 5 } \approx 150.413
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